Introduction to Partial Ordering

  Рет қаралды 193,993

Neso Academy

Neso Academy

2 жыл бұрын

Discrete Mathematics: Introduction to Partial Ordering
Topics discussed:
1) Need to study Partial Orderings.
2) The definition of Partial Ordering.
3) Meaning of Poset.
4) Partial Ordering examples.
5) Difference between comparable and incomparable elements.
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#DiscreteMathematicsByNeso #DiscreteMaths #PartialOrdering

Пікірлер: 71
@risimamathebula4035
@risimamathebula4035 8 ай бұрын
you don't understand how helpful this video was, cos my lecturer was literally making no sense. THANK YOU!!!!!
@morbidreality4909
@morbidreality4909 2 жыл бұрын
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@MrNb-xu7jl
@MrNb-xu7jl Жыл бұрын
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@vikrambabariya5166
@vikrambabariya5166 2 жыл бұрын
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@philipedekobi297
@philipedekobi297 2 жыл бұрын
Explained my lecturer's last 4 classes in 15.5 mins😭😂
@nilaypatil4721
@nilaypatil4721 Жыл бұрын
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@srinivasviswanadhapalli8093
@srinivasviswanadhapalli8093 Жыл бұрын
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@priyaparmar1886
@priyaparmar1886 Жыл бұрын
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@tarupathak
@tarupathak 6 ай бұрын
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@samarthtandale9121
@samarthtandale9121 7 ай бұрын
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@DemonSlayer-bv3nm
@DemonSlayer-bv3nm 7 ай бұрын
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@tinnyw2
@tinnyw2 2 ай бұрын
This is a great video, I was really struggling with understanding this concept.
@user-vm3oj9pm1f
@user-vm3oj9pm1f 16 күн бұрын
superb explanation... wish you could teach all my msc topics...am ur fan❤
@thesaniyaatar1142
@thesaniyaatar1142 Жыл бұрын
Given a set X={2, 3, 4, 5, 6, 7, 8} then divides is a partially ordered relation on X draw the Hasse diagram of POSET where | means divides.
@starrynight3526
@starrynight3526 2 жыл бұрын
Amazing and make more such helpful videos👍👍👍👍
@chusrangagasirmarak4247
@chusrangagasirmarak4247 2 жыл бұрын
I dont understand it ,why do you use a,b instead of using some numbers given in the set S in example 1 and 2 aswell. It would be easier for viewers if use explain using those numbers
@_randomstation
@_randomstation 8 ай бұрын
Agree
@thesigma3779
@thesigma3779 2 жыл бұрын
Best explaination till now on any channel , best channel !😇❤
@17Hieng
@17Hieng Жыл бұрын
Very clear explaination
@RashidSiddiqui
@RashidSiddiqui Жыл бұрын
nice, thanks. Good explanation.
@_Anna_Nass_
@_Anna_Nass_ 2 ай бұрын
Thank you, Neso 🎉
@ramankumar41
@ramankumar41 5 ай бұрын
Nice explanation !!!
@AbhishekThakur-fk7px
@AbhishekThakur-fk7px Жыл бұрын
Thank you so much sir.
@user-rf4te3nx3q
@user-rf4te3nx3q Жыл бұрын
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@betelihemwereta2268
@betelihemwereta2268 2 жыл бұрын
Thank You!
@pranavnyavanandi9710
@pranavnyavanandi9710 2 жыл бұрын
Hello @Neso_Academy. I have a doubt. Here's how you defined the meaning of "partial" in Partial-Ordered-Set: The word "partial" in "partial ordering" indicates that not every pair of element in a set is comparable. And comparable means that, the pair of elements are related by the partial ordering relation, that is, "a R b" or "b R a". But then, by this definition every other type of relation, say, an equivalence relation, would also be partial. I am not saying it would be a partially ordered relation but it would be a partial equivalence relation. Why? Because, in an equivalence relation also, not every pair of elements in the set upon which the relation is defined on, are comparable. If this is the case, then partial is not a special property of a poset only but that of every relation since it does not always relate all the elements of a set. Further, every relation does the ordering of elements of a set based on some condition or rule, so what's so special or different about partial ordering? The way I see it, every relation is partial ordering of the elements of a set. Hope I have understood it right. If not, kindly clarify.
@santerisatama5409
@santerisatama5409 Жыл бұрын
Partial ordering is defined as 1)Reflexive, 2)Antisymmetric and 3)Transitive. Equivalence relation is symmetric, and thus not partial according to the definition. The term "partial" is used to distinguish from 'totally ordered set', where every pair is comparable, extending the definition with 4) a ≤ b or b ≤ a (strongly connected, formerly called total) to the definition. According to wiki, the informal, intuitive meaning of poset is that "Two elements x and y may stand in any of four mutually exclusive relationships to each other: either x < y, or x = y, or x > y, or x and y are incomparable." Your doubt might originate from this: on a deeper intuitive level, the simplest and most natural definition/derivation or equivalence relation comes from negation of relational operators: if A is neither more nor less than B, then A = B (in a given suitably comparable context). Note that interval from 2 to 4 is both more and less than 3 in the standard ordering of integers. Conditioning by Classical Aristotelean logic (which more or less bans "both-and" and "neither nor") has strong tendency to hide deeply intuitive relations like 'both more and less' and 'neither more nor less' from thinking. Working with intuitive and paraconsistent logics is highly recommended. :)
@kuppi._-94
@kuppi._-94 Жыл бұрын
Thank you very much
@uzefaswati5637
@uzefaswati5637 2 жыл бұрын
Thank you sir
@AdityaKumar-mc1vo
@AdityaKumar-mc1vo 2 жыл бұрын
Just wow😌
@lavanjv4414
@lavanjv4414 Жыл бұрын
Awesome teaching ,just amazing.
@JaiBothra
@JaiBothra Жыл бұрын
you look like a cookie if it were a human
@venkatarohitpotnuru38
@venkatarohitpotnuru38 Жыл бұрын
thanks man:)
@maryamalizadeh1498
@maryamalizadeh1498 10 ай бұрын
Thank yooou!
@Abid-qp2jm
@Abid-qp2jm 9 ай бұрын
thank u bhai
@danaizadpanah1257
@danaizadpanah1257 Жыл бұрын
True hero
@amarnath1828
@amarnath1828 Жыл бұрын
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@yashmalve8804
@yashmalve8804 6 ай бұрын
Please enable the caption or subtitles in your videos
@devmallik7749
@devmallik7749 2 жыл бұрын
Can you give example for better understanding like in this video you gave in 11:35 min.
@RKARAN-zs5zn
@RKARAN-zs5zn 2 жыл бұрын
(1,1)(2,2)(3,3)(4,4)(6,6)
@davekenjoplojr.266
@davekenjoplojr.266 Жыл бұрын
What is a poset? Isn't that what we usually have in our sinks where we could turn the water on and off?
@Maluda_Tech
@Maluda_Tech 7 ай бұрын
Tf 😭😭😭😂😂
@Memes-ry7tp
@Memes-ry7tp Ай бұрын
what is "a" and "b" i am confused
@MATHEMATICALSCIENCE-__________
@MATHEMATICALSCIENCE-__________ 2 ай бұрын
Let A = {1, 2,3, 4} and let R be a relation on A defined by R {(1,1), (1, 2), (2, 4), ,2), (4,3)}. Find the smallest transitive relation R* on A containing . Give explanation of this Question. PLEASE....
@manvigupta1938
@manvigupta1938 2 ай бұрын
use warshall method to solve this by matrices
@nethajis1384
@nethajis1384 7 ай бұрын
Can any one answer. How many partial order relations are possible on set of n elements?
@_Anna_Nass_
@_Anna_Nass_ 2 ай бұрын
I don’t know but good question, I’m commenting here in case someone answers it.
@shaikchanmehboob7958
@shaikchanmehboob7958 2 жыл бұрын
1st viewer😊
@monicabattacharya6416
@monicabattacharya6416 2 жыл бұрын
please complete discrete mathematics and datastructures
@uday2159
@uday2159 Жыл бұрын
Had u complete ur undergraduation?
@ahmetkarakartal9563
@ahmetkarakartal9563 2 жыл бұрын
I dont understand the result in 11:23 2 divides 1 but the result is not be integer. But in the question I dont see any restriction for this
@collegematerial5348
@collegematerial5348 2 жыл бұрын
please tell i also not understand this relation is not antisymmetric because 1 divide 2 ,2 divide 1 but 1 is not equal to 2 so how is possible to be partial order
@nava3548
@nava3548 2 жыл бұрын
@@collegematerial5348 also stuck on that 😑
@AbdullahKhan-pv1qz
@AbdullahKhan-pv1qz 2 жыл бұрын
2/1=2 but 1/2 is not equal to integer.
@fezphilip7024
@fezphilip7024 2 жыл бұрын
It's in the definition of "divides". The quotient has to be an Integer. That is, the remainder has to be zero. Otherwise every Integer can of course divide every other Integer.
@techanshul
@techanshul 2 жыл бұрын
Wow
@leetchoy
@leetchoy 5 ай бұрын
cool
@shambo9807
@shambo9807 7 ай бұрын
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@appayyagariaswini2060
@appayyagariaswini2060 2 жыл бұрын
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@collegematerial5348
@collegematerial5348 2 жыл бұрын
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@devangprabhune3591
@devangprabhune3591 2 жыл бұрын
u from which university?
@collegematerial5348
@collegematerial5348 2 жыл бұрын
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@rajeshprajapati4863
@rajeshprajapati4863 Жыл бұрын
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@swatiswagatikamuduli9279 Жыл бұрын
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@rajeshprajapati4863 Жыл бұрын
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@omkarjadhav9008
@omkarjadhav9008 7 ай бұрын
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@gaurav561crazy5
@gaurav561crazy5 2 жыл бұрын
Hm
@omnigod5760
@omnigod5760 2 жыл бұрын
gehu gang
@omkarjadhav9008
@omkarjadhav9008 7 ай бұрын
5:17 they are not antisymmetric They are Asymmetric.
@madhura9816
@madhura9816 11 ай бұрын
Thank you sir
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