Inverse Laplace examples | Laplace transform | Differential Equations | Khan Academy

[@blaineconnell6377]

shoutout to this man for helping engineering majors for over 12 years

[@iBredgen]

I just wanan let you know how much I appreciate all your DE videos. I've been watching since Laplace transforms and you made stuff simple in 25 minutes where my Prof made it horribly complicated in 50. Thanks for clearing all this up for me, I think I actually have a chance to do well on my exam now. Now, time to get back to your videos. I'll probably reach vid #45 soon enough. THanks again

[@hulk8889]

You are right dear iBredgen

[@austinmolnar1155]

You saved me the night before the test, thanks a lot!!!

[@ScotchVX]

Why would anyone dislike this video? Was it hard for them to understand? Did they not like his approach/method? To me, it was very simple to follow and thus I learned something.

[@itsFarawaySkies]

Those are two great reasons to dislike the video, thanks for sharing.

[@ndrsg3013]

because it kinda becomes messy from 9 minutes = all over the place

[@PrinceFX]

i'm still amazed at how easy this stuff is! If Sal taught me this stuff even in high school, I would def get it!

[@hulk8889]

You are right PrinceFx!

[@huehue5286]

When I win a nobel in the future I'll include khan academy in my thanks

[@535_anshuj9]

When will you win?? Just curious.

[@satirthapaulshyam7769]

Did u got it man?

[@rikthecuber]

Include me too! :D

[@maxwellsequation4887]

Are ya winnin son?

[@niggasinkanpur]

Are you winnin son?

[@pialrezwan4823]

thanks khan!! you just saved the day , 6 min of the clip explained so much that i could started solving problems

[@lateralus713]

thank you so much man, this topic was starting to annoy me but now i figured it out thanks to your help

[@hasnainiqbal4870]

this guy.... I've no words!!!!!!!! Hats off man

[@pranshugulati4947]

You're the reason I'm not working at Mcdonalds right not

[@MsAsim123456]

Well clearly you should if you can't spell "now".

[@MsAsim123456]

ahaha, i am just kidding.

[@shardulbirje6379]

@@MsAsim123456 😂😂😂

[@chopperr3ad]

Wish you were my lecturer, makes so much more sense this way. thanks.

[@ApplianceRepairOfTucson]

Man, you are the best on youtube !!!!!! thanks a lot !!!

[@ammess2033]

Somehow when Sal says it, it sticks. Hopefully we have youtube. The only place where half a million student can sit and world class watch a lecture. FOR FREE.

[@evanwitthun3523]

Passed a quiz thanks to this video!!!!

[@kylejermstad]

You my friend are a gentleman and a scholar. Kind of a mathematical gangster. The offspring of a Jedi knight and a wizard.

[@mushtaqhussainmir803]

Man , u made it so easy for me ..

[@kylejermstad]

You my friend are a gentleman and a scholar. Kind of a mathematical gangster

[@turbowil1904]

You guys are absolutely killing it. So useful! Thank you.

[@sirghty]

write equations tidy and in order

[@Dogukan737]

Infinitely helpful. Completely forgot all the Laplace transformations!

[@faridsuhaimi692]

Tq Dr. Nasir

[@THELEGENDVHIBEZ]

so useful to watch your videos. it is really helping me develop in my mathematics classes. God bless you sir

[@albertlam1873]

Thank you Sal. I love you.

[@wintersolstice3573]

Thanks a lot for uploading these Laplace and Inverse Laplace videos. These really helped me understand the topic :)

[@胡有蝉]

the capital F makes it super confusing, try G,H to replace would be extremely helpful

[@iffatiffat6620]

Nice work Sir👍

[@riazislam9598]

uh saved my time

[@Sam-dc9bg]

Thank you for the lesson one again.

[@dwarduk2]

If I understand it right, your U(t) is a step function which becomes 1 at t=0; his u_c(t) becomes 1 at t=c, so both those expressions are equivalent.

[@yash1152]

> _"if i understand it right, your U(t) ..."_ thats one of many reasons why i always quote with respect to what i am replying

[@adituv8565]

@@yash1152 Bro, that comment was from over 10 years ago. The comment system has changed multiple times since and the old reply chain stuff is all gone.

[@yash1152]

> _"The comment system has changed multiple times since and the old reply chain stuff is all gone."_ @@adituv8565 i know, i said to hard quote the comment to which a person is replying to in his/her own comment like i do.

[@BananaPistol412]

Jesus. I’m a third year EE. You have just made the light bulb turn on. Thanks so much!

[@BananaPistol412]

Relax, Signals and Systems Class my dude

[@yash1152]

2:23 Summary of Laplace Transform properties we have looked so far

[@عبدالرحمنحسين-ج7ض]

thank you very much

[@bhthierry4430]

OMG this video created in 2k9 and am watchin it in 2021 lol..

[@eaymw]

your amazing!

[@happyhedgehog6450]

Great video.

[@AdityaSharma-mx3in]

great video sir .....

[@fiih9731]

thank you very much of this wonderful example and explanation

[@fukidngan]

you are really great!!!!!!

[@johnbuckner3701]

@ 3:33, should't the sin function = a/s^2 PLUS a^2 ? I think the solution written is for the sinh function. I'm taking Differentials right now, so I noticed this. Thanks Khan!!!

[@nosafetyswitch9378]

John Buckner it's a + but it's not clear enough,he also said "plus" while speaking.

[@GaMeRHAK7]

very helpful ,, thanx o lot 4 ur work :D

[@rend_neu]

You are really Awesome, thanks a lot for your help. Also, it would be so kind of you if you can pls tell me what software do you use for making videos? I really liked it.

[@8dots]

My textbook says this: L{U(t-a)f(t-a)} = e^(-at)F(s). In other words, it says U(t-a) and not U(t). Which is right?

[@carultch]

u(t) is the unit step function, with its jump discontinuity at t=zero. u(t - a) is the unit step function, shifted a units to the right, in the time domain. L{u(t)} = 1/s L{u(t - a)*f(t - a)} = e^(-a*t)*F(s), where L{f(t)} = F(s). Both formulas are correct. One is just the original form, and the other is time-shifted, and generalized to apply to other functions as well, rather than just the individual unit step function.

[@quadrinhosmonica2735]

Should have defined the inverse laplace transform at the beginning

[@samirhossain6951]

excellent

[@reeb3687]

Why is the laplace transform of t to the n the reciprocal of the integral power rule?

[@josecortes2533]

try to solve this inverse laplace transform: (s+1)/s(s^2+s+1)

[@silverleafmoonplate]

Jose Cortes Breaking it into Partial Fractions and then Inverse Laplace will give you f(t) = 1 - (cos(√3/2 t )* e^(-t/2)) + (1/√3*sin(√3/2 t) * e^ (-t/2) )

[@carultch]

Given: (s + 1)/(s*(s^2 + s + 1)) Complete the square on the irreversible quadratic: s^2 + s + 1 = (s + 1/2)^2 + 3/4 Set up partial fractions: A/s + (B*(s + 1/2) + C)/((s + 1/2)^2 + 3/4) Heaviside coverup at s=0 finds A: A = (0 + 1)/(covered*(0^2 + 0 + 1)) = 1 Result so far: (s + 1)/(s*((s + 1/2)^2 + 3/4)) = 1/s + (B*(s + 1/2) + C)/((s + 1/2)^2 + 3/4) Let s = -1/2, so the B disappears and we can find C: (-1/2 + 1)/(-1/2*((-1/2 + 1/2)^2 + 3/4)) = 1/(-1/2) + C/((-1/2 + 1/2)^2 + 3/4) -4/3 = -2 + 4/3*C C = 1/2 Let s = +1/2, so the coefficient on B becomes 1: (1/2 + 1)/(1/2*(1 + 3/4)) = 1/(1/2) + (B + 1/2)/(1 + 3/4) 12 = 14 + 4*B + 2 B = -1 Partial fraction result: 1/s + (-1*(s + 1/2) + 1/2)/((s + 1/2)^2 + 3/4) Modify the expression, so it resembles standard transforms: 1/s - (s + 1/2)/((s+1/2)^2 + 3/4) + 1/sqrt(3) * sqrt(3)/2/((s+1/2)^2 + 3/4) 1*L{1} - L{cos(sqrt(3)/2*t)*e^(-t/2)} + 1/sqrt(3) * L{sin(sqrt(3)/2*t)*e^(-t/2)} Inverse Laplace result: 1 - cos(t*sqrt(3)/2)*e^(-t/2) + sqrt(3)/3*sin(t*sqrt(3)/2)*e^(-t/2)

[@MrFKD]

you better if you write like that: F(s)=2.g(S).e^-2s

[@Syvmana]

I'm confused, what is this?

[@theamirali10sh]

is u subscript 2 (t) pretty much the same as u(t-2) please someone answer!!!!

[@salmanmujtabaautos4268]

Kaash ap musalman hotay to ap jannati hotay.

[@fernandorendon8914]

🐐🐐🐐

[@gerardsagliocca6292]

You seem to be prone to jump around a bit. Stay closer to your notes.

[@TheDankyshen]

What program does he use?

[@Pr0x1mo]

@Pickulus wtf LMFAOOOOO

[@badwolf69420]

I have to admit, this is the first time I got frustrated watching one of these videos because of how it was presented. Too much jumping around between the solution and the previous examples and substitutions, and it was hard to tell which was which in real time.

[@ndrsg3013]

Specially from 9 minutes... My ADHD got flipped

[@ArunNalluri]

Soo complicated to learn last day :/

[@sleepyhead7391]

@aligsaysai junk comment

[@bandr3598]

بلاس وبلاس مافهمت

[@jasonfortress9027]

#69 comment

[@josecortes2533]

you confuse me even more

[@germas369]

unlearn and learn

[@Muxik4k]

it is very unorganized, previous videos where way better

[@asif7240]

Thank you!

[@manyielkoth2221]

Thank you so much

[@germas369]

thank you very much. very clear explanation