Inverting and Non-inverting Amplifiers - Op-amps | Basic Circuits #13

[@Zzzzzzzzz678]

i only started to understand opamps when i started following this channel. nice work and thank you so much

[@CircuitBread]

Happy to help!

[@monfry2675]

Showing actual setup helped me a lot to accept the purpose of using op amp !

[@CircuitBread]

Awesome, glad it was helpful!

[@songoku6425]

the greatness of your videos is that they explain the purpose of the op amps not just math and configurations thank you sir greeting from so far from syria

[@justincoleman9776]

I always had trouble remembering which one (+ or -) was the inverting input. Then I started thinking of it as maths ideals. When you multiply something by a (-) number, it inverts the sign, therefore the (-) input is inverting.

[@thirsty1629]

Your derivation is the only explanation of why the output of the inverting amplifier is negative that I understand

[@ibzdude]

One important thing to note... is that if the feedback loop is connected to the non-inverting terminal, these equations will still give you the exact same values, but that will not be the actual result. Feedback loop MUST be connected to inverting terminal for these equations.

[@bengriffiths7221]

this man will singlehandedly be responsible for my degree

[@victormasiero5638]

How did you know the direction of the current in the R2 on the non- inverting example you gave?

[@BoCoBuffalo]

It seems to me like the math would resolve itself with the exact same result, even if you swapped the inverting/non-inverting inputs. Is there a reason why the inverting and non-inverting inputs are the way they are in these circuits?

[@Smarty_San]

Hello! It was a very good video with the demonstration to help understand the concept. I had a question though, from the first video of op-amp series I remember that Vout will try to be at A(amplification) times Vin right and that as soon as it gets lower than that it will get back to that value. But I noticed that in the practical example it overshooted that value as well. Why was it so?

[@CircuitBread]

Sometimes you get overshoot as, in the op-amp itself, there is a feedback loop. So, if you've looked at our control systems lessons, you'll see that there is a balance that must be made between responsiveness and the potential for overshoot. As the output is trying to "find" the correct value to control Vin properly, it can bounce around a bit. This is to be expected and, depending on the application, it may not be a big deal or you may need to make some modifications to either limit the bounce (usually slowing response time) or to account for the fact that your output will wiggle a bit before settling down.

[@thaisonvu2736]

How much current can the inverting amp source?

[@RayChris-t3p]

May I ask why you use 0 to 14 voltage as power supply? I think according to the datasheet, pin 4 should be connected to -14V in this case. I used LM301AN op-amp, and when I connect pin 4 to ground ( 0V ), it doesn't work. It shows that the output at pin 6 is higher than the voltage at pin 7.

[@CircuitBread]

In some of these tutorials I gave it the negative voltage, others I didn't. The op-amp should work either way BUT if you don't give it a negative supply, it won't be able to generate negative voltages, which means that some (many) circuits won't work correctly at times. It is always better to give it the +/- 14 volts (or whatever the datasheet says) but it is more complicated.

[@cesardelgadillo4139]

Which op-amp are you using? Can you provide a link?

[@CircuitBread]

I was using this part: LF412CN/NOPB-ND and got it from Digikey: www.digikey.com/short/v312qpp1 I'm not necessarily encouraging you to use this particular part or supplier but that is what I was using in these videos.

[@kaybhee6]

ur plus input is grounded,,,, what happens if plus input untouchrd,,, not connected... floating

[@MR2GR]

I may just be really dumb, but it seems like the inverting and normal op-amp both just use a voltage divider. The only difference i saw was connecting the input to the + or thr -, and which of those the voltage divider is applied to to adjust the output.

[@tnamen1307]

Please check the output when A DIODE l, rather than resistor, is added either at the invert or non invert pin. The outputs are very contradicting! Make videos please.

[@danielfrimpong6068]

Thanks so much for your useful video, they are very clear and not hard to understand. But I have a question I want ask you regarding my electrical work,how can I reach out to you sir?

[@CircuitBread]

Hi Daniel, I recommend checking out our Discord channel. I'm on there sometimes but there are several others that are even more responsive on there than I am. discord.gg/vdqARHb

[@Niceluck-b9b]

You are great, thank you very much for such a precious and kind explanation Dear, Since I don't have practical test devices like oscilloscope etc. Does the simulation program fulfill the purpose and give me semi-real results?

[@CircuitBread]

Yes, simulation programs give amazingly accurate results. There are a lot of options out there but LTSpice is free, powerful, and relatively easy to use (not the easiest but not too bad for a beginner), and it has the ability to give very accurate results if you take the time to setup the circuit with more realistic models.

[@Niceluck-b9b]

@@CircuitBread Thank you very much for your kind reply and advice

[@Dc_tech386]

As I see this guy don’t reply to us viewer comments

[@CircuitBread]

How can we help?

[@pukaseek]

WAY too much talking and explanation. The topic is covered well but all the info could have covered in a 5 minute video