Ion Concentration in Solutions From Molarity, Chemistry Practice Problems

This chemistry video tutorial explains how to calculate the ion concentration in solutions from molarity. This video contains plenty of examples and practice problems.
Stoichiometry Practice Test: • How To Solve Stoichiom...
Solute, Solvent, & Solution:
• Solute, Solvent, & Sol...
Strong & Weak Electrolytes:
• Identifying Strong Ele...
Molarity Practice Problems:
• Molarity Practice Prob...
Ion Concentration In Solutions:
• Ion Concentration in S...
Dilution Problems:
• Dilution Problems, Che...
___________________________________
Types of Chemical Reactions:
• Types of Chemical Reac...
Solubility Rules:
• Solubility Rules
Predicting The Products of Reactions:
• Predicting The Product...
Activity Series of Metals:
• Activity Series of Met...
Will This Reaction Occur?
• Chemistry - Will The R...
Predicting Products of SR Reactions:
• Predicting Products of...
___________________________________
Double Replacement Reactions:
• Introduction to Double...
Net Ionic Equations:
• Precipitation Reaction...
Writing Chemical Equations From Words:
• How To Write Chemical ...
Solution Stoichiometry:
• Solution Stoichiometry...
Molarity & Dilution Problems:
• Molarity Dilution Prob...
Acid Base Neutralization Reactions:
• Acid Base Neutralizati...
____________________________________
Acid Base Titration Problems:
• Acid Base Titration Pr...
Mixture Problems:
• Mixture Problems
Calculating Oxidation Numbers:
• How To Calculate Oxida...
Oxidation and Reduction Reactions:
• Oxidation and Reductio...
Balancing Redox Reactions:
• Half Reaction Method, ...
Ideal Gas Law Problems:
• Ideal Gas Law Practice...
___________________________________
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www.video-tutor.net/
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Thanks for this boss. You are a life saver. For example 4, it's easier if you look for the molar mass first then you look for the mass conc by dividing the gram by liter(obviously you convert if it's in ML) the 3rd step is to look for the molarity by dividing the result of your mass conc by the result of your molar mass(it has to be 284/142) you'll get 2 and you can multiply it by 2 then you'll get 4. Happy to help.

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[@georgesadler7830]

Professor Organic Chemistry Tutor, thank you for a powerful video /lecture on Ion Concentration in Solutions from Molarity in AP/General Chemistry. Some of the examples are easy to understand, however, harder problems are problematic from start to finish. Professor Organic Chemistry Tutor, thanks to the viewers for finding and correcting the error(s) in this video.

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i think there is an error in 5:10 shouldn't it be .2 litres not .25 litres

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At 1:48, you said that we need to divide 2mol by 1 mole. So as at 3:10, why you did not multiply it with 2 and divided with 3? Because this isn’t the ration of moles between 2al and 3SO4 ?

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Does ion concentration change when there is Ka involved?

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[@saifalsarker]

Excuse me! Concentration and molarity are two different terms. Concentration is the ratio of the mass of solute per liter solution and its unit is kg per meter cube. On the other hand, molarity is the ratio of the mole number of solute per liter solution and its unit is mole/Liter.

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in 7:13 why isnt the volume of 800 mL in L

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For the last question. If it was the entire equation I would have to calculate molarity for, would I include the water?

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For the last question why didn't we multiply the Na by 2 when we got 4M It is Na2 shouldn't we multiply it be 2 ? Na2= 4×2=8? Could you explain it to me please

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Bro 4M came bc we multiplied 2 by 2. The molarity of the solution in that case is 2 and in sodium sulphate , sodium has a subscript of 2 so we multiply the subscript by molarity (which equals to 2) and hence 2*2 equals 4

[@abdullah-al-mahir5441]

How can I find the Molarity of the compound NaNO3 when the molarity of Na+ ion is given? Is it just the reverse?

[@cyclonevii_0]

All you need to do is just multiply it by 1 mole of the compound by the amount of Na+ ions given. So : 1mol NaNO3 / 3 mol Na+. This will give you the molar concentration of the solute, or NaNO3.

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Don't you have to convert moles of na to ions of Na by dividing my avogadros number?

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does the M stand for moles or concentration

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Capital M stands for moles/liter (moles per liter)

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5:01 You should have taken 20 not 25

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