Aise Questions khatam karenge Physics ka darr 😱

[@NMSPhysicsISAC]

Subscribe for more such interesting and conceptual based physics problem ❤

[@soumyadeeppradhan]

Awesome 👍

[@keshavnagar1265]

Yeah sir Pls continue this series

[@aaravmehta1099]

Incredible Insight!!! Thanks alot sir. I came acros the last queston many months back and quit it because I thought it was too complicated.

[@AnamikaVerma-rs3en]

Nms sir op❤❤❤ and Rajat sir op ❤❤❤

[@NMSPhysicsISAC]

God bless you beta ❤

[@pepethe123]

I started the 1st que with the basic thought ki sabse nazdeek toh kya pta usi pe gir jaye for that the time of flight has to be equal to 1 sec I multiplied it with vcos theeta the horizontal component for any unknown value and it was equal to 1m as it will be isoceles right angled triangle(given 45 degree) and I made the equation for y axis and put the value of t to be equal to one for and got the value of vertical velocity v sin theeta equal to 4 Then simply we get by dividing that tan theeta equal to 4 or 76 degrees and value for velocity be root 17 metre/sec.

[@RishabhKumar-hp9oi]

very amazing thought process......

[@NMSPhysicsISAC]

Thank you! Cheers!

[@AbhishekMamodiya]

Sqrt((g(d^2+8h^2))/2h)

[@Nimit_oc]

Same 👍🏻

[@spgaming1922]

Please continue this series sir 🙏

[@Zoro-hn7vp]

u = (2gh(Cos^2 - sin^2)/cos^2sin^2 )1/2

[@boby7878]

Assume upar wali director+ve ha Eq1 Vcos∅ ×1sec = 1m Eq2 -1m=vsin∅×1sec -1/2g×1² Divie eq2by1 Tan∅=4 As simple as AYUSHi ma'am 👿

[@justfeel9767]

Nice thought

[@Zoro-hn7vp]

1st ko toh aise krlo ki 1 second me 1 m jayega niche -1 = u cos - 5 u cos = 4 aur x ki eqn usin = 1 tan = 4 hogya solve

[@adityajha2889]

Homework question ka answer:- √(2gd+2gh)

[@Dynamic.chemistry228]

Amazing❤❤❤ rajat sir and NMS sir❤

[@collectregularly]

U=(√2gH+2g√H^2+d^2) Is it correct...???

[@iitianiitian4593]

❤

[@NMSPhysicsISAC]

😊❤

[@satyamyt5363]

Sir please continue this series of 3 ques in 15 min ❤

[@mayank_teacher]

Rajat don ❤❤

[@VishalKumar-wh9yu]

Envalope of parabola

[@krishnamania1]

U=root(g×(2H+(d²/2H)) hai kya sir ?? Jaise apne sphere wala kiya vaise hi kiya ?

[@FranklinSaville]

Sir second last question ( jisme 2H ,H and D diya hai ) uska answer root (3gH +g×root H^2+D^2) hai ?

[@sayantansarkar4560]

Sir isme toh 2 variable tha bas u and angle, time bhi diya hua tha ki 1 second mein fat jayega, horizontal aur vertical distance diya hua hai 1 and 1, toh agar ek y ka displacement equation s=usin(theta)t+1/2at2 or x displacement s= ucos(theta) likhke sab data put karde toh 2 equation 2 variable solve ho jayega, kya ye approach sahi hai?

[@RajatKumarSir]

Han but jis jagah bomb 💣 explode kiya hoga us point k location pata kr li then usi point ki bunker se distance likhake ,minimise karna pdega …

[@user_2910wk]

Sir amber batch ka price reduce kr dijiye please 🥺

[@aritrasahaclass7roll15secb9]

sir last question me (circle wala) usme differentiation ke jagay AM-GM use kar sakte hai easily.

[@shivx3295]

kar akha hai yeh question

[@shubhamyadav7401]

Sir KZbin par padhana start krdo please sir😢😊

[@rmishra70]

Loss in mechanical energy is why work done by friction alone ? Mechanical energy is defined as sum of KE and PE , i am bit confused here can someone please guide me. Thanks

[@RajatKumarSir]

Block par WET lagaenge then us par friction ka work and gravitational force ka work from A to B aaega then usko likh skte hain Wf+Wg =Kb-Ka ie = -80 J (given) But Wf+Ua-Ub=Kb-Ka :-ie Wf= ME)b -ME)a =-35J( given)

[@RajatKumarSir]

Where Kb-Kinetic energy at B Ka-KE at A Ua-gravitational potential energy at A Ub=PE at B ME-Mechanical energy