J1 = 1 and J2 = 1/2 Clebsch Gordan coefficient- A

[@PrincePoswal2]

Love from Rajasthan sir, when u said beta

[@PrincePoswal2]

Hello sir how to make table??

[@dr.vipenpalsingh9279]

It's very simple. Start with. J1=1/2 J2=1/2 case. Then you will be able to create it for J1=1 J2=1/2

[@milroydissanayake886]

THE BOOK IS THEORY OF NUCLEAR STRUCTURE BY M K PAL APPENDIX A

[@meghasharma5239]

Well explained sir

[@AkashKumar_2000]

Very Helpful Sir!🙏

[@priyade6506]

wow awesome explanation sir.. thank you

[@dr.vipenpalsingh9279]

Welcome

[@tajis6227]

This is From Which book sir ji

[@dr.vipenpalsingh9279]

You may refer any book. No particular. Freelancer stuff.....

[@prabhudayalsharma6287]

Sir hm jab particle physics ka question bna rahe the toh usme isska kafi use ho raha tha bt mujhe kya smjh nhi aaya .... Wo qn aapko kaise vejun

[@dr.vipenpalsingh9279]

We can discuss in detail.

[@dr.vipenpalsingh9279]

Send me your question at [e-mail]

[@prabhudayalsharma6287]

@@dr.vipenpalsingh9279 vej diye hn sir ..Error aa raha tha

[@prabhudayalsharma6287]

Many many thanks sir

[@dr.vipenpalsingh9279]

@@prabhudayalsharma6287 which error

[@fbstore9972]

Sir A= 1/v3 or 1/v2

[@dineshadhikari7739]

1/root3

[@almighty3351]

Tnk u sir

[@Ghanshyam-sharma001]

8:04 and 14:01 sir could you please give the references to these formula used here.. and thanks for this explanation

[@dr.vipenpalsingh9279]

Send me an email i will send you the detailed calculations

[@harijerry]

It is recursion relation for cg co efficient

[@dr.b.s.rathore9504]

If j1= 1/2 and j2=1

[@dr.vipenpalsingh9279]

Check out CG coefficient table

[@dr.b.s.rathore9504]

@@dr.vipenpalsingh9279 what will be the solution?

[@dr.b.s.rathore9504]

Please send me the solution of this question