Japanese | Can you solve this ? | Math Olympiad X=? & Y=?

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Learncommunolizer

Learncommunolizer

Күн бұрын

Пікірлер: 20
@kurtmager1626
@kurtmager1626 7 ай бұрын
No need for the quadratic formula. Just use identities. (x+y)²=(x-y)²+4xy So x+y=+/- √((x-y)²+4xy) x,y=0.5((x+y)+/-(x-y))
@ffggddss
@ffggddss 7 ай бұрын
x - y = 4; xy = 4 Find x & y. Here's a trick we learned in high school algebra, back in the day, that will solve this problem. In a quadratic equation of the form x² - Sx + P = 0 the sum of its roots is S, and their product is P. [To see this, expand (x-r₁)(x-r₂) = 0, which obviously has roots r₁ and r₂.] In the current problem, we have the difference and product, not the sum and product; but no sweat - the difference is the sum of x and -y. So just negate the 2nd given equation, and write: x + (-y) = 4; x(-y) = -4 and now we know that the quadratic z² - 4z - 4 = 0 has roots z = x, -y. Easy to complete the square by adding 8 to both sides: z² - 4z + 4 = 8 z - 2 = ±2√2 z = 2 ± 2√2 Now we know that the product xy is positive, so x,y are either both positive (Case I) or both negative (Case II). Case I: x = 2 + 2√2, y = -(2 - 2√2) = -2 + 2√2 Case II: x = 2 - 2√2, y = -(2 + 2√2) = -2 - 2√2 Check these in the original, and they work. Fred
@ffggddss
@ffggddss 7 ай бұрын
When the video gets to 1:30, with y² + 4y - 4 = 0, the quadratic formula isn't what you want, especially in a time-limited test situation. Much faster is to complete the square by adding 8 to both sides.
@zvonimirkujundzic6867
@zvonimirkujundzic6867 7 ай бұрын
Thanks for another clear example and simple explanation, becouse the most ordinary people dont know how to solve it!🎉
@Ms_Math1
@Ms_Math1 7 ай бұрын
Good
@wagnerperlino5048
@wagnerperlino5048 7 ай бұрын
Well done !
@mircoceccarelli6689
@mircoceccarelli6689 7 ай бұрын
Observatio : 4y + y^2 = 4 y^2 + 4y + 4 = 8 ( y + 2 )^2 = 2 × 2^2 ( y + 2 + a )( y + 2 - a ) = 0 , a^2 = 2 😊👍👋
@oahuhawaii2141
@oahuhawaii2141 Ай бұрын
It's easy to brute force this problem: x - y = 4 ... y = x - 4 x*y = 4 x*(x - 4) = 4 x² - 4*x + 4 = 4 + 4 x = 2 ± 2*√2 y = x - 4 = -2 ± 2*√2 (x, y) = (2*(√2+1) , 2*(√2-1)), (-2*(√2-1), -2*(√2+1))
@bobbyheffley4955
@bobbyheffley4955 7 ай бұрын
I got the y values by completing the square.
@alamshaikhahmad2415
@alamshaikhahmad2415 7 ай бұрын
(X_y=4----- x+y=4----'xy=40)
@사현-w2o
@사현-w2o 7 ай бұрын
Thank you so much. 😊
@oahuhawaii2141
@oahuhawaii2141 Ай бұрын
09:00 Not a perfect square.
@АннаГригорьева-у8м
@АннаГригорьева-у8м 7 ай бұрын
Этот пример не похож на олимпиадное задание!!
@MRBROGFOWN
@MRBROGFOWN 7 ай бұрын
Results x = 2 + 2√2 y = 2√2 - 2
@oahuhawaii2141
@oahuhawaii2141 Ай бұрын
There are 2 solutions.
@EustahijeMihajlović
@EustahijeMihajlović 7 ай бұрын
Whats this kindergarden olympiad?
@zvonimirkujundzic6867
@zvonimirkujundzic6867 7 ай бұрын
Becouse of kindergarten questions!😂
@ffggddss
@ffggddss 7 ай бұрын
Yeah, unless it's one of dozens of problems to solve in a limited time, so to do well, you have to be quick with the solution to each question. Fred
@baovu8681
@baovu8681 7 ай бұрын
X=2,Y=2
@Vajtosan
@Vajtosan 7 ай бұрын
2-2 !=4
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