Java Spring Boot 3.2 Years Interview Experience

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GenZ Career

GenZ Career

Күн бұрын

Complete Interview Preparation Material: topmate.io/gen...
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This Video contains:
java spring boot interview questions for 3 years experience
Java Spring boot interview
Core Java Interview
spring boot interview questions and answers
java interview questions and answers

Пікірлер: 11
@genz-career
@genz-career 3 ай бұрын
Complete Interview Preparation Material: topmate.io/genzcareer/930954 Interview Preparation Kit: topmate.io/genzcareer/959954 I would recommend you to get above Interview Preparation kit and crack any interview [99% Chance]
@weednweights
@weednweights 3 ай бұрын
Thanks for the free content, this is really helpful for Java interview prep.
@shubhamjaiswal8590
@shubhamjaiswal8590 3 ай бұрын
Wow, this one was hard, questions weren't straight forward He did great for 3 years experiance guy👍
@DarakhshanHayat
@DarakhshanHayat 3 ай бұрын
Good Questions. Thank you for providing free content ❤
@manutyagi8019
@manutyagi8019 2 ай бұрын
WAP To print the sum of alternate indices of an array List asList = Arrays.asList(1,2,3,4,5,6,7,8,9,10); int sum = IntStream.range(0, asList.size()).filter(x->x%2!=0).map(i->asList.get(i)).sum(); System.out.println(sum); use intstream
@lokeshkumarreddy1346
@lokeshkumarreddy1346 3 ай бұрын
Materials pdf or videos plz let me know ?
@jitendrakumar-fg4ll
@jitendrakumar-fg4ll 2 ай бұрын
Which are the topics covered you in this pdf ?
@genz-career
@genz-career 2 ай бұрын
@@jitendrakumar-fg4ll everything
@jitendrakumar-fg4ll
@jitendrakumar-fg4ll 2 ай бұрын
@@genz-career there is any index
@bikkumallajahnavi3933
@bikkumallajahnavi3933 2 ай бұрын
List l1 = Arrays.asList(7,1,5,3,6,4); System.out.println(l1.stream().filter(x->l1.indexOf(x)%2==1).reduce(Integer::sum));
@Black_hacker-mj2ro
@Black_hacker-mj2ro Ай бұрын
public static void main(String[] args) { List numbers = Arrays.asList(10, 20, 30, 11, 21, 31); System.out.println(sum(numbers)); } public static int sum(List numbers) { return (int) numbers.stream().collect(Collectors.partitioningBy(num -> num % 2 == 0)).get(true).stream() .collect(Collectors.summarizingInt(Integer::intValue)).getSum(); }
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