Thaks Sir,Great Sesion . Never Imagined of these many scenarios in Java String. Got to know about interesting Concepts from String. Good Explanation!
@arunsekar63413 жыл бұрын
ungala madhuri Java va solli kudukarthuku oruthar porandhu dhan varanum
@anusathiya88873 жыл бұрын
really explained very well! Thank you so much
@kamilabanu6663 жыл бұрын
Super ah teach panringa.....👍
@shakilapichandi1896 Жыл бұрын
Mesmerizing...
@Humanity__56443 жыл бұрын
Vera level 💯👌🔥
@venkadesansivalingam39793 жыл бұрын
Kotlin basics videos pannunga sir plz.!
@sobhikarajkumar7225 Жыл бұрын
In 15.59 you have told s1 and s2 in SCP but it is in heap memory .not in SCP
@vijayanand90513 жыл бұрын
Sir i have doubt you said when its primitive data type only "==" operator will work but string is non primitive how "==" this operator is working
@arunsekar63412 жыл бұрын
== operator will also work for non primitive data type but it will compare the memory of the String, if memory is different for the two strings the it will go to else part that means not equal. Am I cleared your doubt bro?
@harinipriya6710 Жыл бұрын
thank u sir
@madhanp78586 ай бұрын
String s1 = "Java"; // "Java" is added to the string pool String s2 = s1 + s1; // s2 is a new String object in the heap with value "JavaJava" String s3 = "JavaJava"; // "JavaJava" is added to the string pool Sir, if two objects is going to Concatenation means, then it is in heap memory only at the run time for scenario #12. can you clarify sir? And if we use String s2 = (s1+s1).intern(); then it will be stored in String pool and both refers in same memory reference in string pool at the run time
@Amazingkattuvasi4 жыл бұрын
Years sir heap and stack detailed information needed