JavaScript Interview Questions- Machine Coding - Most Asked Question

Javascript Interview Question on objects and Array will be discussed in this video .
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[@VinitNeogi]

Should we use data.forEach instead of data.map as we are not concerned with return value of map function?

[@amitbm3608]

Thank u for the awesome video. Please continue react tutorial and complete the series.

[@sivatirumani531]

Nice Explanation

[@pranavpawar7792]

Wow such a nice explanation... I really liked your approach and logic... Thanks Nisha

[@DanielSparza]

Thanks for do this kind of videos

[@akiratoriyama1320]

Thank you!!

[@Aravind-mh5wh]

we can write using ternary operator like below let ar = ['a','s','s','b','c','a','c','d','a','s']; function arrOccurances(items){ let output = {}; items.forEach(item=>{ output[item] = output[item] ? output[item]+1 : 1 }) return output; } console.log(arrOccurances(ar)); (OR) let ar = ['a','s','s','b','c','a','c','d','a','s']; let output = {}; for(let item of ar){ output[item] = output[item] ? output[item]+1 : 1 } console.log(output) ; not only these ways, as Nisha said we have many ways to do it. Thanks Nisha :-)

[@websilt]

Another way to do this: const items = ["a", "b", "c", "a", "b", "b", "c", "d"]; const count = {}; for (const item of items) { if (count[item]) { count[item] += 1; } else { count[item] = 1; } } console.log(count);

[@kavinkumar]

well if you cant use map , let arr=['a','b','z','a','b','a','c'] let obj={}; for (let key in arr) { console.log(obj[arr[key]],arr[key]); //undefined , a initially obj[arr[key]]?obj[arr[key]]=obj[arr[key]]+1:obj[arr[key]]=1; } console.log(obj) { a: 3, b: 2, c: 1, z: 1 }

[@Aravind-mh5wh]

last line of code is repeated , so simply we can write like below obj[arr[key]] = obj[arr[key]] ? obj[arr[key]]+1 : 1;