Java 8 🔥 | Programming Interview Questions & Answers | Stream API | Java Techie

In this Tutorial We will discuss commomly asked coding & programme on java 8 stream api with hands-on coding
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[@claytonrobert3907]

Best ever java coding stream 8 video .

[@gtbaba123]

Im springboot coder. Plz continue these series. Highly appreciated your work.

[@SipunsOriginal]

Nice one quick recall before the interview.

[@saurabhsuman4960]

Simple and to the point coverage of different stream related questions. Thanks for your efforts.

[@abhinavmishra9690]

Very informative and useful video for interview. Thanks

[@dmode1535]

Thanks, just what I needed for my upcoming interview.

[@chandan07talreja]

Excellent Video Basant. Keep Interviews Videos like this coming.

[@user-rl8dl2sz9f]

Very informative and helpful

[@AkshaySingh-wx3cp]

It's just perfect. Thank you. Please keep going.

[@mohammadzakaria2579]

Great Video 🙌Thanks for sharing 👍 Please keep sharing similar coding challenges on Java8+

[@Atul_Shegokar]

wow excellent.... Thank you very much @Java Techie, many times asked this questions & now I can answer.

[@vinodnayak27]

Really Useful and covered most of the repeatated questions on Java 8 interviews...Thanks Basant😍

[@jaswantshergill8357]

Very informative video

[@sarojsahoo8763]

Very nice explained

[@soulfulGirl_]

Your really doing amazing job, with no doubt about content I can trust n watch and get quality content , thank you and please continue doing this great job.😊

[@nirmesh44]

superb explanation.

[@aman_deep21]

thank you for teaching how to use stream API effectively

[@shekhar1497]

thank you very useful lecture.

[@abhishekramesh504]

Thanks @javatechie excellent content, but for this problem, this is much simpler //find longest string from given array String longestword = strings.stream().max((s1,s2)->s1.length()-s2.length()).get();

[@neerajayarasani8456]

Simply Great video brother, Thank you

[@muhassinmusthafa3379]

Hi Bro..Thanks a lot..watched ur videos and really more helpful Two alternate ways to find the second highest number : Without using boxed() 1. Integer secondHighest1 = Arrays.stream(num).sorted().skip(num.length - 2).findFirst().getAsInt(); With using boxed() 2. Optional secondHighest2 = Arrays.stream(num).boxed().sorted().skip(num.length - 2).findFirst(); and then print secondHighest2.get() condition -> array should not be empty and must contain at least 2 elements

[@alokkottawar9394]

Informatic session

[@fookoboy9623]

very useful sir

[@jagrutipatil1020]

Appreciated 😊🙏

[@pravaskumar7078]

Ur content are always unique , Very Helpful set of Question and answers

[@anilreddy5291]

I am waiting from long time. Thanks

[@sidhanshuraghuvanshi1]

Most Interviewed questions on Stream APIs. Best channel out there as I said earlier also. Keep doing this great work man. Thanks a lot❤

[@tanveerkundargi5249]

really helpful, thank you

[@ksaravind9739]

very very good and useful bro, this is called spoon feeding 😄😍😍😍 love it

[@Rkreddy123]

Very useful

[@tveshamahanta1300]

Very useful video 🙏please make more videos!

[@sakshibhisikar2547]

Thanks for this video ❤

[@techtips7641]

Please provide more examples.. It really helps!!.. Continue doing this as a series.. thanks a lot

[@user-nd9yh2xz3h]

very helpful

[@Vithal_Nivargi]

Thanks 👍 please make one more videos on coding questions

[@amolorape13]

Because of you sir i cracked couple interviews, when I started looking for a new job, I just watching your video again and revising the concept One of the best KZbin channel for learner Lot's of respect sir..

[@Javatechie]

Glad to hear this Amol 😍. Congratulations for your achievements and keep learning 😃

[@satishp351]

good video

[@tishusingh9110]

Thank You Java Techie 😊

[@thevagabond85yt]

34:30 using map() is redundant List oneStartingNumberLists = Arrays.stream(nums) .boxed() .filter(n -> n.toString().startsWith("1")) .collect(Collectors.toList()); Since it is boxed() meaning Integer can be converted into string using toString()

[@vishalmore5653]

Hi Sir, This video is very much useful. please make such video more frequent. 🙏

[@uvanana.]

Thanks 😊

[@praveens2272]

Thanks Basant

[@icode24x7]

Nice Video..!!...Appreciate if you can you please create a playlist of Java where time complexity and space complexity is maintained.

[@neha6000]

Wow thanks

[@azharnawaz1020]

my guruji is always the best🙏🙏🙏

[@aadiraj6126]

Very useful lecture for beginners. Produce more such interview related coding questions which involves 0 to 6/7 years. We're here to consume 😋

[@Javatechie]

Sure Aadi 😜. Then KZbin is Broker

[@azharnawaz1020]

@@Javatechie No youtube is kafka server

[@muhassinmusthafa3379]

@@Javatechie

[@vino7tech]

really it is great video for clear the interview and getting more knowledge by way of your teaching . Thank you very much sir.

[@Javatechie]

Thanks Vinoth 🤗

[@yogeshpatil-vx2pi]

That’s very well covered . 👏one request Basant if u can create videos on Microservices interview questions in detailed with examples will be helpful for many of us . Thanks for all work you are doing so far ❤🎉

[@Javatechie]

Yes buddy it's in a queue. Will upload within a month

[@malleswarrao3887]

​@@Javatechieyes we are waiting

[@ishantkhandelwal6263]

Excellent ! Please bring in some more practical problem solving examples in JAVA. This is very rare high quality stuff

[@Javatechie]

Thanks buddy i will

[@arnabchowdhury4892]

​@@Javatechie Please create a java 8 code to find sub string with maximum repeating characters

[@jaswanthreddy8749]

Hello Basant, For unique elements we can use distinct() method function also right, correct me If I am wrong thinking. String name = "ILoveJavaTechie"; String[] split1 = name.split(""); Stream distinct = Arrays.stream(split1).distinct(); System.out.println("FoundDuplicate elements " + "" + distinct.collect(Collectors.toList()));

[@Javatechie]

This will give you a unique element not duplicate

[@radhikagadve]

Max length str solution ----> Arrays.asList(strArray).stream().max(Comparator.comparing(String::length)).get();

[@rishiraj2548]

🙏💯💯

[@rishiraj2548]

Good day

[@michaeldeng1981]

Hi, java 20 just released

[@akashtawade9264]

For Duplicate elements, we can use Collections.frequency(1,x)....By using this we can easily filter out duplicate. Then why you took map and all ? String s=input.toLowerCase(); char ch[]= s.toCharArray(); List list = new ArrayList(); for(char c:ch) { list.add(c); } list.stream().filter(t->Collections.frequency(1,x)>1).collect(Collectors.toList()).forEach(System.out::println); @Javatechie

[@archie5766]

hey stream dont use your brain and use hashmap...listen to basant sir :) explaining with humor really nice sir. Thanks

[@Javatechie]

🤪🤪🤪🤪

[@arnabchowdhury4892]

​ @Javatechie Please create a java 8 code to find sub string with maximum repeating characters

[@AdvaitK-kw4sb]

Great Video !! Very well explain each answer. Where can we find the source code,am not able to see in git repo

[@Javatechie]

GitHub link mentioned in the video description

[@jeebanpradhan8050]

What is identity method use case of plz ??

[@vrushabhpawar4209]

Hi @Javatechie, in 3rd question for finding 1st non repeat element from the String, if we provide new LinkedHashMap() instead of LinkedHashMap constructor refferance its giving compilation error, Do u know why?

[@Javatechie]

No we need to give a new object of LinkedIn hashmap . Pass as constructor or method reference it's upto you

[@AjaySingh-mo6ho]

if Array like this- Integer arr[] = {10, 5, 8, 22, 30, 30, 2}; then how to find second largest element of this array?

[@nikhilgobade297]

1st question was asked to me in TechMahindra interview.

[@Farm2Code]

For what much experience

[@sdash2023]

Sir they are saying not to use .Get() for optionals in reactive programs. Could u plz say whats the best way to handle optopnals in reactive way? ❤ you sir.

[@Javatechie]

Check isEmpty or offNullable in optional then get the object that is the correct way to deal with optional

[@sdash2023]

@@Javatechie thanks a lot sir.

[@Kannayyaedits]

How to find missing numbers in array using streams ?

[@sayantanghosh5939]

Please continue the Kafka series .eagerly waiting for that .

[@Javatechie]

Yes buddy next weekend i will upload 2 videos on Kafka.

[@sayantanghosh5939]

@@Javatechie please complete the series . Waiting since long for your Kafka series .❤️

[@jeebanpradhan8050]

Bro why did u take entryset here ?

[@jeebanpradhan8050]

Bro groupby simple definition plz

[@johnvick8861]

i want use of redis

[@vasu5313]

Second Highest, why cant be this... 25:00 Integer res = Arrays.stream(numbers).boxed().sorted().collect(Collectors.toList()).get(numbers.length - 2); Yes but your solution can handle exception FindFirst :)

[@_itbuddy]

Sir please make video on checkmarks for intellij

[@Javatechie]

Okay i will do that

[@bhavanisankar71]

Thanks brother first question I faced in interview that time I failed to write 😔 ,do next video for core java when we go for java 8, because in system round they are asking time complexity and memory wasting , so which one is best loops or java8

[@oludamilareolukotun9929]

Functional programming does not improve the performance of any system. it has the same complexity as writing a conventional imperative style of programming. The only advantage streams and functional programming generally present is, clean, concise and easy to read code.

[@bhavanisankar71]

@@oludamilareolukotun9929 which one best

[@oludamilareolukotun9929]

@@bhavanisankar71 Functional style is better. Take a look at the 2 styles for removing duplicate below. You will see functional is easy to read and clean FOR LOOP FOR GETTING DUPLICATE public static List getDuplicateForLoopStyle(List strings){ Map maps = new HashMap(); for (String s : strings){ if (!maps.isEmpty() && maps.containsKey(s)){ int value = maps.get(s); maps.put(s,++value); }else maps.put(s,1); } List result = new ArrayList(); for (Map.Entry entry : maps.entrySet()){ if (entry.getValue() > 1){ result.add(entry.getKey()); } } return result; } FUNCTIONAL STYLE FOR GETTING DUPLICATE public static List getDuplicateFunctionalStyle(List strings){ return strings.stream() .collect(Collectors.groupingBy(x -> x, Collectors.counting())) .entrySet() .stream() .filter(x -> x.getValue() > 1) .map(Map.Entry::getKey) .collect(Collectors.toList()); }

[@RealSlimShady-um6gf]

Latest versions of Java please.

[@garikinarajesh1999]

How you are exploring these methods. What strategy you will use while exploring any new technology.

[@oludamilareolukotun9929]

In my opinion documentation and there are also good books out there

[@Javatechie]

Practice a few more basic programs and then try to convert it to java 8 stream and play with it . You will explore more and more once you start playing with it . To be fair i don't use documentation to learn rather i tried to understand various scenarios by debugging source code

[@paramaguruo5302]

How to find unique elements from 2 different list of integers. Element in one list should not present in other list. Request you to share the program to solve the above problem. Thanks

[@Javatechie]

Please share some sample inputs

[@tejeswarreddytadi3289]

Will these be asked for 5 years candidate. Please share as well some other questions as well basant, thank you ❤❤❤ to your channel

[@Javatechie]

Yes buddy programming questions is common for any experience

[@jeebanpradhan8050]

Bro how l is first non rpt .. bcoz c is non repeat first

[@sasmitamohanty4536]

Please make videos on Apache Kafka

[@Javatechie]

Please check out my Kafka playlist

[@azharnawaz1020]

guruji please do one real time project guruji please so that we can survive in industry

[@Javatechie]

Okay i will do that buddy

[@user-kd4fm1fp8e]

continue the kafka series with a implemented project

[@Javatechie]

Yes i will

[@rashmiranjanswain601]

@@Javatechie bhai Ghar kouthi....

[@bhargavi4557]

How to remove adjacent duplicates of a string in java8

[@Javatechie]

Try this public static String removeAdjacentDuplicates(String input) { return input.chars() .mapToObj(c -> (char) c) .collect(StringBuilder::new, (sb, c) -> { if (sb.length() == 0 || sb.charAt(sb.length() - 1) != c) { sb.append(c); } }, StringBuilder::append) .toString(); }

[@bhargavi4557]

@@Javatechie thank you for your response

[@TechInfo1663]

String input= a2b2c1d3, String output=aabbcddd Anybody implement it

[@Javatechie]

You can achieve this using Java 8 streams. Here's a Java program that takes the input "a2b2c1d3" and produces the output "aabbcddd" using streams: ```java import java.util.stream.Collectors; public class Main { public static void main(String[] args) { String input = "a2b2c1d3"; String output = decodeString(input); System.out.println(output); } public static String decodeString(String input) { return input.chars() .mapToObj(c -> (char) c) .collect(StringBuilder::new, (sb, c) -> { if (Character.isLetter(c)) { sb.append(c); } if (Character.isDigit(c)) { int count = Character.getNumericValue(c); char prevChar = sb.charAt(sb.length() - 1); for (int i = 0; i < count - 1; i++) { sb.append(prevChar); } } }, StringBuilder::append) .toString(); } } ``` This program uses streams to process the input string character by character and builds the desired output. When you run it with the input "a2b2c1d3," it will produce the output "aabbcddd."

[@akashtawade9264]

For second highest number program, if int[] numbers = {5,9,11,2,8,21,21,1}; Then your logic will fail because...in reverse order it will show [21,21,11,9,8,5,1].....but second highest number is 11....but it will show 21. I think we need to add one more logic for remove duplicacy again then only it will show 11. int[] numbers = {5,9,11,2,8,21,21,1}; Integer SecondHighestElement = Arrays.stream(numbers).boxed() .collect(Collectors.toSet()).stream() .sorted(Comparator.reverseOrder()) .skip(1) .findFirst() .get(); System.out.println(SecondHighestElement); This will work. @Javatechie

[@CheeseStickzZ]

That's a nice explanation for java 8, but the exercises you are solving, best way is not to do them with streams, just a regular for loop

[@oludamilareolukotun9929]

why not stream?

[@CheeseStickzZ]

@@oludamilareolukotun9929 it's slower with streams unless you have a very large dataset in the array, like 1,000 elements, otherwise for loop and just using collections is faster performance

[@debiprasaddash654]

Then why companies are still using java8

[@coderbaba786]

Hi All, Integer l = Arrays.asList(1, 41, 3, 31, 1).stream() .collect(Collectors.groupingBy(Function.identity(), Collectors.counting())).entrySet().stream() .filter(x -> x.getValue() == 1l).findFirst().get().getKey(); System.out.println(l); In this example I am expecting output 41 but getting 3 , why ?? ?????/

[@Javatechie]

It will internally use a hashmap so we can't expect an insertion order . That's why I explained in video what to do check and apply