JEE Main 2023 PYQs - KTG & Thermodynamics | Jan Attempt | Eduniti | Mohit Sir

[@mohitgoenka99]

👉 Download KTG & Thermodynamics PDF - bit.ly/3JloO2A 👉 Jan Attempt JEE Main 2023 Solutions Playlist - bit.ly/3xlLCIp 👉 Join Telegram for updates: telegram.me/edunitimg

[@devanshkh]

sir apne youtube chennel me subscription dedo 😋

[@prakashdeora5163]

revision 11:47 {thoda hatke Q] 24:24 [In isobaric process heat Absorbed partly goes to inc. U and partly to do W 26:22 [Wd on the system means wd is - so Q = U - W is 1st law 31:19 [ thermal properties ka concept] 41:16 [Q and U relation]

[@SR20057]

1)✅ 2)✅ 3)not in syllabus 4)do it again 5)✅(do it again) 6)✅ 7)✅ 8)✅ 9)not in syllabus 10)✅ 11)✅do it again 12)✅do it again 13)✅do it again 14)✅do it again 15)✅ 16)mixed concept do it again 17)✅ 18)do it again 19)not in syllabus 20)✅ 21)do it again 22)do it again 23)✅

[@Phantomboii007]

damn

[@SR20057]

@@Phantomboii007 kyu damn bro??

[@Phantomboii007]

@@SR20057 nah I mean it's good

[@SR20057]

@@Phantomboii007 ohh thankss but my target is 90+ so it is not good

[@bhumichhabra07]

Note for self :- *work done = (n× r× Delta t ) / 1- gamma * ke = 3/2 kt * cold reservoir = sink = T2 * convert temp. into kelvin before approaching solution. * any% of Delta Q = Delta W * gamma = 1+2/f and it is independent of temprature. * ke= 3/2 pv * Cv= fR/2 *when one more vibrational degree is given then degree of freedom will increase to 2. * in isothermal, Delta U= 0 * in isochoric, Delta W=0 *in adiabatic, Delta Q=0 *in isobaric, the heat absorbed goes partly to increase internal energy and partly do work. *16th, 20th, nd 22nd question must be done once more.

[@Gwuwbakjzba]

thankss

[@dextro9322]

Kitna aya?

[@ShivrajGavande]

Yahi likhe the mene bhi 😅

[@quadirkhan8144]

31:16 new type question 25:52 confusing question 41:28 ∆Q = nCp∆T, ∆U = nCv∆T (Revisit again - (to me))

[@rishigupta3966]

11:36 concept graph 13:59 unique 23:00 one vibrational mode = 2 degree of freedom 31:47 thermal properties , visit again 35:55 see it per molecule f 39:45 concept 43:19 44:22 done in 1.3 hour

[@rameshwarsahu001]

22:16 Q11 confused 21:51 Q13 revisit 27:23 Q14 confused 31:13 Q16 concept 36:14 Q19 confused 40:21 Q21 good que 41:13 Q22 concept

[@mohitgoenka99]

well done dear

[@saurabhbansalll]

Revision Questions Q5 11:45 (different variety left it in my first attempt) Q18 35:19 (i used the pen 🥲) Q18 37:26 (missed the negative volume) Q21 40:15 (gamma is independent of temperature)

[@king32749]

Same here

[@piyushgautam2943]

Ho gya selection?

[@SleepyAurora-wq6xl]

2:22 repeat it 5:42 remember it 7:00 repeat it 10:05 repeat it 11:48 repeat it (i misread 3 into 5 in pressures value) (and also instead of multiplying 4800 with 0.9 just substrate it by 480 you found earlier) 14:40 remember the 2nd statement 18:09 nice (remember it) 20:02 its t2/t1 not t1/t2 dont get confused 22:44 vvvvimp remember it 💯 25:41 dont do silly mistakes 27:43 assume volume to be constant 29:19 language is confusing 31:39 repeat it 35:16 repeat it 41:46 remember it (oscillate means vibrational not translational)

[@mohitgoenka99]

very good dear keep learning and solving

[@riteshdebnath6044]

3:00 (Done but good for revision) 12:00 19:00 31:20 38:00 42:00 [REVISE] Note:-Always take molecular masses as M Gamma is independent of Temperature

[@mohitgoenka99]

very good dear keep learning and solving

[@Aryanandha30]

For revision 6:55 Cold reservoir= sink=T2 31:32 37:37 workdone = area under pv graph 41:06 Note 42:01 "Do not oscillate" means there's no vibrational mode 44:15 Note the way of calculation

[@mohitgoenka99]

well done dear keep solving & learning #learnlikeneverbefore

[@harshsuiwal7935]

16/20 ✅ , 2 unattempted , 2 incorrect[Assertion & reason] ,Marks 62/80 ,under 33.33 mins Q5 11:46 Q13 25:40 Q16 31:15 ,Coefficient of volume expansion😑 Q22 41:17 Manipulations Sir i wish for you to stay healthy 🙏

[@Ashketchum2025-i7b]

IMP QUESN :- Result : 5:18 / 47:33 quick review : 9:35 / 47:33 imp 14:14 / 47:33 iconic prob : 19:52 / 47:33 silly mistake : 23:15 / 47:33 ( 1 additional vibrate mode = 2 dof ) Hard : 33:49 / 47:33 LOL : 36:06 / 47:33 (🌟 ) quick review : 36:06 / 47:33 --> y = T ( cCp/Cv) lang. ki Maya : 36:06 / 47:33 quick review : 46:13 / 47:33

[@mohitgoenka99]

very good dear keep learning and solving

[@kunjalsingh55]

Each and every jee aspirant who saw your lectures is very grateful to you sir including me. I remember at the new year's eve when I was so worried regarding my Jan attempt for jee mains and finally I found this channel which just boosted my preparation. My mock test score in physics jumped from just 40 to 75. Specially those challenges which you gave and those 8 hours of 11th and 12th revision videos. And finally going through all this....I scored 98 percentile in physics. We all love you sir 🙏🙏❤️ I promise to score better in 2nd attempt 😀

[@anitabharti3464]

Thanks a lot sir for these sessions. ❤️❤️❤️❤️❤️. LETS ROCK IN SECOND ATTEMPT. And yeah sir i will utilise every single day in a precious manner and made you proud.❤️

[@Siikayy]

Glazing

[@bharathgopavaram6432]

Bro by doing all these 360 ques we can get good marks in April attempt at least 10 ques?

[@Siikayy]

@@bharathgopavaram6432 brother 10q to formula padhkar bhi nikal jayege. Aasan aarha h physics

[@bharathgopavaram6432]

@@Siikayy Ha bhai matlab, Jan attempt se aayega na concept?

[@yusufkhan-d7x3r]

amity kaissa hai?@@bharathgopavaram6432

[@sufiyanahmad4707]

32:36 Imp 41:33 Revise Easy tha Thanks sir following 10 day challenge and completed block 1 and block 2

[@nikhilraj1812]

Thnku sir ji ❤ aim 99%💯

[@iamA0509]

2:39 re (formula yaad rkho) 12:19 31:23 37:59 41:30 re 17:10 formula based 18:17 p=kt 35:00 dhyaan do

[@snehakumari4326]

11:54 16:10 18:39 approach 27:53 32:10 42:11 divide

[@mohitgoenka99]

Well done on completing it Keep learning and solving

[@DefinitelyPrateek]

13:10 Approach nahi bana 22:11 One Vibrational Node Contributes Two DOF 27:41 Approach Nahi Bana Also Temp. In K 31:40 Retry 36:00 Par ye to 3/2KT hota tha na 3/2 KT is for *translational* KE per molecule Y is adiabatic constant and does not depend on tenperature 41:57 Retry

[@tony-hh4su]

For Revision 3:43 jab bhi kuch samjh na aaye us process sei related saare formulae likh le kuch na kuch samaj aa hii jayega 5:49 forgot formula KE of molecule 3RT/2 11:56 did it but important for JEE 2024 14:41 statement 2 22:26 one additional vibrational mode = 2 extra degree of freedom 31:27 very good question 35:31 new formula for me 41:35 jab bhi heat given ho aur constant pressure or volume mentioned ho use Q = nCpΔT or Q = nCvΔT ✨ wasn't able to solve 7 questions

[@mohitgoenka99]

well done dear #learnlikeneverbefore

[@TheItachiUchiha_07]

*Timestamps* Q5 12:08 Q16 31:35 thermal properties okay!! 2023 Jan attempt done ✅ 🥲Iss chapter ko 3 saal me pehli baar pdh ke pehli baar questions solve kr raha hu still manage to make every single question except 2 🙇🏻‍♂️All because of you sir!!

[@Disha-on1ib]

5:11 2024 me same question uth ke aya dono attempt me 6:46 carnot karna hai tuje 11:41 right but alag socha 14:13 do again 19:51 observe 20:26 carnot 22:49 📝 ez 29:06 v const 30:51 excatly same question 33:35 revisit ( Thermal properties) 📝 36:05 excatly same ques 36:38 carnot 39:07 units 40:49 📝 42:14 📝 + do not oscillate matlab no vibrational✅

[@mohitgoenka99]

very good keep learning and solving

[@padhaku.neeraj]

1 2:59 formula+ good conversion there 5 13:07 micro concept 6 16:22 see answer 8 18:52 nice 10 22:01 my bad 12 23:43 learn 13 25:55 batman bawal q 15 31:02 small trick break right side into plus to get alpha fast calcultaion ke liye h physics ka concept nahi h baba 16 31:30 new concept 17 34:17 nice 20 37:27 bad question 22 43:16 batman q 25 43:55 nice

[@teaforu345]

Thanks sir 10:05 q4 11:45 q5 31:37 q16 40:15 q21 gamma is independent of temp

[@Irkntl-rm8qe]

4:44 GQ(s) 12:20 GQ(s) 31:16 new ⭐️⭐️⭐️ 37:16 eff max is 1

[@mohitgoenka99]

very good dear keep learning and solving

[@JUSTANSHKUMAR]

10:35 Q 42:10 [confused] 40:20 IMP GAMA IS INDEPENDENT OF TEMPRATURE 46:02 Q IMP 23:04 i vibrational mode means 2 extra add in f 12:03 Thoda diff sawal 14:47 Q See 2nd statement samjho 32:02 nice question 25:38 work done by gas postive hota hai + workdone on gas megative hota hai - 28:00 volume constant maan ke pv is equal to nrt 33:00 acha question hai saleem sir ne bhi pratice session main karya hai last lecture main see notes last lecture 36:52 assertion [confuse] Thank you sir

[@mohitgoenka99]

well done dear keep learning

[@Shreyas-q1u]

12:51(increase in internal energy is ΔU only) 37:50(silly mistake)(thermodynamic formula doesnt already include sign, and area under graph gives absolute work only.) 40:23(do not assume small cv on your own) 41:12- good to solve

[@mohitgoenka99]

well done on completing it keep learning and solving

[@factofam6333]

correct = 1,2,4,6,7,8,10,11,12,13,14,15,17,,21,23, incorrect = 20 (38:37 === bs maine yhi dhyan nhi diya ki work done -ve hoga maine 3rd tick kiya tha ) unattempted = 5,16,18, 22 5= 11:45 ( thoda sa hatke hai ) 16= 31:12 -- (31:41 ye to mujhe yaad hi nhi tha 😁 32:23 ye maine socha hi nhi ki pressure ko hata skte hai --- 32:42 ye to breaking news hai 😅 ) 18=35:14 22= 41:51 (do not oscilate means there is no vibrational mode ) 42:11 (ye confusion mujhe hua tha 😁) 44:34 = bas yhi me maine quest dhang se na padha

[@mohitgoenka99]

well done on completing it keep learning and solving

[@ArunRaj-px7uw]

21:50 As per formula , Vrms= Root(3RT/m) , option b and c both are correct. Please check if im wrong

[@fungamer3059]

22 - 0 vibrating mode 21 - adiabatic const independent of TEMP. 18 - avg KE/ molecule = INternal energy = f/2kt 16 - redo 13 - dq= heat supplied to sys, dw = work done by sys 12

[@mohitgoenka99]

well done dear keep learning and solving

[@chrisevans3923]

Sir Solving 2020 and 2021 PyQ first and then doing 2023 makes me feel like 2023 is very easy, thanks to you. I have good confidence in physics, and I'm following your 20-day plan. I started it on the 13th of March because of the boards, and until tomorrow the backlog will be covered thanks to you, sir. I can improve my JEE percentile, as I can feel it now. And sir, I have no words for how thankful I am to you after Jee's results. I want to meet you personally if possible.

[@kundalaman]

31:32 :- Good manipulations 🔥 41:14 :- QUICK READ 🧠

[@Myvita_chitransh]

great session sir . we respect your hard work. 😇😇😇

[@idksaraaa]

Q1 - ✅ Q2 - ✅ Q3 - ✅ Q4 - (Removed from syllabus) Q5 - ❌11:50 Q6 - ✅ Q7 - ✅ Q8 - ✅ Q9 - (Removed from syllabus) Q10 - ✅ Q11 - ✅ Q12 - ✅ Q13 - ❌ (WD on the system) 25:58 Q14 - ✅ Q15 - ✅ Q16 - ❌ 31:19 Q17 - ✅ Q18 - ✅ Q19 - ✅ Q20 - ✅ Q21 - ✅ Q22 - ❌ 41:12 Q23 - ✅ Thank you so much sir:)

[@mohitgoenka99]

keep solving & learning #learnlikeneverbefore

[@nitesh7052]

SIR PLEASE MAKE A VIDEO ON THERITICAL AND CONCEPTUAL QUESTIONS ON ALL CHAPTERS BECAUSE WE ARE ABLE TO SOLVE THE NUMERICALS BUT IN QUESTIONS LIKE Q NO 4 CONCEPTUAL THESE QUESTIONS ARE REALLY TOUGH AND HECTIC , IF YOU CAN MAKE A SINGLE VIDEO ON SUCH QUESTIONS IT WOULD BE VERY HELPFUL FOR ALL OF US ALSO YOU TOLD TO STUDY 13 CHAPTERS FROM NCERT FOR FACT OR CONCEPT BASED BUT THIS IS IMPOSSIBLE BECAUSE WE HAVE TO ALSO STUDY CHEMISTRY AND MATHS WHICH IS GOING TO BE TOUGH LIKE EVERY YEAR 😍😍😍😍🥰😃😃

[@bhaumikreelworld]

10:34 18:55 - choose common volume to determine corect graph 37:39 - trapezium ka area nikalna tha naa ki triangle ka

[@Future_iitian_]

19:49 DOUBT Sir pv = constant Let constant be k1 k2 k3 for t1 t2 t3 Then k3>k2>k1 So using hyperbola graph trends Cant we do directly? Like xy=5 is above xy=3 likewise that

[@sakshidas2961]

28:27 always put temperature in kelvin 32 :19 thermal properties in thermodynamics , if you cant complete thermal properties then go through the formula of the chapter

[@sreedipsaha1619]

13:00 very good conceptual question

[@mohitgoenka99]

well done on completing it keep learning and solving

[@adiii1618]

20 days checklist 1 phase target done Thank you sir ❤

[@Bhardwaj.Sharma]

Q.5 Unique type 12:31 Q.8 Graph based 19:01 Q.14 Unique type 27:53 Q.16 Good Q 32:15

[@KushalChaturvedi-ng1iv]

Review these questions 👇👇👇👇 22:50 11Q 32:00 16Q 36:00 18Q 40:00 21Q 45:00 23Q

[@sohampendse8488]

42:30 guruji Q.22 mein each molecules rotates kaha hai sirf , the. Translational as well as rotational must be zero no?????

[@mohitgoenka99]

translational to hoga hi just there is no vibrational

[@sohampendse8488]

@@mohitgoenka99 ok thanks sirji

[@priyanshuraj13083]

must do - 5,6,13, ***16 , 20 -[area Pura x axis se lena hai], **22 pv not equal to just kinetics energy there is a factor of 3/2

[@nikhilmahore7396]

Super fast solving thank you sir

[@rushilgupta1203]

13:50 Stuck in this question just like everyone but no problem learnt the concept 😊 19:49 question 8 - Revisit

[@mohitgoenka99]

well done dear #learnlikeneverbefore

[@rushilgupta1203]

@@mohitgoenka99 Thank you so much sir for these revision and motivation videos

[@civilbro5800]

36:54 sir in this question, how is it the assertion as whatever the value of T1 is, if T2 = 0 K it won’t make any difference

[@DrTenma0811]

Best question-31:30 Q16(to me)

[@aakash4510]

5:21(dont use PV^y as no info about P use TV^y-1) 33:25(same idea as last one)

[@IronMan-e9t]

33:50 thermal property formula revise 40:51 gama and temperature relationship

[@512_jee51]

question no 16 ...repeated question from 27 August shift 1 2021...bas us ques me PT^3=const .. diya tha jisse uska ans 4/T tha

[@Future_iitian_]

5:20 are sir to nikal lo na aap final pressure Let p initial p1 Let p final p2 Work = p2v2-p1v1/1-r And pv^r = constant 2 equation 2 variable 😊😊😊 I solved using same answer is coming same just one extra n is coming in numerator

[@study21200]

Question for revision:- 1 - 2:30 5 - 12:00 16 - 31:18 21 - 40:20 22 - 41:22

[@fact_hub9112]

Q1> 2:22❤️ Q5> 11:44 ❤️ Q16> 31:10 ❤ Q18>35:15 ❤ Q20> 37:28 ❤️ Q21> 40:16❤️ Q22> 41:14 ❤️ Q23> 43:45

[@atomsandhormones]

2:50, 13:30 (read question properly!), 16:00 (good additional pt), 19:03 (good additional pt), 28:00 (P1T2 = P2T1 i.e P/T = const!!! 🤦🏻‍♀️), 31:31 (alternative method), 35:22 (alternative method), 38:16 🤦🏻‍♀️🤦🏻‍♀️🤦🏻‍♀️🫠

[@mohitgoenka99]

well done dear #learnlikeneverbefore

[@psgaming2812]

33:33:thermal properties 36:01:used wrong method 43:40:rev

[@mohitgoenka99]

keep learning, solving and revising #learnlikeneverbefore #eraoftruelearning

[@hiteshgoyal3035]

Revision Q.1 3:30 (Approach) Q.5 12:10 (Again) Q.16 31:31 (Again Imp) Q.22,23 41:10 (Again)

[@kushalmohan2665]

Revision for ktg and thermo Q1. ,q5,q8 Q12 isothermal ∆U=0 Q16 cofficient of volumetric expansion Q20. Area trapezium Q21 Q23

[@mohitgoenka99]

well done keep learning #learnlikeneverbefore

[@Sadlife0007]

✔ day 19 ❣ ..... Wish to get this type qns in APL ""

[@flamewings-np5yx]

Isse acha kuch nai ho sakta bro🤌

[@madxgaming2198]

Sir at 43:00 ,it is given that each molecule rotate about an internal axis , thus it means 3 translational and 3 rotational eq to 6 ......???

[@vanshika_gupta]

Questions i have to review- Q14. Take V as constant Q16- thermal expansion concept Q17 Q20- revisit Q21- remember- gamma proportional to Temperature Q.22- didnt click Q23. Easy but silly mistake

[@yash_8889]

Dhanyawad guruji🙏🏻🙏🏻

[@ankeshsingh7154]

Thank u sir ❤️

[@imaginaryworld946]

5:10,11:58(🌟),39:46,46:24,31:19(👈)

[@mohitgoenka99]

well done on completing it keep learning and solving

[@Nitiangirll]

13:32 heat supply. Heat supply is work done and work done Jo ham log nikale Hain 16:10

[@mohitgoenka99]

well done dear keep solving & learning #learnlikeneverbefore

[@Dyson2024]

Revision 2:32 12:04 15:40(s-2) 31:15 35:15 38:02 41:13 43:56

[@Nameless-j3i]

42:32 mei sir ideal gas in any process ke liye hi hai baki cases mein only const volume pe hi valid hai. Source : atkins

[@aakashverma2723]

14:00 [hint recall formula of workdone ] 33:00 40:45

[@Future_iitian_]

43:30 alternate approach which is clickable Energy = f/2nrt And q = (f/2+1 nrt)for isobaric Hehe boi

[@Shubham.4xx]

12:15 Good Question(Revise) 18:11 23:18 31:20 41:22 done, thank you sir! ❤❤

[@mohitgoenka99]

Keep it up

[@Shubham.4xx]

@@mohitgoenka99 Thank You so much sir

[@adrijachoudhury4034]

thank you sir!!! done:)

[@anubhavmishra295]

Thank you sir for this session

[@sunondo8671]

2:22 12:00 15:00 22:30 23:30 26:00 31:20 35:40 40:25 41:40 44:10

[@a.l.o.k.s.o.n.k.a.r]

Doable but Tricky:- 11:56 19:57 27:34 35:08 46:19 Multiple Concept Involved:- 34:03 Thank you sir ❤

[@Scrollwithme6]

Sir literally I love your pyq session They are really helpful 😃 Keep it up the same work ! 😉

[@SHIVAPREETHAM]

KTG&Thermodynamics-REVISE💥 10:06[Conceptual-Absolute Zero Temp-> -273°C 11:48[Different type of Ques*] 14:33[Conceptual] 18:23[Graph Based] 31:19[Do it Once Again] 31:19[Arrow Plays a major Role] Sir, Should i do those Questions which i have marked for every chapter OR Follow Challenge 1&2. Please Reply Sir❤

[@mohitgoenka99]

you can do our 3 challenges dear in time bound manner

[@SHIVAPREETHAM]

OK sir,Thank You ❤@@mohitgoenka99

[@eshaK-j5g]

13:50 why we r using p (v2-v1) here he didn't mentioned about isothermal?? Pls reply!!!

[@Dev-nl5wx]

Sir please make a dedicated video on U-tube problems please sir

[@Mansisinghal1234]

Sir you are the best teacher of physics.

[@excited0628]

Tq sir ❤ For redo ✨🤞🏻 2:28{mistake Krane wala swl} 6:01 & 16:15 & 31:44 & 35:33 [equipotential kinetic energy wala concept dekho💥]🔥😳 12:14 [gud ques 🔥] 18:15 37:49{mistake Krane wala swl} 40:17[info✨] 41:21[gud ques]

[@gauravagrawal301]

THERMO REVISE DOUBT PT: 3:43 AREE BHAI SITUTN 😅 13:31 Good One 19:50 22:37 Tricky 26:58 Don't ever repeat this mistake 😢 31:35 😢 41:04 NTA ☕

[@areebnasir8880]

***delta Q=nCpdeltaT for constant pressure***

[@tanmaysharma9167]

23:00 matrix match ques confused with adiatic and isochoric bt got correct answer 27:00 silly mistake

[@mohitgoenka99]

keep solving, learning & revising #learnlikeneverbefore

[@NiteshChoudhary1-vl4qu]

2:30 7:00 11:50 14:40 17:00 20:05 22:20 23:42 27:30 29:53 31:20 37:37 40:30 41:34 44:14

[@adyasingh1603]

sir in question no.22 there is written that gases do not oscillate so don't you think degree of freedom even for diatomic gas in this will become 3 and ans would be 441 J 43:25

[@namanraikwar4555]

#7 thank you sir Great sir.

[@AyushYadav-yz1od]

33:32 revise 43:20

[@RajuBhai-dz7op]

Sir 8 th question mein agar hum slope -p,/v leke kr rahe h to mera ans a a raha h

[@RahulBisht-idk]

For revision 11 - 1 degree = 2 16 thermal ka question 23 good question 🎉

[@18darshvirsinghsec-a67]

Ques 1,5,6,14,16,21,22,23

[@anujyadav-jr7gc]

Thanks for the informative lecture

[@Shreyas-q1u]

sir at 40:26 maine zyada hi soch liya, I thought it is written Cp/small cv ,where small cv is specific heat capacity at constant volume, so this way a Molar mass term was coming , and from ideal gas equation T directly proportional to molar mass of gas .... ig

[@krisshgera2888]

you are a very good teacher

[@mohdjabir5518]

Sir ji.... 🔥🔥🔥🔥🔥🔥🔥🔥

[@sxurav]

ques -10:05, 13:00, 26:12, 28:00, 35:45, 40:26, 42:10

[@adwaithkrishna.p]

31:52 unique question 43:36

[@AbhisekKumar-wp3zi]

sir 28:08 me volume constant lenge tu p1t1=p2t2 hona chaye tha kya ?

[@AbhisekKumar-wp3zi]

sie 18:01 me tu direct value le kr krha hu tu nhi aa rha 1.6\1.4 se aisa q

[@khushbujahan7772]

Sir masaalah u are growing ❤❤ sir u wont beleive i were wstching chem video of such channel i saw all comment section qere full of eduniti of chem ❤❤❤ sir really u are great in near future u will grow more and more i will pray for u ❤❤❤

[@benzene979]

Done😌🙌,only modern physics remaining,it will be done by tomorrow 😁👍.