The PDF of session will attached to the link pinned in the Telegram Channel:- t.me/JEEnexus
@SakshamKR-zy1wi6 ай бұрын
Thank you bhai ❤
@IITIAN_IAS_Motivation5 ай бұрын
sir iska PDF nahin mil raha hai pls help team pls tg bhi check kiya content wala bhi
@novazx51933 ай бұрын
Sir pdf nhi hai telegram pe
@sanatanisandeepxyz2 ай бұрын
Sir PDF nahi mila 😢
@Sassy_6576 ай бұрын
1:36:00 method to find equivalence relation 2:32:01 must revise 2:50:55 trick 2:54:57 revise 2:57:04 imp 2:58:45 definition question 3:02:51 checking true value
@zaramuhx2 ай бұрын
doing the lords work
@Vedant-x2q6 ай бұрын
Quality learning better than most of the other coachings
@StudyModeActived6 ай бұрын
Sir , rather than making one shot , a series of lectures covering all topics in detail for a chapter will be useful..(just a humble request)
@akashs75246 ай бұрын
Yes , I agree...
@Palakpukku6 ай бұрын
I also agree
@GaganDwivedi-os5td6 ай бұрын
Koi n Bhai One shot isiliye best h kyuki one shot dekhle jee main ke 80-90 percentage to ho hi jate h Isliye pehle focus on jee main😊
@HITANSH_JEE26 ай бұрын
@@GaganDwivedi-os5td maths ke 80-90%? Air 100< vale ho kya? Kuch bhi ?? 😂
@GaganDwivedi-os5td6 ай бұрын
@@HITANSH_JEE2 bhai main ke to itne bn hi jate h bas advance mein thodi problem ati h
@ei-kun22123 ай бұрын
the only teacher who reminds me how beautiful maths can be. planning to drop this subject due to extremely hard questions... but nah its amazing
@Nitin_gotnochill_185 ай бұрын
1:09:05 sir correct answer is option a only reflexive
@MohanaPriya-qn1rm4 ай бұрын
Yes, he's right
@Abhi-w9b3 ай бұрын
But x/2 should be less than x so it is not reflexive as sir said in starting y>or equal to x
@BenStokes1234Ай бұрын
1:45:04 1:53:22 1:53:31 (🌟) 2:00:47 2:04:39 : Onto koi bhi sawal : Range = Codomain krdo bas... Codomain diya hoga, range nikalna hoga.. 1:54:09 : To find Range of y=f(x) : express x=f(y) (express x as a funcn of y) and then find all those values of y for which x is defined [ in x=f(y) ] 1:55:31 🌟 - 2:00:18 One-one / Many-one : M1 : Graph. 1:46:05 1:48:30 M2 : f(x2) = f(x1), (1:46:26 ) aur agar x2=x1 ke alawa koi bhi soln aa jaye then funcn is many one... 1:50:10 M3 : Make rough sketch of curve using AOD 2:26:24 2:21:52 : Pattern dhundho 2:36:53 : f(g(x)) and both are piecewise defined. Step 1 : in f(x), replace x ➡️ g(x) Step 2 : Draw graph of g(x) Step 3 : 2:44:30 : Inverse of a function 2:57:13 3:06:08 : g(f(x)) = x ➡️ g(x) is inverse of f(x) ⚠️ : 3:03:55 Solving Hack : 2:51:15 🌟
@abouttech77286 ай бұрын
Sir Homework : Both reflexive and symmetric so sir ek matrix bana liya A*A kyunki reflexive hai to diagonal to aayega hi relation mai For symmetric(Considering with respect to upper triangle) : ham kisi bhi ek element in upper triangle ko leyenge to uske corresponding ek element lower triangle wala aajayega so ham kisi bhi upper triangle wale element ko le sakta hai ya nahi le sakta baki kaam ho jayega so 2 choices per element of upper or lower triangle . Total no. of element in matrix = n**2 no. of element in diagonal is n no. of element in each triangle equal as square matrix so no. of elements are (n**2-n)/2 So number of relations are 2 raised to power (nsquare - n)/2
@kaliaiit6 ай бұрын
Bahuuut badhya shera.... Keep it up❤❤❤❤
@noobi5396 ай бұрын
is it helpful for someone who doesn't know A of functions?
@RSNPIT112346 ай бұрын
1:25 you will find rajwant sir
@FTGUY105 ай бұрын
😂😅
@Sachingurjar200724 ай бұрын
Yeah!!
@FocusonSolution7803 ай бұрын
41:13
@AparnaBaudh6 ай бұрын
Lots of love to you dearest sir from my core of pure heart ❤! THANK YOU
@jay_ff_18835 ай бұрын
Sir why you not covered even odd fn and periodic fn
@boarder124 ай бұрын
UDA DIYA SIR NE
@ultimatefactsff17853 ай бұрын
This is covered by sir in 11th class lecture
@gauranggupta41763 ай бұрын
Which one @@ultimatefactsff1785
@sagniksarkar85703 ай бұрын
@@ultimatefactsff1785 kisme? standard functions waali mein?
@Anonymousiey12 күн бұрын
2:14:48 idhr [1-(alpha)²] nhi hoga?
@sohzam22Ай бұрын
3:15:57 (gof)inv= (f)inv(g(inv)) , aur inv exist krne ke liye oneone hona zaruri hai. is definition se bhi direct keh skte hai
𝐓𝐈𝐌𝐄𝐒𝐓𝐀𝐌𝐏𝐒 4:12 *Topics* 4:48 Critical Topics 5:44 *RELATIONS* 5:54 Cartesian Product of two sets 7:43 Definition of Relation 9:12 Remark (Relation on A) 10:03 Description of Relations 14:57 Domain, Codomain & Range 18:32 *Total Number of Relations* 20:23 *Inverse of Relation* 23:43 *Types of Relations* 24:38 1️⃣ Empty Relation 24:57 2️⃣ Universal Relation 25:09 3️⃣ Identity Relation 25:55 4️⃣ Reflexive Relation 29:25 5️⃣ Symmetric Relation 31:10 6️⃣ Τransitive Relation 30:28 NOTE 47:50 _QUESTION: Minimum number of elements that need to be added_ 1:14:59 7️⃣ Equivalence Relation 1:15:13 _Checking Type of Relation Theoretically_ 1:24:03 👉 Equivalence Class 1:26:04 *Number of Relations* 1:36:07 *Number of Equivalence Relation* 1:38:04 8️⃣ Antisymmetric Relation 1:39:32 *Basics of Functions* 1:42:08 *Classification of Functions* 1:48:01 Checking One-One Function 1:53:15 Checking Onto Function 1:58:34 _Finding range of Piecewise Function_ 2:08:29 *Composition of Functions* 2:09:41 Example 2:16:14 Domain & Range of Composite Function 2:20:44 _Question (Multiple times Composition)_ 2:30:31 *🌟 Composite Function of Piecewise Defined Functions* 2:43:07 *Inverse of Function* 2:45:29 Identity Function 2:47:25 *Definition* 2:47:51 Algorithm to find Inverse of Function 2:52:11 *Inverse of Piecewise Defined Function* 2:58:54 Finding inverse if relation b/w functions given 3:01:36 *NOTE:* Inverse of a Function is unique 3:04:10 *Inverse of Itself* 3:07:00 *Inverse of Composite Function* 3:08:27 Condition for function to be invertible 3:11:08 _Conceptual Question_ 3:16:22 ① Graph of Inverse Function 3:17:35 ② Solutions of f(x)=x & f⁻¹(x)=x are same
@Abhi_IIT2025Ай бұрын
legend.
@Paarth-g6q6 ай бұрын
I was searching for this chapter today morning and sir uploaded it today itself thank you sir
@noobi5396 ай бұрын
Is it helpful for someone who doesn't know A or function?
@vihaansrivastava49566 ай бұрын
@@noobi539 you should just know set theory for relations. nothing else is required
@Ueuehehsjystwywhsyywyw26 ай бұрын
Thank You Jii 💕
@IITD-or6fw5 ай бұрын
Bhai pdf upload NHI hui hai , pls karva dijiye.
@mo_ayaan_5 ай бұрын
2:26:23 sir answer can be option C also right??
@Garvit-LookatthisDuude3 ай бұрын
C kaise hoga bhai 2006/2008 aaega toh cut krke 1003/1004 hi toh hoga
@Garvit-LookatthisDuude3 ай бұрын
Incorrect poocha hai
@ARJUN_OG692 ай бұрын
26:00 reflexive , symmectric , transitive sets
@protech94166 ай бұрын
1:35:53 Is me 1×1×1×2^3 If n=3
@GamingWorld-ke3jj6 ай бұрын
Sir Gaming World Me hi Hu😂 Mera naam Abhay hai😅 46:21 & 1:04:00 Thank You sir.
@RajvardhanShrivastav6 ай бұрын
Name change Kar na bhai to
@GamingWorld-ke3jj6 ай бұрын
Arey Nahi bhai, Name se kya ho jayega
@GamingWorld-ke3jj6 ай бұрын
@@RajvardhanShrivastavAbhi 12th me ho kya? Kaise chal rahi h prep?
@RajvardhanShrivastav6 ай бұрын
@@GamingWorld-ke3jj ha bhai Chal rahi he prep
@kaliaiit6 ай бұрын
Theek hai shera....❤❤
@saieshulhe45312 ай бұрын
pdf is not available on tg
@ajit62506 ай бұрын
Sir ITF ka next chapter laye pls Love you Bhai❣️❣️
@One-Shot-1014 сағат бұрын
✋DOUBT✋ 1:53:12 , can someone please explain why also option C is correct?
@Shantanu_afk12 күн бұрын
36:05, 38:58 ,40:39, 42:22, 47:29, 50:35, 58:11
@RaashiSharma2917 күн бұрын
the pdf of the session is not there on the telegram channel where is it available
Si pura to padhate with even odd and periodic fnxs ❤❤🎉🎉
@VaishnaviAgrawal-ji1vg4 ай бұрын
Very great lecture thanks bhai 🎉❤
@SharvilJoshi-bc7nm6 ай бұрын
mera bhai mera bhai💖💖💖💖
@sikhowithshubham51972 ай бұрын
Last seen1:10:00
@NihalChandsah-vv7sc6 ай бұрын
Thankyou so much Bhai
@adityakushwaha6024 ай бұрын
2:34 personal reference
@cherryblossom89596 ай бұрын
Best mathematics teacher 😮. Surely you will fall in love with maths by attending bhai's session ❤
@mariiii09-z6yАй бұрын
@@noobi539 bhai function mein toh A huta hi nahi.
@karnikatrivedi6 ай бұрын
Sir is this sufficient can we solve pyqs and all kind of questions after this??
@arnavvhhhh6 ай бұрын
yuh
@sarangg53486 ай бұрын
lol this is not board this is jee man
@simranbhadani30526 ай бұрын
Thank you so much sir 😊😊
@THEEND-y1x4 ай бұрын
Tum kahi dekha dekha lag raha hai
@AKSHAY-12903 ай бұрын
@@THEEND-y1xtera mother hain 😂😂😂
@ckjain_maths8594Ай бұрын
Sir, Please, explain the sentences " this relation is symmetric by default." " This relation is transitive by relation." An identity relation is an equivalence relation by default." " Reflexive relation by default is non- existent. ".
@ArtCraftwithAngelАй бұрын
PNC even odd functions kaha se padhe shot incomplete for function
@sikhowithshubham51972 ай бұрын
58:46 last seen
@creativecraft156 ай бұрын
1 ghante se important and main cheej .......🙏🙏🙏🙏
@KyoichiShido-ph7ez6 ай бұрын
When will be the next lecture ???
@Education-356 ай бұрын
Total no. of reflexive and symmetric relaⁿ :- For reflexive = 1×1×1 For symmetric = 2×2×2•(1) hence, 2³ ● This is for [n = 3] *_Bhai_* sabhi teachers direct formula bata dete hai no. of relaⁿs ka but aapne too..... 😃😃😃 Iss tarike se too kabhi kisi ne padaya hee nahi 😶😶😶 JEE aspirant 2025 🔥🔥🔥
@JEEnexus6 ай бұрын
Well done shera... Keep it up...❤️❤️
@cherryblossom89596 ай бұрын
Agreed 💯👍
@Education-356 ай бұрын
@@JEEnexus 😊😊😊
@ItxAbhay4166 ай бұрын
Bhai physics kaha se krna h brother plz bta de
@Education-356 ай бұрын
@@ItxAbhay416 Sorry, But me competition nahi badana chahata
@veeraraghavanpandurangan71483 ай бұрын
You can understand and appreciate it well If you study ncert by yourself And solved 75% the exercise
@fiteasy0014 ай бұрын
Sir odd even and periodic function nhi padhaya
@adityakushwaha6024 ай бұрын
3:10 concept building ques
@realkakarot2 ай бұрын
Iss sir ka naam kya hai bhai zabardast padhate hai ye 🗿 Inke waja se mera cengage calculus pura complete ho gya 🗿
@ManishSingha-ng7ikАй бұрын
Is it enough for JEE mains and boards
@Flashy_itachi24 күн бұрын
@@ManishSingha-ng7ikbro it is even enough for jee advanced.
@studyhard-e6f6 күн бұрын
Proved ❤
@sikhowithshubham51972 ай бұрын
Last seen 1:30:00
@BanothThirupathi-q6q5 ай бұрын
Thank you sir
@ABHISHEKBYAHUT053 ай бұрын
1:24 par find elements related to 3 bilkul bhi samjh nhi aaya
@adarshkumar34556Ай бұрын
anybody else having problem in opening pdf of this session? i am having.. the site is not directing to pdf even if i press on view pdf
@YASHDARAKАй бұрын
Koi mujhe vo 11 th lecture konsa hai bata sakte ho yaha pe sir jo baar baar keh rahe ki 11 me padha tha
@samaygaba4796 ай бұрын
Proofed 3rd part love u sir
@sikhowithshubham51972 ай бұрын
Sir 3:04:00 pe galat Kara hai
@ArmaanjitSingh-v7jАй бұрын
Sir iski dpp enough hogi jee mains ke liye
@priyanshuchauhanvlogs935Ай бұрын
❤❤JAI SHREE RAM 🙏 JAI SHREE GANESH JI 😊 JAI SHREE KRISHNA JI ☺️ THANK YOU SO MUCH SIR JI 😊🙏
@Ikigai7474 ай бұрын
THANK YOU FOR EVERYTHING SIR YOU ARE SUPERB!
@abouttech77286 ай бұрын
Sir doubt pls give a look Sir ek calculus ka question hai maybe i guess sir dimak mai vaise hi aagaya book mai nahi hai school teacher ne solve nhi kiya looks simple but when thinks about it its quite difficult sir pls you can help ; Sir a point going in x - axis at 1unit/second when t = 0 but acceleration in x(axis)= y(value of y) and acceleration in y(axis) = x(value of x) sir now it will also move in x and y sir ham trajectory ya path ki equation kuch nikal sakte hai kya?
@MohitSingh-ud2wi5 ай бұрын
2:40:08
@agnidiptasarkar30246 ай бұрын
1:34:35 Sir proved 3rd part
@Hitman-2566 ай бұрын
Sir kya 11-12 pcm ka sara syllabus starting se detail me kraoge na plz 🙏🙏🙏 sir reply
@manangupta25096 ай бұрын
Only maths and chemistry
@Hitman-2566 ай бұрын
@@manangupta2509 physics ni hogi?
@JaskaranSingh-hg5bn6 ай бұрын
Pata nhi @@Hitman-256
@SarthakGautam-eb3wf6 ай бұрын
Sir, The third part proved👍👍👍🙏🙏
@deepanshupanwar453913 күн бұрын
42:56
@ajay_master_mind40026 ай бұрын
Sir iss baar lecture ki starting mein nature of chapter and weightage index kyu nhai hai
@kynsign6 ай бұрын
absolutely love your efforts sir that you do for us, just another humble request to you that, please do something about physics too...physics oneshot would be a blessing for us!!
@noobi5396 ай бұрын
Is it helpful for someone who doesn't know A of functions
@kynsign6 ай бұрын
@@noobi539 totally!
@shivanisuraj64255 ай бұрын
1:39:00 functions starts
@shivanisuraj64255 ай бұрын
2:04:07 stopped
@Mehendi.vibes99Ай бұрын
This video is enough for kcet preparation??
@Aspirant.iitjeeАй бұрын
yes
@ManishSingha-ng7ikАй бұрын
@@Aspirant.iitjee is it enough if I am watching for the first time for boards and JEE mains can I watch this full series for mathematics
@Aspirant.iitjeeАй бұрын
@@ManishSingha-ng7ik yes its enough for mains provided u do sufficient practice after watching one shot but make sure that u re able to grasp everything.
@SharvilJoshi-bc7nm6 ай бұрын
love u bhai , here from class 11th
@disciplinedev6 ай бұрын
sir what is difference in these and older lectures?
@sharvarishahare5529Ай бұрын
Kn vhich pdf rakhte hai
@shsbsvsb5 ай бұрын
2:30:00
@The_Greatest69692 ай бұрын
thank u sir❤❤
@shivanisuraj642519 күн бұрын
5:54
@spicyhaikya88895 ай бұрын
11 ka relation yaad dila ke emotional kr diya sir😢
@18football186 ай бұрын
Bhai syllabus timeline 🙏🙏🙏
@18football186 ай бұрын
Syllabus kb tk complete hoga bhai???
@Cool_dhruva-xt1sq6 ай бұрын
December
@sarangg53486 ай бұрын
this is 12th relation and function only?not 11th included?
@Hemalatha-yu7ht5 ай бұрын
Yes only 12th
@yashsoni87145 ай бұрын
Thank you sir 🥹🙏🏻🙏🏻🥹
@aarushgupta17895 ай бұрын
2:26:00 sir isme C option bhi toh glt hai
@Garvit-LookatthisDuude3 ай бұрын
kaha bhai 2006/2008 aaega toh 1003/1004 ho toh gya Correct
@Garvit-LookatthisDuude3 ай бұрын
Incorrect poocha hai
@aarushgupta17893 ай бұрын
@@Garvit-LookatthisDuude thnk u i got it in last but forgot to delete the comment
@Anuragff154215 күн бұрын
40:40
@Study-pi8gf2 ай бұрын
48:41
@shubhamruparel27502 ай бұрын
Proved at 1:34:45
@srijanraj25073 ай бұрын
1:45
@paramtiwaripoint96946 ай бұрын
11 Wale dekh sakte hai ya rehne de
@gauranggupta41766 ай бұрын
Nhi 12 th ka hai
@aditi312456 ай бұрын
Dekhlo 12 me asani hogi
@vedagyamishra46506 ай бұрын
Rehne de
@vidyeshvaidya16696 ай бұрын
Rehen dekh 11th kahi kar pehle
@grewknowledge87506 ай бұрын
nope
@sameer_plays01413 ай бұрын
sir very well understood
@KanwarWorld5 ай бұрын
es lecture koo dekhne ke baad unacademy ka module solve hoo jaye gaa kya