4.3 Queue Implementation using Linked List in C | Data Structure Tutorials

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[@vishnupriyabalakrishnan920]

Q1qq

[@riyajaiswal2137]

I tried this code but its not working ...for linked list and array as well

[@AnkitSingh-go6qq]

@@riyajaiswal2137 yes i also check code is not working if we deque element many times

[@VivekRaj-eb6mk]

@@riyajaiswal2137 that's not code, that the algorithm .

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At struct datatype after} semicolon is required

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[@mohdehtesham8357]

Just one note while running the code as is, the front and rear are globally initialized as NULL, so the functions dequeue(), display() and Peek() will always hit on the first condition. So, there is a need to either initialise the front and rear as local and pass those as arguments to the given functions or update the global pointers to the recent values as a whole.

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[@darpananand9848]

Ma'am we can also check the condition for 1 element in Dequeue Function i.e if there is only 1 element in the Queue , and we want to delete it , then the code would be void dequeue() { struct node*temp=front; if(front==0 && rear==0) { printf("UnderFlow Condition "); } else if(front==rear) { printf("The element which is deleted is %d ",front->data); front=rear=0; free(temp); } else { printf("The element which is deleted is %d ",front->data); front=front->next; free(temp); } } BTW Thank you so much Ma'am for this Amazing Content ❤❤

[@justcurious1940]

No need if we don't use the rear in the past functions I think .

[@babon_zia]

Thanks for letting me understand the queue concisely.

[@ravibisht2904]

Mam apko dekh kr apne app hi padne mai man lag jata hai.. Nice explanation

[@sivasubramani612]

@Jenny, I think at 2:50 sec, we can't consider front at the right end and rear at the left end since this is a singly linked list and after deque (which will take O(n)) we can't change the rear pointer to point the previous node. What do you think? If its right. please give a like so that it will be on top and will help others.

[@pavanbhadane8334]

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[@riyajaiswal2137]

I tried this code but its not working...linked list and array as well for queue ...both arent working.

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[@baraamayasa5190]

thanks for your great explanations the data structure more fun and a lot easier with your lessons in this code there is a little problem when the front and rear pointers referring to same node because front pointer will be null otherwise rear pointer will lost the node but in that situation must refer to null so we need to add that statement to the code. #include #include struct node{ int data; struct node* next; }; struct node* front=0; struct node* rear=0; void enqueue(int data){ struct node* newNode=(struct node*)malloc(sizeof(struct node)); newNode->data=data; newNode->next=0; if(front==0&&rear==0){ front=rear=newNode; } else{ rear->next=newNode; rear=newNode; } } void dequeue(){ struct node* temp=front; if(front==0&&rear==0){ //&&rear==0 printf("empty queue "); } else if(front==rear){ //peek(); front=rear=0; free(temp); } else{ //peek(); front=front->next; free(temp); } } void display(){ struct node* temp=front; if(front==0&&rear==0){ printf("empty queue "); } else{ while(temp!=0){ printf("%d\t",temp->data); temp=temp->next; } printf(" "); } } void peek(){ if(front==0&&rear==0){ printf("empty queue "); } else printf("front data: %d ",front->data); } int main() { dequeue(); enqueue(5); enqueue(0); peek(); enqueue(-3); display(); dequeue(); dequeue(); dequeue(); dequeue(); enqueue(11); peek(); display(); return 0; }

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[@raghavjoshi9751]

Mam in deletion condition their should be one more condition that is else if(front==rear) { printf("deleted element is %d ",temp->data); front =rear=NULL; } cause in last else condition (front= front->next) that make the front to point to the next undefined memory

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[@rahulsrivastava7017]

in dequeue(), there should also be a condition for when there is only 1 element in queue, that is, else if(front==rear) { Node *temp=new Node(); temp=front; front=NULL; rear=NULL; free(temp); }

[@pavanbhadane8334]

We can just write free(front) front=rear=NULL;

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😅

[@justcurious1940]

@@pavanbhadane8334 exactly what ChatGPT just told me.

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to be honest I was distracted while going through the topic, its due to the beauty you hold mam.

[@sharath5796]

note : while dequeue op, first we have to make temp->nxt as null and then free temp

[@justcurious1940]

Do we make a memory address NULL before or after we free it ?

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Mind Blowing Explanation Maam thank you :))

[@sudharsands5773]

Mam, you missed discussing a case in dequeue() i.e,, when front==rear. When front and rear is point same node

[@justcurious1940]

U will have to update the rear or the whole code will break;

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Great Explanation.......

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Amazing content Jenny! Keep it up.

[@alokshukla1223]

Thank you ma'am ! That was really very helpful.

[@jithinmv6516]

in dequeue you forgot to write the case for a single element, I mean front and rear points to same node, Which means only one element in queue, So we have to do (front=NULL and rear=NULL)

[@karamsingh7785]

That's exactly what i was going too comment

[@arvsaurav]

I think there is one other way i.e., if we will use only front==0 instead of (front==0 and rear==0) at every place.

[@qasimalikhan9692]

else if(head==tail){ std::cout

[@ankitxalxotoo5580]

@@qasimalikhan9692 thanks brother

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thank you ma'am!!!!!

[@HarithaSree14]

Awesome mam....Helps a lot

[@ducatidiavel9639]

Hello Ma'am, I have 2 questions, 1) Given that the video is about a LL implementation of a linear Q, are there any rules that a circular linked list cannot be used, in place of a singly linked list with 2 pointers? 2) And regarding your statement that a DLL using a head and tail pointer.. A DLL uses Nodes that only have a previous and next pointer right?

[@ayaamverma6742]

1) A circular LL can be used here tho it will also contain the head and tail pointer like the singly LL used here; thus practically we will be using only the semi-circle of the CLL since our enqueuing and dequeuing are restricted between the head and tail pointer. Hence the last pointer of our CLL (from last node to first node) won't be of any use and simply be using memory space. Otherwise using a CLL is as good as singly LL.

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Very easily explained 👌

[@polymathmeraj6750]

a small correction..... in dequeue operation, a new condition will come, if(rear==front && front!=0 && rear!=0){ front =rear =rear->next; free(temp); }

[@justcurious1940]

Yes, I agree .

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Thank you so much 😊♥️♥️♥️

[@LakshanWannige]

Thanks ma'am.

[@tejamucharla2727]

Hii mam this is teja.. In enqueue you did the one mistake. That is in while loop your wrote the temp. Never temp equals to 0.You to do temp->next ==0

[@avirupbanerjee3253]

Mam why do we need to specify both front and rear while checking whether the list is empty or not. We can do it using rear only.

[@DoronOverflow]

I came across a video here, I think you have a bug, in the dequeue function. You did not check the case if in the queue have only one element. Because then what happens ? You do not maintain the rear pointer. For example when you check if the queue is empty the test will not be correct! Say try if your program to run: enqueue then do dequeue and then print. The easy correction is, after front = front->next: if (front == NULL) rear = NULL; Besides it looks great channel, will start watching

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Thanks Jenny Maam

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Mam please post a video on priority queue and it's algorithm

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I have implemented the logic myself first and then watching the video 😁

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Thank you 🙏