Thank you so much !! I learnt something new and awesome
@jiejenn3 жыл бұрын
Glad the video helped.
@lolocucaracha4 жыл бұрын
You are the best! Thanks you!
@nathitshabalala54142 жыл бұрын
My man!
@vishnumohan89773 жыл бұрын
I need to specify the sheet name and the header while selecting an excel file using this method. Is it possible?
@eduardoribeiro27973 жыл бұрын
Hi Jie, how should I proceed to copy the selected files to another path? Could you help me?
@crazybeyblader23724 жыл бұрын
What if i want to select a folder ?
@luisguareschi51044 жыл бұрын
filedialog.askdirectory()
@poloikary4 жыл бұрын
Thanks, This is similar to what I want to do but I am new to python. I I have a code that compile cvs and I would like to choose everytime a folder to run the code and merge the cvs on that particular folder. Any guide in how to do that? Thank you very much for your video
@4ng8bf665 жыл бұрын
How do I display the result of random numbers in a text box instead of the terminal?
@robertwest57463 жыл бұрын
Great. Thank you. How did it work? You have fie_path. I guess file_path was already stored.
@eliav35 жыл бұрын
does anywone have similar solution to python 2.7? "withdraw()" has not worked for me
@tayyab15 жыл бұрын
Thanks
@gurubellimanoharsai74164 ай бұрын
could you explain root.withdraw()
@ArtisticWorld4all5 жыл бұрын
if I want to open a folder then select the image then how can I do that???
@jiejenn5 жыл бұрын
Not following your question. Can you be more specific?
@ArtisticWorld4all5 жыл бұрын
@@jiejenn I want to make a program by which I can go to any folder and selects any image from there and then this image will show in window
@TheJonathasg5 жыл бұрын
@@ArtisticWorld4all import PIL Than it will look like something like this Image_file = Image.open(file_path) Image.show(Image_file) Try it, i don't know if it will be exactly like this because i'm typing from my phone, but will be really similar
@JAMESDOOM225 жыл бұрын
@@TheJonathasg def openImage(): fullfilename = filedialog.askopenfilename(initialdir="/", title="Select a file", filetypes=[("Image files", "*.jpg; *.png")]) if(fullfilename != ''): im = pimage.open(fullfilename) im.show() what is lack about this code? i use button to open file dialog then display it in new window...
@TheJonathasg5 жыл бұрын
@@JAMESDOOM22 install pillow via pip, then: from PIL import Image im = Image.open(fullfilename, "r") im.show() try it