Joel David Hamkins & Graham Priest: The Liar Paradox & The Set-Theoretic Multiverse | RP #60

  Рет қаралды 4,815

Robinson Erhardt

Robinson Erhardt

Күн бұрын

Пікірлер: 55
@joeldavidhamkins5484
@joeldavidhamkins5484 Жыл бұрын
Joan Bagaria, mentioned in the introduction, is staunchly Catalan, rather than Spanish, and based in Barcelona.
@robinsonerhardt
@robinsonerhardt Жыл бұрын
thank you for clarifying this!
@Spacegraham
@Spacegraham Жыл бұрын
Great lineup...great video!
@robinsonerhardt
@robinsonerhardt Жыл бұрын
thanks graham
@romanbesel4759
@romanbesel4759 Жыл бұрын
Those are two of my favorite thinkers. If you now bring Penelope Maddy on, I die a happy man.
@robinsonerhardt
@robinsonerhardt Жыл бұрын
will get to work on that, then!
@zeke4665
@zeke4665 Жыл бұрын
Love both guests. And awesome dialogue. But I like the mustache even more
@robinsonerhardt
@robinsonerhardt Жыл бұрын
I prefer the guests but am enjoying the mustache too
@annesmith2400
@annesmith2400 Жыл бұрын
Discussion much appreciated TY gentlemen 💕
@berick0176
@berick0176 Жыл бұрын
This is certainly one of the podcasts of all time
@robinsonerhardt
@robinsonerhardt Жыл бұрын
that’s precisely what I want to hear
@bilgekoksal3537
@bilgekoksal3537 Жыл бұрын
Great video! I wonder how the discussion at the end of the part Paraconsistent Logic and the Liar would go on. It seems reasonable that replacing the liar sentence with "this sentence is either false or not well-formed" should be giving rise to another paradox for Joel. Although he says he wouldn't recognize it as a well-formed proposition in the first place (which I am inclined to accept), then I am not so happy, because I can argue again what Graham said, and I feel like going back and forth between these is the liar all over again. Does anyone have any thoughts on this?
@MasterBoshan
@MasterBoshan Жыл бұрын
I saw this when it had
@robinsonerhardt
@robinsonerhardt Жыл бұрын
there’s a few billion people it hasn’t hit yet
@pawarranger
@pawarranger Жыл бұрын
wow what a treat
@robinsonerhardt
@robinsonerhardt Жыл бұрын
🦢
@timdion9527
@timdion9527 10 ай бұрын
All logicians are liars. It is the only solution to the Liar's Paradox... Alas, my statement is true but not provable.
@muhammadhanzlaqadri7229
@muhammadhanzlaqadri7229 Жыл бұрын
Wish you could’ve invited Hartry Field too.
@mikhailfranco
@mikhailfranco Жыл бұрын
I recommend the book: _The Liar: An Essay on Truth and Circularity_ Barwise and Etchemendy
@StephenPaulKing
@StephenPaulKing 11 ай бұрын
Robinson, you might look into Non-well founded set theory. Jon Barwise, no longer with us, did a lot of work on its application in computer science.
@ReflectiveJourney
@ReflectiveJourney Жыл бұрын
super hyped for this one.
@robinsonerhardt
@robinsonerhardt Жыл бұрын
me too and I’ve listened three times
@johnschindler4152
@johnschindler4152 Жыл бұрын
If I understand Sorensen's setup of Yablo's paradox (46:25) correctly, can't we assign alternating truth-values consistently with the relevant instances of the T-Schema? That is, all odd-numbered people speak truly and all even-numbered people speak falsely, or vice versa.
@joeldavidhamkins5484
@joeldavidhamkins5484 Жыл бұрын
If the Yablo assertions assert "all later assertions are false," then your proposal wouldn't work. If they each merely assert "the next assertion is false", then your proposal is fine. It is the former situation, consequently, that is more paradoxical.
@StephenPaulKing
@StephenPaulKing 11 ай бұрын
Self-consistency of axioms seems to be the criteria of existence of a logical system. How is self-consistency proven internally in such cases?
@pmcate2
@pmcate2 2 ай бұрын
the poor audio on graham's end kinda makes this unlistenable.
@Erin-un3xp
@Erin-un3xp Жыл бұрын
The electrons in that painting is definitely a responsive energy!
@mkhex87
@mkhex87 Ай бұрын
Priest and Hamkins is a dialogue I am only now realizing I needed
@BlakeErhardt-Ohren
@BlakeErhardt-Ohren Жыл бұрын
@robinsonerhardt
@robinsonerhardt Жыл бұрын
yes agreed
@patrickwithee7625
@patrickwithee7625 Жыл бұрын
Isn’t the Liar’s Paradox a formal fallacy? That is, we can’t just define A=~A at the meta-level, but this seems to be exactly what the Liar’s Paradox is doing. Clearly, if you suppose A~A, you’ll be able to get a contradiction and prove ~(A~A). Those seem to be our two options: prove that an in-language formalization of the Paradox is just an inconsistency, or fallaciously define a formula as its negation. In terms of natural language, I agree that “this sentence is false” seems to be saying something, but we know that a formal theory’s truth isn’t definable by that formal theory, a la Tarski. So, whatever it’s saying is either just absurdity in a different fashion, or it’s just a demonstration that semantic truth is logic/theory-specific.
@Erin-un3xp
@Erin-un3xp Жыл бұрын
This is great!
@robinsonerhardt
@robinsonerhardt Жыл бұрын
I'm so glad you like it :)
@pairadeau
@pairadeau Жыл бұрын
this
@annaclarafenyo8185
@annaclarafenyo8185 Жыл бұрын
This discussion is pointless, as neither the mathematician or the philosopher understand computational foundations.
@jwp4016
@jwp4016 Жыл бұрын
This the perfect youtube comment for the most renowned logician and set theorist lol
@annaclarafenyo8185
@annaclarafenyo8185 Жыл бұрын
@@jwp4016 "Renowned". Joel Hamkins is a good set theorist, but he doesn't follow modern foundations, although he's a finitist when you compare him to other set theorists.
@pmcate2
@pmcate2 2 ай бұрын
@@annaclarafenyo8185 It's not clear how you came to the conclusion that Joel is more finitist than set theorists. Much of his work is infinitary.
@annaclarafenyo8185
@annaclarafenyo8185 2 ай бұрын
@@pmcate2 He's a finitist compared to Woodin. Woodin still thinks the Continuum Hypothesis has an answer.
@annaclarafenyo8185
@annaclarafenyo8185 2 ай бұрын
@@pmcate2 It is not easy to see when work in set theory is "infinitary". Likely the most finitist person in set theory was Cohen, the second in line is Solovay.
@annesmith2400
@annesmith2400 Жыл бұрын
Eubulides the Megarian🏺😎 💞impredicativity💞
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