This animation shows the Joule expansion of an ideal gas. The speed of the particles stays the same during the expansion which explains why the temperature of the gas remains the same.
Пікірлер: 25
@mithileshsingh12126 жыл бұрын
initial and final temperature of gas in chamber is same only, otherwise temperature does not remain constant during the process this is because speed of particle does changes , first increases and then decrease
@lucasherrmann69852 жыл бұрын
For this reason it isn't a isotermic process.
@aryanaryan99899 Жыл бұрын
@@lucasherrmann6985first increase (T) and then decrease(T)
@aryanaryan99899 Жыл бұрын
@@lucasherrmann6985he stated that in the end about temp.
@anthonykaburu39762 жыл бұрын
What do you use to make the animation?
@iqraurooj65167 жыл бұрын
But my book says: when sudden expansion of gases occurs cooling takes place (Joule Thomson effect)
@newfiecanadian7 жыл бұрын
Yeah, what's up with that? Why does an ideal gas not cool upon expansion?
@iqraurooj65167 жыл бұрын
but this video shows that the speed of the particles stays the same during the expansion so the temperature of the gas remains the same.. wasn't it supposed to cool upon expansion?
@newfiecanadian7 жыл бұрын
Yeah, I'm confused too. I'll let you know if I find out anything to clarify. :)
@Wexexx7 жыл бұрын
It does not cool because in the special case of an ideal gas the Joule Thomson co-efficient is zero. However, if you have a real gas it will indeed cool.
@iqraurooj65167 жыл бұрын
Ohkay. So joule thomson effect is experienced only incase of real gases. Thankyou for the clarification.