Joule Thomson Effect || Thermodynamics Chemistry || Lecture - 18 || Chemophilic Academy

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[@ishasharma8696]

Sir ur teaching manner is superb.... thank you so much sir for explaining....i am very confused that topic but now i completely understand thank you so much....❤️

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Great job sir

[@babokhan6118]

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[@subhashverma9252]

And check first law of thermodyanmics

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[@aakasharora155]

You explained this topic so well!!

[@gouravchakraborty6196]

There's something missing here.. you should have mentioned heating and cooling above and below inversion Temperature respectively. I was looking for an explanation of that.. moreover boyle temperature is also basically the temperature where Z for real gas approaches that of ideal gas, i.e., it behaves ideally. Then how come a gas have two ideal temperatures?

[@theseeker7903]

I think....Boyle temperature is temperature at which a real gas behaves as ideal gas on maximum pressure range.... but at inversion temperature, it becomes completely ideal gas no matter what the pressure is...

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[@uttampadval3066]

Very Nice explanation

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Bahut achha bolaa

[@afsanaansari1008]

Teaching method is awsm

[@mayankmishra9227]

Yesss dear

[@avishekghosh7706]

Appreciated 👏

[@anamikavermaofficial54]

Thnku sirr

[@AN-or1ed]

Exelent

[@anjalikanwar9558]

Tq sir

[@rex007yt2]

Sir!! something went wrong.While doing mathematical analysis of joule thomson effect. According to you 1st law of thermodynamics is dU=dQ+dW. But in actual it is dQ=dU+dW.Please clarify the problem or my confusion..

[@pallavisingh3446]

No the 1st law of thermodynamics is discussed correctly...

[@pallavisingh3446]

Please check your books

[@faridayesmin602]

That differs in case of physics and chemistry due to pressure measurement.

[@washimakram7381]

Koi btayega w= -pv kese hua?

[@abrarifaz2313]

E = Q - W E= Q=W Which one is correct????

[@snehaa_12]

At 7:44 dp kha gya ye smjh ni aaya !

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Sir aapki aavaj hi nahi aari iss vdo m

[@activitybasedlearning5275]

dp=- why?

[@gouravchakraborty6196]

That's because on moving from P1 to P2 the gas os expanding hence final pressure is less than initial pressure. That is why dp=negative

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Sir chemical potential pai aik veideo banao

[@sussushi]

veideo spelling is wrong, video

[@electrogirl9638]

Thoda slow smjaao sir

[@thebookishgirl927]

P2 Jo Hoga negative kyuki P1 jyada hai

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Nd thanku for reply....sir g

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Yes

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Wth sir teach a bit properly and slowly it's to hard to catch