Voltage Drop Calculation for Cables - Voltage Drop Tutorial for Electrical Engineering

[@EngrAhmedMahdy]

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[@alijaved21]

when referring to using 2 cables to reduce voltage drop. Do you mean increasing the number of cores for the supply voltage cable?

[@EngrAhmedMahdy]

Not cores, actual cables. Instead of one 200 mm2 cable, you will connect two of that 200 mm2 in parallel. The current will be divided by half and the voltage drop as well.

[@kobe8502]

At 6:45 you said that if we're adding loads, the voltage will reduce. However, according to Ohms law: V = IR, an increase in resistance(load) will result in an increase in voltage also. I may be wrong but can you clarify this part? Thank you!

[@EngrAhmedMahdy]

Hey Kobe, Remember that loads are connected in parallel, so the total impedance will be reduced leading to increase in current and subsequently, increase in the voltage drop in line.

[@kobe8502]

@@EngrAhmedMahdy Thank you for this

[@kobe8502]

@@EngrAhmedMahdy I'm at the near end of the video. Why did you say that the solution for voltage drop is to decrease the resistance? Does it mean that if the loads that are connected in parallel are reduced, then our current will also decrease resulting in a lower voltage drop? Thank you in advance for your help.

[@EngrAhmedMahdy]

@@kobe8502 V at the load = Vsupply - I*Z(drop on impedance of cable) The voltage drop can be reduced by selecting a cable with higher crosssectional area to decrease the total resistance of cable leading to lower voltage drop.

[@aminebe2354]

thank's for you video @Ahmed Mahdy

[@EngrAhmedMahdy]

You are welcome :)

[@y20likujyb]

what If we have for than one cable for each phase?

[@EngrAhmedMahdy]

The current will be reduced and the voltage drop will go down. If I have one cable and the voltage drop is 5%, by having two cables of the same size. The VD will be 2.5%. VD=I*Z, the current is divided into two cables so the total current will be reduced by half as each cable will only take half of the original current. This will lead to decreasing the VD to half.

[@mayudinmultani8240]

18:09 Please explain line to line voltage in 3 phase system is 208 v You put value 380v as base voltage where this 380 come from

[@EngrAhmedMahdy]

The phase voltage is 220V and the line-line voltage is 380V at load or 400V at the transformer. When calculating the voltage drop percentage, you divide the voltage drop by the nominal line to line voltage (380V or 400V) If the supply is 380V line-line voltage, you use this value.

[@nandikavish8202]

Sir, in this example, why did you not consider the line to line voltage to be 400 Volts as mentioned in the supply voltage? Please clarify.

[@EngrAhmedMahdy]

Hey, Yeah, it should be 400V instead of 380V. We usually have 380V as voltage at end user and 400V as a supply from the transformer itself. So there are 20V for voltage drop.

[@abouakrekhan3028]

Tank you

[@EngrAhmedMahdy]

You are welcome brother :)

[@ahmedcade9202]

TNX SIR , BUT I WANNS KNOW HOW DID YOU FIND THE LENGHT 120 IS IT FROM THE CATALOG OR IT WAS GIVEN ?

[@EngrAhmedMahdy]

Length of cable? This is obtained from the cad plan after you design the route for cables in the electrical design, you will be able to the length.

[@ahmedcade9202]

@@EngrAhmedMahdy that is real live example . but according to this example was it given

[@EngrAhmedMahdy]

@@ahmedcade9202 Yeah, it is given in the problem.

[@ahmedcade9202]

@@EngrAhmedMahdy than u

[@roshanshrestha9182]

Hello sir, I was looking for a complete electrical system design course

[@EngrAhmedMahdy]

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[@roshanshrestha9182]

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[@neethusuresh4751]

Words are not clear

[@EngrAhmedMahdy]

Thank you for your comment. I wanna ask you a question, can you watch this one and let me know if it is better or not and the words are clear or not? kzbin.info/www/bejne/q5eXhXSAr6uIsKs