Kinetics of Particles Example in Cartesian Coordinates - Engineering Dynamics

[@julseu_lol]

2 hours of paid lecture from my professor and all it took is someone from youtube and 30 mins (introduction + this video) of my time to finally understand the concept. You're a lifesaver, man! Thank you.

[@ireneyousif1513]

Your voice is very soothing. You really help me get over my ex.

[@structurefree]

If I could be a material property, I would be the modulus of toughness...💪....I hope you finish your engineering degree and become the baller you were meant to be!

[@SuperJclam]

THanks! for explaining step by step! my professor wont explain anything he just derives the formulas :(

[@TheLevidance]

Exact same here, he spends 500 hours every lecture deriving formulas, and then goes through an example thats literally "Here are our equations, lets sub in some values, cool, thats our answer". If it weren't for structurefree, I'd have failed long ago

[@kitho147]

You are truly amazing at presenting those concepts! Big thanks!

[@structurefree]

Thanks!

[@droe1337]

I think its pretty clear... Thanks btw! learning alot

[@sribantichakraborty5503]

thanks

[@Hanker14]

shouldnt the X componet Wx be Wx CosTHETA rather than SINE, can someone please tell me why it isnt.

[@structurefree]

+Ehioze Hanker i use sine because the 15 deg angle is between the W vector and the y-axis, which is perpendicular to the inclined plane.

[@2ris2]

I didn't understand how you factored out (g) from the step at 11:51. I don't think you can factor out the (g) like that. if you see the previous step g(sin theta) - uk(cos theta) = a, g was multiplied only to the (sin theta) and not the coefficient of kinetic friction. If you leave (g) un-factored you get a value of 2.1526 m/s2 as your acceleration.

[@michaelmolter6180]

For me, the hardest part of these problems is converting a horizontal angle to a vertical angle (6:34). Every instructor brushes that part off, but that's where I make the most mistakes. Where can I learn more about doing that switch correctly? I just don't see it intuitively.

[@DeanOckenden8]

Move the block down to where the angle is. As in, the block would be sitting on a rotated Cartesian plane. That should show that when say the X plane is rotated, the y plane rotates proportionally. Then slide the block up X plane to its current position and you'll realise no rotation has changed and the rotation is still proportional. Probably a very poor explanation. Something much easier to teach in person. Probably worth asking your professors about it one on one.

[@abhishekgiri4694]

why did you put Wx = Wsin@ but not (Wcos@) and Wy = Wcos@? Can you explain a bit, please? (@ = theta)

[@WeightLossWebsite]

because the 15 deg angle is between the W vector and the y-axis, which is perpendicular to the inclined plane.

[@deno141]

should have gone to spec savers.

[@seabasschukwu6988]

Kinda lost me where when we tried to prove that acceleration is constant. Around 13:20