Kirchhoff's Rules (3 of 4) Circuit Analysis, Example No. 2

[@Xx-nd1rs]

thannnnnnnnk you I have an exam and before I watched your video I was totally lost but you made it so easy and clear..I understood it very well... thank you again you are genius!

[@stepbystepscience]

Great, thanks for the comment, I hope the exam goes well!

[@RawDiscovery]

I am in the same boat right now, I have my first exam in a few days and have learned a lot from this KZbin channel. Thank you!

[@kanagarajpalanivel8271]

It's very kind of you to respond promptly to individual ,which speaks volumes about you.I myself a senior Professor of Internal Medicine in a Govt.Medical College.Thanks-Dr.Kanagaraj.

[@stepbystepscience]

I teach physics and a little math at a small private school in Berlin, Germany.

[@scourgemusic8490]

Step-by-Step Science sir you are a life saver im really REALLY thankful for this Im a student of electrical power engineering and electric circuit analysis was really giving me a very tough time The way you explained kvl and kcl have helped me a lot Hats off to you sir much respect

[@Afrojaw329]

8 years later and this video is still helping the current generation of EE students.

[@stepbystepscience]

great to hear, thanks for your comment

[@Garen1]

I dont know why u are not that popular yet. Ur videos are freaking amazing!!!! Its clear and easy to understand, thanks alot!

[@stepbystepscience]

+Alla tatevosian Thank you very much for noticing and commenting, tell all of your friends! You can see a listing of all my videos form my website at www.stepbystepscience.com

[@chemist7908]

I know sheesh

[@nashenaspadarem398]

Why we have two voltage sourses? 🤔

[@fusetechllc]

I am not studying electrical engineering. I have to know this for an electrician contractor licensing test. I studied Ohms Law in apprenticeship school, but never any advanced formulas. (I did find Kirchhoff, Superimposition and Thevenin in my old textbook.) My new textbook was too complicated. I found other videos with similar techniques, but this method works without having more calculations. Using the node rule to write out the equations eliminates steps that get confusing when calculating the current and voltage drops later. I had a textbook quiz that only had answers and didn't show how to solve it. I tried multiple ways for hours and days. I finally got the answer by trying different combinations of the various values. I had to add the two power source values together for one of the branches. But, I couldn't figure out why the answer was correct. With this method, the positive and negative values and current direction are determined before you work any equations. I got the correct answers to the textbook quiz, following this method, on the first try. I agree with other comments that your channel should have way more views and likes.

[@stepbystepscience]

Thanks very much for your great feedback

[@amosmclaughlin6186]

Very helpful I learned this in class the other day and was confused, this cleared it right up for me!

[@stepbystepscience]

Great that you found the videos helpful. You can see a complete listing of my videos at www.stepbystepscience.com

[@theimprovist4158]

This guy is amazing, he literally explained the whole chapter, including an efficient solving method for the equations. Thank you so much

[@stepbystepscience]

That is very nice of you to say, thanks!

[@theimprovist4158]

You re kindly welcome

[@saarah1750]

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[@stepbystepscience]

Thanks, so nice of you!

[@laurenadkins147]

Thank you so much for these videos. Your videos are by far the most helpful and easy to follow that I have come across. I always recommend your videos to friends who need help!

[@stepbystepscience]

Thank you very much for the comment and all of the support. Very nice of you!

[@Hadesgrieve]

I found your video 15 minutes before my exam, It helps a lot! Thank you

[@stepbystepscience]

Great hope the exam went well!

[@kanagarajpalanivel8271]

I am a senior medical doctor -found very easy and useful to teach my son .fine

[@stepbystepscience]

Thanks for all of the great comment and thanks for helping your son. He is lucky to have such supportive parents.

[@tsholofelommopane9659]

wow ur amazing sir I didn't get a thing in the lecture room on this concept,but through the basics u presented followed by application of the basics and steps u stated ,now I get it...grt work ur the best God bless the works of ur hands

[@stepbystepscience]

Great, glad that the videos were helpful and thanks for letting me know.

[@noorahmad.35]

I have so much respect for the people that can teach others in a simple way. Thanks a lot! You just got yourself a subscriber!

[@stepbystepscience]

You are very welcome and thanks for the great comment.

[@timnablessing3049]

thanks so much i had alot of problems in solving kirchoffs law but after watching this video i learn more

[@stepbystepscience]

Glad to hear that and thanks for commenting.

[@guuguu7559]

I’ve my mid term in 3 hours u saved my life thanks 🙏🏻

[@stepbystepscience]

You're very welcome!

[@Shipsisawesome]

I love physics, but these circuit problems give me some serious headaches. Thanks to your video I now can wrap my head around it and achieve the desired results. Thank you!!

[@stepbystepscience]

Yes, they can bit of a pain in the you kn ow what. More algebra than physics.

[@datpham31415]

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[@stepbystepscience]

Thanks for all of your support and comments.

[@crunchygoow6940]

I am sharing this channel with my class chat!

[@stepbystepscience]

That's wonderful, thanks for sharing!!

[@joloallexicepineda7347]

Thank you I clearly understood the lesson 😁😁😁 May God bless you always!

[@stepbystepscience]

I'm glad it was clear, you are most welcome!

[@rocketzan]

Great video! You're a life saver, keep up the great work!

[@stepbystepscience]

Thanks, will do!

[@carlosdominguez7088]

Excellent as the two previous ones. Thanks!

[@stepbystepscience]

Thanks again.

[@redmanmain2204]

your the best.. great instruction skills step by step.. i await more of your excellent teachings.

[@stepbystepscience]

Thanks for the great comment, You can see a listing of all my videos at www.stepbystepscience.com

[@acdcjonnyboy]

Great video, love the way you explain every step very thoroughly, this is exactly the type of video that helps people like me learn, thanks for the excellent video and teaching style. However I did get stuck at 9:18, couldn't quite work out how you got to 4.21. Nonetheless your video taught me a lot and was very helpful.

[@stepbystepscience]

Thank you for the very thoughtful comment. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@julliferjosephtuba2202]

I'm 2 years late! but for 9:81, 3.21(I²) was simply transposed to the left side of the equation. Remember that any variable has a coefficient of 1 by default, thus 3.21(I²) was added to 1(I²) and got 4.21(I²) as the result.

[@foolishgruntigluana7041]

Thank you man really... I first solved it myself after learning from your previous parts and then checked by looking at your solution and got the exact right answer! I thank you from bottom of my heart. Solving such problems is a really big thing for me, even though I am 15 and should be able to it :( Btw subscribed to your channel!

[@stepbystepscience]

Great that you found the videos helpful. Thanks for the great comment and of course thank you for subscribing.

[@collegeguy1325]

signed up just to tell you that your explanation is amazing! If we could have professors like you teaching , engineering wouldn't be so tough to understand then! Thank you for taking your time and explaining this. Subbed!

[@stepbystepscience]

That is very nice of you to say. You can see a listing of all my videos at my website, www.stepbystepscience.com 2

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You're welcome and best wishes for your degree.

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Love this guys explanations

[@stepbystepscience]

Glad to hear it, thanks!

[@carterkessinger2023]

You are the absolute man. Thank you so much. God bless you.

[@jeanpierrevanderzandt8021]

I have an exam coming up and not to sure about all this. After watching this video it is making alot more sense to me now. I just don't understand where you state after I2 = 9.8 -3.2I2 it says 4.2I2 = 9.8. isn't it supposed to be 3.2I2 = 9.8?

[@gddoragasim6223]

I wouldn't to understand these laws if not for these videos , thanks !

[@stepbystepscience]

Thanks for that great comment, I spent a lot of time putting those videos together.

[@jharakesh61]

You explained well. Thank you sir

[@stepbystepscience]

You are welcome

[@VIPULSAINI1]

Thanks for being a great teacher

[@sniperkid389]

You are very simple, straight forward and only talks about what is on the screen. Not cluttered at all. Very easy to follow. Like the best one I've seen so far on youtube. I have a question though. I learnt this addition or subtraction way in class and sometimes for it, it's like simultaneous equations and sometimes for example replacing let's say, i1, as (i2+i3). It looks easy and sometimes i get it and other times not but i like your way better. Thumbs up.

[@stepbystepscience]

Great and thanks for the comment. I try to get right to the point. You came here for something and I try to give it to you in the most efficient way possible. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@Hduey]

omg thanks so much. after hours of searching on KZbin. this helped immensely.

[@stepbystepscience]

You are very welcome and thanks for taking the time to comment.

[@karimk8551]

nice and clear explanation. Thanks I2(unes)

[@lakshmiduvvuri6035]

Thanks so much for simplifying everything for us

[@stepbystepscience]

My pleasure! You can see a listing of all my videos at my website, www.stepbystepscience.com

[@ihabalbadr1910]

Nice teacher and very clear explanation.

[@stepbystepscience]

Thanks for saying so.

[@rayjasmantas9609]

Good description of circuit analysis.

[@stepbystepscience]

Thanks, took a while to put together.

[@chemist7908]

brilliant video so easy to understand its just perfect

[@karlsingh9076]

Loving the videos about Kirchoff's Laws.

[@nehahittoo6080]

Very helpful video. Thank you so much!

[@RobertoRodriguez-bl1xm]

excellent work on the explanation. I appreciate your step by step.

[@qisyaqistina944]

thank you so much sir, it helps me lot

[@stepbystepscience]

Glad to hear that, you're very welcome.

[@sanderdewilde8500]

thank you you saved me

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Glad to hear it, you're welcome!

[@Javianmadden]

Love these videos💯 learnt alot..thank you💯

[@stepbystepscience]

Great and thanks for commenting.

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Thank you so much. This has been troubling me for the whole week and I have finally found the video that as exploded my mind. Thank you again. Never subscribed to a channel this fast before. I can tell your videos will help me through this semester. Thumbs up for every video I watch for now on. Thanks again

[@jackyouo66]

It is really helpful !!!!

[@rajeshpayyanveetil]

Awesome Videos!! Great explanation. Thanks.

[@stepbystepscience]

Awesome comment, thanks and you are very welcome.

[@kanagarajpalanivel8271]

This very useful and neat explanation to students and teachers as well.please keep it up

[@lesegodiphofu3619]

you really helped me ....keep helping us

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New videos every week! Please subscribe.

[@anthonyschroeder3611]

at 9:38 solving for I2 when moving the equation to rearrange for I2, shouldnt it be 3.2 I2 = 9.8? therefore I2 = 3.06 amps?

[@hamoodbelushi2534]

makes it so simple to understand

[@GonzoRibeiro]

Very good video. Very helpful thank you and plz keep up the good work.

[@stepbystepscience]

Thanks for the comment.

[@johnjcb4690]

BEST MAN

[@stepbystepscience]

Thanks.

[@mihupolo]

excellent

[@stepbystepscience]

Thanks!

[@jeffersoneener9071]

Thank you so much...........understood very well sir.......

[@stepbystepscience]

Glad to hear that, you're very welcome!

[@MATTYROCKS1996]

Very good explanation, very easy to follow. thanks.

[@stepbystepscience]

+MATTYROCKS1996 You are very welcome, I try to go through everything step by step. In fact, You can link to all my videos at my website: www.stepbystepscience.com

[@nataliasmith6721]

wowee this was great!!!

[@stepbystepscience]

Thanks, glad you think so!

[@Mustafay3sil]

I watched another yt channel ı love physics but after two of your videos totally damaged. This channel is not for beginners. Anwyway thanks for helping and for your time.

[@stepbystepscience]

Keep watching, I have videos for beginners through university.

[@mr.brosio7915]

Super helpful, thank you!

[@lindombazima8401]

min 10:48 does that mean the answer is wrong when its always negative. I get that we chose the wrong direction.. but does that mean the answer is wrong because of the negative sign? If so, should we redo the calculation? just so to get a positive value???

[@stepbystepscience]

No it is not the wrong answer, it only means you choose the wrong direction for the current. The current is flowing in the opposite direction with the same magnitude.

[@eltayibyousif6349]

thankkkkkkkkkkkkkkkkks alot man finally i did it right

[@stepbystepscience]

Excellent and thanks for the comment.

[@nikolaynetsov6529]

I thing I2 must be equal -2.3A because we transfer 4.2 in the other side and It becomes -4.2. So we must divide 9.8/-4.2. Can you tell me where is my mistake? I understand almost everything except the math part. Could you also recommend me some video which will help me with that problem? Also why you chose to find I1 in loop1? Why we don't find I2 in loop1? Great video and you explain very well.

[@BINAYKUMAR-bs6ev]

Sir..how do we recognise that in a particular question we need to consider the outer loop as well?

[@everything_strength]

How do we know when to ignore a 3rd loop around the outside?

[@avanishmeedimale2618]

i watched this video series like 10 times considering how quick i forget things XD

[@stepbystepscience]

That is a lot of times, thanks for watching and commenting.

[@jonelbabano304]

Very conducive. Thank you.

[@lislehill3198]

Fantastic video! thank you so much!!!

[@stepbystepscience]

You are very welcome and thanks for commenting.

[@prabalsharma9199]

I finally understand this thank you!!!

[@stepbystepscience]

Great, you are very welcome and thanks for commenting.

[@jawariajaleel6972]

sir what if we take a full loop and a small loop? would that be wrong? because I tried to solve it that way and we have missing variables that way. is it the wromg way or just an inconvinient one?

[@stepbystepscience]

You can use any of the loop you want, you just have to have enough and the right ones to get the right number of equations and all of the variables.

[@jz2710]

Thanks

[@stepbystepscience]

You are very welcome.

[@sarahransomm]

THANK YOU!

[@stepbystepscience]

You are very welcome, thanks for commenting.

[@josegalvan1340]

You are great, man. Really appreciate the help!

[@medinecharyyeva9313]

how do we know which way to start the loop from? for L2 you started from N1 but then i started from N2. Is there a difference?

[@stepbystepscience]

It does not matter where you start.

[@letsgrow_together]

awesome video

[@stepbystepscience]

Thanks for the comment. You can see a listing of all my videos from my website, www.stepbystepscience.com

[@johnlloydmartinez135]

Thankyouuu thankyouuuuu

[@stepbystepscience]

You're very welcome 😊

[@takshaykumar6965]

Thanks you sir you are great

[@glendanightingale9232]

At 9.20 in example 2 you add 3.2 to both sides. How did you get 4.2 ?? would it not be 3.2?? where did the 1 come from. Thanks.

[@stepbystepscience]

Good question...on left side of the equation there is already I2 which is really 1I2...and 1I2 + 3.2I2 = 4.2I2. Does that help?

[@glendanightingale9232]

@@stepbystepscience many thanks for the simple explanation. I have forgotten my algebra 65yrs young starting to forget it seems.

[@glendanightingale9232]

@@stepbystepscience Understand many thanks.

[@elham1822]

Thank you so much. This helped a lot :)

[@stepbystepscience]

+Elham Mohammed Great, thanks for the comment. You can link to all my videos at my website: www.stepbystepscience.com

[@Matt-xn1cq]

I have a Kirchoff Problem that I am struggling to solve, if I send the problem to you could you help find the answer? It would be much appreciated!

[@manojkumarsubramaniam7122]

Thanks for the video bro It helps

[@stepbystepscience]

Thanks for the comment. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@MaxRollison]

Ahh ok. I was originally thinking the Voltage source would change like a resistor when going against the current. Hopefully I got it now

[@stepbystepscience]

Great

[@nickxd3776]

if we choose the wrong direction of the current does it mean we have wrong answer?

[@stepbystepscience]

No, but you will get a negative answer for the current. If get a negative answer for the current then you know you chose the wrong direction for the current.

[@HopeMaswanganyi-bz7fo]

So if the answers come out negative do i calculate again?

[@stepbystepscience]

If you talking about the current, no. A negative current means it is actually flowing in the opposite direct to what you choose when you set up thew loops.

[@Mike-vi2eo]

thank you this helped so much. However my professor required units on everything and i'm now have trouble with what the correct units would be i.e. when you solved for I1 and I2. Other than that great video.

[@Mike-vi2eo]

+Mike 1 nm i figured out unit thx for video

[@stepbystepscience]

+Mike 1 Current is measured in amps. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@rolderchenmasilang597]

on 9:53 have you notice that 3.21(i2) become 4.21(i2) on the other side. that means you got the wrong ampere reading

[@dolevdo]

no he is correct

[@stepbystepscience]

This is a basic algebra question....The equation is really 1I2 = 9.8 - 3.2I2, but we do not write 1I2 we just write I2. (just like when we write x - squared, we write x^2 not 1x^2. (Although you can write it either way). To solve the equation for I2, you have to add 3.2I2 to both sides of the equation. 3.2I2 + 1I2 = 4.2I2 and the equation becomes 4.2I2 = 9.8. Does that help?

[@deadspace4755]

What's the name of the required maths/algebra skills to correctly do the calculations/equations? l'm not native English speaker, just needed the name and then l can solve my problem. Thank you Also, if we find negative results and not change the direction, will it be considered correct in a test? Perhaps it depends on the one giving us the tests, so asking them would be recommended?

[@stepbystepscience]

Yes, asking them would be recommended, and probably if you are asked the direction of the current flow you should give the opposite direction if you get a negative result. Solving the equations you be algebra and maybe you would call it solving simultaneous equations by elimination.

[@deadspace4755]

Do you have Thevenin's theorem in your channel? l didn't quite find anything

[@stepbystepscience]

Sorry, but no.

[@fera5165]

Txs!

[@ligman9216]

+1 respect

[@nkelerasodi5382]

The nodes on the circuits, do they have to be where the circuit branches or they can be on the corner of the circuit

[@stepbystepscience]

Nodes are where wires come together, then can not be on the corners.

[@nkelerasodi5382]

Thanks a lot

[@Adrian-b7p5z]

What if I sub i2 with eq (i2=i1-i3) into the both loop eq? can it be solve with that way?

[@nikojames5085]

Why did you choose to find I1 in the L1 equation, why that rather then I2?

[@scorpion6828]

ty

[@akmalaqil587]

What if i assume the I3 the opposite way? I found out the calculation is different. Please help me!!😭

[@ramez2207]

How do you assume the direction of the current??

[@stepbystepscience]

Choose any direction.

[@RaginiStarmaker]

Hey your videos our awesome but i want to know that if our current comes neg. So it is correct na we have to only change the direction.... Suppose we have - 0.04 current so we have to change the sign only so our correct ans. Is +0.04..? Plz tell

[@stepbystepscience]

If the current comes out negative that means you chose the wrong direction for the current when you set up the problem for applying the voltage law. The current is flowing in the opposite direction.

[@ruelshakya15]

does to value of the negative current be equal to the value of current if we calculated it in the correct direction??

[@stepbystepscience]

yes.

[@belleluze]

I really enjoy the videos and I thank you for your time, but is there a way that you could slow down just a bit, you go through the exercises so fast it's hard to understand. Thanks

[@MadSk3eZ]

9:19 why and how can you add -3.2 I2 to I2 and it equals 4.2 I2 = 9.8?

[@toja2981]

hello,I don't understand why in L2 the V(45v) it's negative,can you explain it to me ,please ?

[@stepbystepscience]

When you go across a battery from the positive terminal to the negative terminal it is a voltage drop (negative), if you go in the other direction, form negative to positive, then it is a voltage gain (positive). Does that help?

[@toja2981]

yes,thank you very much ,you helped me a looot !!!