KMC-Sub Assistant Engineer(2nd December,2018) Answer Key || KMC Previous year paper

[@bapansardar3232]

Maam sab question gulo arakom vabe discuss kore dite sotti khub valo holo amader. Thank you.

[@Wish1993t]

Question30: answer=0.002 hobe bcz axial compressive strain=0.002 and outermost fibers 0.0035

[@dhirendranathhembram4888]

mam q no 22 easily solve with apply this formula E=2G(1+u) , then determine the value u and apply this formula E=3K(1-2u)

[@surajitpramanik6775]

Max proj. Of chajja is 600mm (q) 65

[@zafarabbas3406]

Full form of pvc is poly vinyl chloride 😀

[@Wish1993t]

Question55: refraction correction=0.01122d^2 Curvature correction=0.0785d^2 Combined correction=0.0673d^2

[@abhijitpaswan]

Please make a video on KMC 2000 JE question paper solution.

[@sumanpati2239]

Max projection of chaja as per NBR is 600mm not 500 mm

[@bishwarupkundu5646]

Question no 39 Why answer is 120 not 60

[@ipsitanandi1512]

Cos thita = -1/2 not 1/2

[@ordinarilyextraordinarymay9898]

55.no qus e cc ta vul bollen..ota combined correction er value.. r cc=0.0785d^2

[@dhirendranathhembram4888]

mam please solve 2020 ssc je solve paper

[@shashibhushankumar1631]

Maim interview me kon kon sa languages use kr skte hai

[@SmileLearnCivilEngineering]

Since it is a state exam.....so you will be asked bengali......in general

[@viralshorts7735]

hello mam . can you give me this question paper ? i went to pint this question paper .

[@SmileLearnCivilEngineering]

Its in our group

[@shubhadipghosh1434]

@@SmileLearnCivilEngineering in which group ma'am

[@polumurujitendraraju4293]

@@SmileLearnCivilEngineering which group ma'am reply me

[@SmileLearnCivilEngineering]

please watch the video till the end you will get all info

[@nirmalsarkar1625]

30 number question answer is d

[@monikachalki107]

Ai exam are cut off koto chilo jodi aktu bolen taholea khub valo hoi???

[@joycivil91]

Plz send this pdf link

[@msd1306]

2007 Soulation kmc

[@SmileLearnCivilEngineering]

Coming up soon

[@BITTURABBANI]

30-D

[@apanjantour6392]

13no qus ta bujlam na

[@ss_bongvlog.2087]

900 hoba

[@nirmalsarkar1625]

32 d

[@Wish1993t]

True bearing=azimuth when angel 180° So,right answer 269°30'-180°=89°30'

[@SmileLearnCivilEngineering]

Thank you for the valuable information...

[@dipalimaity2191]

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