Kotlin Newbie To Pro - LOGICAL AND COMPARISON OPERATORS - Part 8

[@derekkolb6324]

Commenting to support the page. I appreciate the way you explain the flow of things. In 24 hours, I have learned more about Kotlin from this playlist than I have in 2 weeks of my college course! I cannot wait to keep watching your playlists!

[@moyaalhayek3288]

I really liked the harder version of the homework, thank you!

[@userglls]

so do i

[@mformobileapps]

great tutorials😍...finally started Kotlin

[@ekafrancium]

The answer is True for both simple and hard expression.

[@carolinegatwiri2309]

Both Expressions give True value

[@seedgv]

Both True. Catching Up to your tutorials man.

[@marktilton8943]

Hard expression got me. But I assume it was true because False = False = False. Looking forward to the next lesson.

[@udaytewary3809]

Simple expression true because in the expression we have and operator which have more preference than or so that expression will be evaluated first and solving we get ans as true Hard expression ans is true because evaluating the all the bracket term after that we will evaluate all the remaining logical operators we will get ans as true

[@Luffy_2804]

thank you for this amazing course

[@shobhithjb4626]

Note: && Operator will not check the second expression if the first expression is false, because false && anything = false || Operator will not check the second expression if the first expression is true, because true || anything = true

[@christianzakhour4402]

This is true and important, for example: I have used a comparison where the second case could be null if the first is not true and the app should crash in other languages like c++

[@ananddangwal8424]

9:47 Answer is true and 9:53 Answer is true.

[@ironicdelta6097]

great work dude!!!

[@arnobhasan8930]

great tutorial video Its easy to sort length video Vary helpful.

[@salihdahi]

Thank you very much. Well explained m you saved much time

[@PeramVinodreddy-yx7vp]

U r seriously something

[@suntvhits]

Both True, True

[@h.venkateshdeveloper6997]

simpleExpression = true hardExpression = true

[@kseniyabuko]

Cool homework 🙂

[@linux2698]

thanks

[@jaychavan]

Both are true !

[@prasanjeetchakraborty8402]

simpleexpression =true hardexpression = true

[@MinhajIqbal-tt5tp]

True both

[@AndreWatkis-q8h]

The value of the simple Express is true whilst the value of the hard expression is also true. Here's my code: fun main() { val simpleExpression = 3 > 4 || 4 > 3 && 4 (x + y) && (!bool || y < z) println(hardExpression)

[@imanerbarta1]

Both are true

[@dionnecf]

Homework: simpleExpression = true hardExpression = true :-)

[@patilpatade]

explanation inorder to solve these type of question. remember will look into precedence of operators. if, precedence of operators are same then will see Associativity. simpleExpression: 3>4 || 4>3 && 4 and and

[@bhavikmehta4938]

Pro Tip: == is a compares the value, and === compares the memory address.

[@GraceTechnologies-x8d]

fun main() { val simpleExpression = 3 > 4 || 4 > 3 && 4 (x + y) && (!bool || y < z) println(hardExpression) } output: true false

[@DrFate_Channel]

simpleExpression = True hardExpression = False

[@MoonwalkerOfDreams]

false and true, did it without doing it

[@willianrodrigohuber7968]

I don't know it are the better answer, but was what i know do !(x != z) && bool || z > (x + y) && (!bool || y < z) at first moment i change all ocurrences for each variable for our respective value !(9 != 9) && true || 9 > (9 + 3) && (!true || 3 < 9) evalueted all comparison into the parenteses !(false) && true || 9 > (12) && (false || true) true && true || false && true evaluated the two operation and true || false rest just evaluated or comparison true