(L-30) Aldol Condensation || with Mechanism || Aldehyde ketones Chemical Rxn. || NEET JEE

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In this video, you will watch the Amazing Session about " (L-30) Aldol Condensation || with Mechanism || Aldehyde ketones Chemical Rxn. || NEET JEE". This session will be helpful for those students who preparing for neet aspirants.
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[@vedantuneet]

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[@laxmansinghnirwan8967]

Sir ap jo homework diya. Vo ker liya hai

[@studentofcollege]

Itna quality education to hame kahi par bhi nahi milta even no coaching centre will provide this . Arvind Arora sir to chemistry ke badshah he ❤️ jo sare bharat ku educate karna chahte he.thank u so much sir for your hardwork.

[@vishugamer5676]

Bhai coaching wala jayada nhi fek diya

[@KhushbooKumari-ji9ib]

@@vishugamer5676 😂😂😂

[@DivyanshuSaini23]

Lol😂

[@sisodiyamedicalcare1146]

Bohot badiya sir

[@studyshort289]

बस कर पगले रुलाएगा क्या

[@likhithshivaji5173]

Sir I got 58/60 in organic chemistry test of KCET exam. Thank you so much sir. All was possible only bcaz of u👍👍

[@ujjwalkumarsingh5216]

Are Bhai party de tbb

[@provatkumarbarman3938]

Congratulations

[@veenakalmat6547]

Wow congratulations

[@aabidakhan7567]

Congratulations 😃😃

[@shauncrasta]

Bro which books did u refer?

[@HarshKumar66743]

*Sir, what I like the most about your videos is that, it is short without compromising the major topics and basics...please keep this pattern in future also!👍*

[@vedantuneet]

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[@itzpkg]

4-Methyl Pent-3-en-2-one ..From Ketone by "Aldol condensation"

[@Honest_Penaldo_fan]

Mesityl oxide

[@itzpkg]

@@Honest_Penaldo_fan Hein ?

[@Honest_Penaldo_fan]

@@itzpkg what hein? I said the common name of the compound you wrote

[@itzpkg]

@@Honest_Penaldo_fan I was just kidding...dude Actually Mene 2 Sal phle comment Kiya tha....or 2 sal bad kisi ne reply Diya ... Kudos to your attention ‼️❤️

[@Honest_Penaldo_fan]

@@itzpkg Ok thanks 😂😂... You are appreciated

[@Fatimafaisal220]

You taught this wayy better than my PhD professor in university 😃 lots of respect from Pakistan 💚

[@varnitamishra9491]

We learn this in school 🤣🤣🤣🤣🤣,and our competition is way to high,this is considered as trash after JEE exams in college 1st there is whole different thing

[@Fatimafaisal220]

@@varnitamishra9491 hehe, we also have to learn this in high school but yeah I never did and always left this topic on choice but in uni's 1st semester, the first topic they taught us was this and I had no choice but to learn🥲🥲

[@varnitamishra9491]

@@Fatimafaisal220 we have no choice to leave any topic in pcm if we are serious jee aspirant

[@Fatimafaisal220]

@@varnitamishra9491 what's jee aspirant?

[@sakshamrai5872]

@@Fatimafaisal220 for Engineering

[@prajnamondal1579]

Sir ketone Wala ho gya ... Answer is 4-methyl pent-3-en-2-one #thank_u_sir

[@comradepeter87]

That is my answer too

[@kisanyadav4169]

Nice Sir Ketones Magic A Raha Hai

[@aaronrocque2912]

I got the same!!!

[@ameeshakushwaha9302]

Mera bhi 🥳

[@narenderkumar4732]

Same

[@bipinmaurya3824]

We are done in ketone form according to aldol condensation

[@LalitB_Official]

Have a look on this video too at kzbin.info/www/bejne/sGqUfIWKor2pb8k

[@MadhuKumari-dy6sl]

P

[@MadhuKumari-dy6sl]

P

[@AllAnimein]

Hi

[@rishavmondal2833]

Sir I am preparing for GPAT. .and prefer watching your description videos...I love the way you describe sir.....Huge respect....🙏

[@shahakrubab9609]

Superb method of teaching.... Love u sir

[@Uniquemotivator11]

4 hydroxy 4 methyl pentan2one. (Without heating) After heat:- 4 methyl pent3 en2one.

[@pranjalkumar6550]

(CH3)2-C=CH-C=OCH3

[@nishakushwaha8167]

Sir apka jitna sukhriyada karu utna kam hai ap soch nai sakte ap hum jaise gareeb bache jo coaching afford nai sakta unke liye ap kitne bade efforts de rahe hai thank you so much sir

[@daksh7717]

4-methyl pent 3-en 2-one😁😁

[@madhumaurya8025]

Finally sir mujhe aldol aa gya .... maine bahut teachers se smjhne ki kosis ki but .... but aap se behtrrr koi n smjhaye...apne pura concept hi clear kr diya...thanku sir sooo much🙏🙏🙏

[@amitrajput7019]

even after three year no one can beat sir in chemistry

[@shauryasingh9553]

change it 4 man

[@GghsbararaBarara]

Change it 5

[@kimv9292]

the ans for aldol condensation of acetons is ( 4-Methyl pent-3-ene-2-one)

[@chetnapiplani1904]

ya exactly 👍

[@shivoshitajhalta8061]

Same😊

[@tarakkumar6942]

Thankyou so much sir for putting ur immense efforts to teach us! You are the best chemistry teacher across youtube, you work very hard for us! Thankyou again~

[@studywithattitude7522]

#funny

[@mohitking7933]

Product is 4-Methyl pent-3-en-2-one.

[@eshnadutta1549]

Ketone wale hi Gaya sir. Aldol form is 4-hydroxy 4- methyl pentan-2-one. After condensation, it is 4-methyl pent-3 -en-2 one.

[@adityaraj9926]

Ncert

[@roshanisirmetasentarkahahm3357]

Bas galti nikalo

[@vishvas_rasekar]

Sir

[@kastubhkumar2515]

@@adityaraj9926 hmm

[@bintzubair]

Yes correct. Thanks for mentioning the answer. I was able to check mine. ☺

[@deweshsingh7914]

Thank you sir 🙏🙏👍👍🙏🙏👍😊😊👍

[@MayankKumar-sb8bq]

Thankyou so much sir and team

[@meeta_ramaiya]

Thank-you very much sir,👍👍👍

[@chetanbhagat8011]

4-hydroxy,4-methyl pentane-2-one

[@Chabda_Ngaojei]

The answer is Mesityl oxide.

[@nagparveen7553]

Sir it's ans is before condensation 4 hydroxy 4 methyl pent 2 one and after heating answer is 4 methyl pent 3en 2 one....

[@rupanzell7699]

Book se koi nhi bta dega

[@sigmastatus6379]

Sir my answer.......... 4-methylpent-3en-2one. (aldol condensation product)

[@freeridersk4674]

Thank you so much sir🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗

[@pinkeshmeena473]

4 methyl pent -3-en-2 -one

[@vaibhavaggarwal7803]

Sir the final product is 4-methyl pent 3-en-2one

[@pyuyadav4271]

Aap mechanism bhut deeply or ache se btate ho

[@utkarshmishra4199]

Thanks a lot sir I cracked iit because of you.

[@r.k.m.9720]

I have done sir and the answer is 4methylPent-3ene-2one. Thank you sir.

[@hanitadahiya813]

Yes sir ho gya... 4 methyl pent-3-en-2-one...

[@abhay.rijwani]

Answer of hw question Mesityl oxide or 4-Methylpent-3-en-2-one

[@bhupendrarajwade7583]

Ketone wala ho gya sir ji thank you so much

[@mohdhanief142]

Srr u r only one ☝whose teaching method is much better for us😍😍 Thankuu so much sr 🙏🙏may God bless uh srr🥰🥰🥰

[@mohdhanief142]

🥰🥰

[@arindombabu9844]

The ans is 4-methyl pent 3-en 2-one. Sry sir thora late Ho gaya. 😀😀

[@yushina8252]

Same..

[@muhammadali-gp4cg]

Same....

[@medicosnibbi4621]

Same to you

[@cindrelladolly3823]

yeah same😊😊

[@krishnakriparadhekripa5708]

same

[@munazzahusnain1331]

Wow very nice method of teaching love u sir 😊❤

[@mushrratfarooqui5153]

Thank you so much sir board pr smjhane k ly 🙏 ..ap best ho sir🙏❤️

[@kapishjain9262]

Answer of hw is 4 methyl pent 3-en 2 one

[@jayrajsuthar8139]

Sir Ketone wala ho gaya. Sir Andol- 4-hydroxy,4-methyl pentan-2-one. And, After Condensation it becomes 4-methyl pent-3-ene-2-one. Sir Ek question h, Condensation k baad Jo product bana kya hum usko generally Enone bol sakte h.

[@alihasrat4720]

aap too real guru ji ho

[@kiran9222]

This is just awesomee ❤️❤️❤️

[@Bhababu143]

sir ketone ke bhi ho gaya 😊😊 apne itne ache se pyar se padhaye h toh samaj me aa gaya....Mahadev Aap ko lambi umar de🙏🙏🙏🙏🙏🙏

[@Drparulkardam]

Thankyou so much sir ❣️

[@SagarSingh-jq4ue]

For acetone,,,,,,,,4-methyl pent-3-en-2-one ..........

[@MayankKumar-sb8bq]

Answer 4-methylpent-3-en-2-one

[@gaurichaudhary2873]

Ketone -4-methyl pent-3ene-2one

[@princenagar1686]

(CH3)2-C=CH-CO-CH3

[@Crazy_Gamer4855.]

Misityl oxide

[@princenagar1686]

@@Crazy_Gamer4855. Now these things don't matter to me, moving forward with coding

[@deepalisinghal8571]

Answer for aldol condensation while using ketone is 4-methyl pent 3-ene 2-anl

[@peeyooshchauchan4441]

Experience is the best teacher sir...👌

[@SimrnHh]

Boht acha samjhaya😊

[@misbahhussain1021]

Sir g u r great I slove all bsc questions because of ure good lecture

[@riteshagrahari7963]

bahut aache se samjhaye sir

[@c.cykosstar]

outstanding brother!Thank you soo much

[@fasiu.9018]

Hello sir, i m from pakistan.really in love with ur concepts.all my conceps are covered ur amazing.Love from Pakistan💚💚💚

[@beactive4443]

Thanks for accepting that indians r far better than Pakistanis in every respect 😂

[@notbad9071]

Thank you🌹🌹🌹

[@Vishal-uy8rf]

You are great sir

[@pratikbhoir365]

Thank u sir Now its easy😀

[@manigoel79]

Ketone waala ho gya pretty much easy🖤

[@rohitpandit8690]

Thank you madejee team for their support to coaching free india

[@좋아해방탄소년단]

I did my homework sr it was quite simple 😊😊😊

[@mansi2500]

ARMY 💜

[@drshubhamsinghbasti8713]

Good presentation sir

[@richasharma864]

Thanks sir it really works. Now i am able to work out the questions. Well explained.

[@kumariindu1200]

Done sir answer is -4-methy pent-3-en-2-one.

[@manoharkumarsharma5755]

Sir aapki short tricks and mechanism fast samaj me aata h

[@saliqkhan3525]

Love you sir 😍 your way of explaining is too good

[@LalitB_Official]

Have a look on this video too at kzbin.info/www/bejne/sGqUfIWKor2pb8k

[@naveendongre6180]

SIR Ketone wala ho gaya.. ans.: 4-METHYLPENT-3-EN-2-ONE... *THANK YOU SO MUCH SIR😀😀😀😀😀😀😀😀😀😀🤗🤗🤗🤗🤗😊😊😊😊😊😀😀😀😀😀😀😀😀😀*

[@kumaradityamamc6262]

Apki Saran me aa ke chemistry badiya hogai ketone wala ho gya 💯💯💯💯

[@EVILHYDRA]

Sir thank u ans is 4methyl pent-3en-2one

[@deepbanerjee5900]

Loss of hydrogen from alpha position during the loss of water leads to formation of conjugated double bonds which the second reason why hydrogen is released from alpha carbon....nice lecture by the way👍

[@rachitdwivedi6774]

Sir question ho gya 👌 🙏Thanks for the effort you make on us, sir

[@DeepakKumar-sf3tu]

Hey bro can you explain the in dilute naoh is present you know I understand that in naoh oh- is gone for formation of bonding then where is na???

[@futuredoctor1268]

​@@DeepakKumar-sf3tuin solution with water

[@futuredoctor1268]

​@@DeepakKumar-sf3tuNaOh was base it work was till it gives OH ion not Na

[@mussaratsiddiqui7574]

Check kar liya sir owsum 😆😃

[@rohinpathan6379]

Thank you made e jee team and thanks a lot sir 👍🏻

[@raambanjaria8203]

🔴आपसे अच्छी केमिस्ट्री अन्य कोई नहीं पढ़ा सकता। 👍☝️😘👏💝 ..........Thank you so much dear sir ji 🙏 Love you.

[@NamanPrajapati-t8e]

aldol condensation of ketone : 4methyl pent3-en-2one

[@mackychhabra3782]

Sir u r so nyc Sir can u upload the vedio on the basis of intramoleculer aldol condensation

[@shaliniverma187]

adol 4hydroxy 4methyl pent-2-one after heat 4methyl pent 3-en -2one

[@zebapraveen9309]

Sah8 hai

[@almasmujawar3091]

Thank you soo much sir u explained the best nd I was very confused with aldol condensation bt after watching ur video all confusion is gone THANKS AGAIN😀

[@warishaansari4044]

Thank you so much sir and all made jee team

[@sirvilive2935]

Completed.. Thankyou so much Sir

[@sageerahamad.9320]

You are really a great teacher. You grab our attention very fast. We don't get bore for a single minute during your videos. Keep it up.☺️👍

[@shriyachouhan1716]

Thank u sir for clearing the concept 😊😊

[@pravallikagoudke2743]

Sir I got 4-methyl pent-3-en-2-one & thank you so much sir 🙂👍

[@atharvakankale3700]

Thank you so much sir really lub you 💖⭐

[@navaneeth_us]

Sir can you do a video on Latimer diagram. The question related to it had been asked in NEET 2018

[@mukundprajapati4041]

nice sir thanks for naming aldol

[@Jarasandhsingh]

I cleared my homework and I am waiting for your next interesting video cross aldol.

[@riddhinandwana9510]

Sir ans nhi aaya

[@shreyaraghoji7814]

FOR KETONE PRODUCT IS 4 methyl pent-3 en -2 one

[@prakharsonisoni4102]

Sir ketone wala ho gya Answer is 4 Hydroxy- 4 methyl pentenon 2

[@ravirai8433]

Good trick sirji........ Thank you sir

[@bhaktaranjansahoo560]

Ans. 4-hydroxy -4-4methyl pentan- 2 one . ... After heat to give :- 4-hydroxy-4-4methyl pent-3- en- 2 one

[@Un_Tech]

Ketone product=4-methyl pent-3-en-2-one

[@ashishgupta7603]

Sir ..I got instant motivated when I see u and your hard work...thanku sir for this

[@HarshvardhanVyas]

your every lecture I understand

[@masoomsoni7892]

thanku so much sir .......nd whole madeejee family...... nd gooood mrng to u sir...

[@kingjj9]

Well explained!

[@Black.c0123]

sir ketone wala ho gaya 4Hydroxy-4methyl-pentan-2-one after condensation(∆) 4Methyl-pent-3-en-2-one