L'hospital's Rule Indeterminate Forms, Limits at Infinity, Ln, Trig & Exponential Functions Calculus

[@TheOrganicChemistryTutor]

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[@habeebahmustapha2623]

who else calls this L hospitals rule and not lospitals rule

[@ChampChamp000]

I leave it fancy and say lopital's law , if something works properly don't touch it

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[@Timmy16-]

25:37, he made a mistake by saying that cos 0 is -1 but it's simply 1 and the fraction would then be 0/0 which allows us to use L'hôpital's Rule

[@bonamonisandeepkumar3650]

π=180,so Cos(180-0)=-cos(0)=-1

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[@theapexpredator157]

Isn't it L'Hôpital's rule and not Hospital?

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Thanks for this video. It has served as a good review of L'Hospital's / L'Hôpital's Rule.

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[@asoup1972]

The example at 35:02 really helped me out. Thanks!

[@Earlx3n]

I pray you see this... Since f.g= f/1/g How do i know which function is Which?? Like is there a specific Way to substitute them; its really confusing cause i always get the wrong answer if i sub them the other round Please helpp

[@jovyjay670]

Thank you best teacher, I'm kindly requesting for help on this number Lim Xtends to 1 ((1/lnx)-(1/(x-1)))

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[@nis3232]

Auto correct corrects "hopital" as hospital, actually it is "l'hopital" rule

[@iamxanderdiaz]

At 18:57 the answer should be negative infinity not infinity. The derivative of -x^3 is -3x^2.

[@cayanlamanna]

19:58 why isn’t the nominator = 0? Wouldn’t it be infinity - infinity?

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Need a video for complex numbers

[@TheTeaBag97]

I think there is a mistake at 18:48 you did the rule 3 times instead of 2 . thank you very much you are the best .

[@JensenPlaysMC]

you can do it as many times until you find the correct answer

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[@rupamsaikiah2579]

Thanks 🙏 sir your expelation is so helpful for me

[@kalamanivelliangiri7977]

hey...how do you choose among the two terms to make one of them as the denominator to fulfill the f(x)/g(x) condition?

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[@ley90]

in the xlnx part, u said f·g = f/1/g , i assume f=x and g=lnx. then it should be x/1/lnx not lnx/1/x.

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Thank you so much for this amazing video!

[@youssufamr8140]

I think the answer at 55:30 is 4. Because after multiplying 1/x we should multiple the (+1) too . Which will make it (+1/×) . I tried to make sure by solving it in another way and it came 4. But at the end . Thank you so god damn much . Calculas would be hell without you . Every quiz or mid term I come to you

[@JensenPlaysMC]

nope, you cannot just multiply by 1/x this would change the entire question. if you multiplies 1/x on the numerator aswell, that would be fine

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Thank u so much for making this excellent video!

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thank you so much sir .....(i like your vedio very much)

[@jesussaquin6266]

For 13:20 you can also use the squeeze theorem

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Damn...better than my lectures 😂

[@hasanaldhubaibi3590]

your explanation is really good, but there's still one thing. In the exam I am having a month later, the calculators are not allowed in the exam, so is there's another way to find the result of Ln and the cos and sin which are not famous without the calculator.

[@Alex-kd4vo]

18:33 what happens if we do it again to just get 6? Why doesn't that work?

[@maryamojodu880]

You can't find the derivative again because that would be using L'Hopital's rule again. And L'Hopital's rule is only applicable for 0/0 and ♾️/ ♾️

[@MathCuriousity]

QUESTION: Toward the end he solves limits by creating equations equal to y. Why is he allowed to do this? It feels “wrong”

[@ahmackalak7553]

I have a quick question :) At 45:31, why can you use L'Hopital's rule when you still have an infinity - infinity case in the numerator?

[@kgshbteambeasto_o963]

My answer would be that since we know x >> ln(x) as x -> infinity. x is much bigger than ln(x) so x^2 - ln(x)^2 will still -> infinity, so it is a infinity/infinity case.

[@JensenPlaysMC]

@@kgshbteambeasto_o963 if you assume that he couldve just said that at the start and then just write the answer to begin with

[@shintori23]

38:00 how did the negative sign go infront of the e^-x after?

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You saved my life!

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[@andrejzlatevski4290]

Thank you for helping me , cheers dude : )

[@Sneaky1ne]

You can also do lim a = e^( ln (lim a) ) and work from there, it's faster for me.

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What do you do when x is the exponent

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[@kevinfrancisquete7884]

Lim {x - lnx} @x approaches to infinity = Lim 1 - 1/x @x approaches to infinity = 1 - 1/infinity = 1 - 0 = 1

[@omarahmad7368]

if you don't might, what is your calculator type?

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Thanq so much sir.... its help me alot

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يعطيك العافية ياعسل

[@nabarajbaral2063]

What must be added to the polynomial x^3-4x^2+x+2 to make it x^2-x+4?

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sir can you upload a video on Taylor and maclaurin series????

[@shrinidhic3715]

THANK YOU SOOO MUCH!!!!!!!!!!!!!!!!!!!!!!!!!

[@hamzajashari]

57:32 use lim (1+1/x)^(x) = e i think is more simple for understanding, if u wanna explain L Hospital's u right ...................x->~

[@ta4504]

Isn't one raised to the infinity one?