L8 - Equivalent Circuit of a Transformer

[@eepower]

What a great teacher!. Your time and effort is really appreciated. I am studying to become a PE and your knowledge and lecture helped me greatly. You are a good man. God bless you. Thank you.

[@sibonelomthunzi7089]

Im from South Africa doing n5 and i just had to come here to learn

[@Cucumberick]

Shouldn’t be Zt on Ex-29 be multiplied by k^2 for the secondary side of the transformer?

[@atmsc4nd4l]

why is that when i solve this, the voltage is slightly off to the other equivalent circuit? so it means that this is not accurate?

[@niki-maria]

isnt V1/V2 = k? thus also meaning E1/E2=k? 3:37

[@kora2511]

Yeap and k=I2/I1=N1/N2 also

[@amitkumarkharwar7655]

Only in case of ideal transformer

[@joenathanshepherd8666]

At second sum,since inductor current lags by 90degree of minus will come then the ans is -0.8j you have mentioned as +0.8j

[@jordanw4798]

How is R1 and X1 worked out?

[@pradeepyemula6015]

for the question in this video, the values of R1 and X1 are given. Otherwise, R1 and X1 can be determined by performing a short circuit (SC) test on the transformer.

[@jordanw4798]

@@pradeepyemula6015 so when you perform a shirt circuit test, what equation would be used to determine them?

[@pradeepyemula6015]

@@jordanw4798 see 9th video in my playlist titled “AC Transformers”

[@pradeepyemula6015]

kzbin.info/aero/PL-uxPiMl0_6FPrEBGS4EwFBK5WMosImyq

[@jordanw4798]

@@pradeepyemula6015 sorry, im probably just confusing myself. Ive watched that video a few times. Do you label R1 and X1 as something else?

[@zeinselzer2897]

thanks, you make it simple and easy to understand. good job!

[@pranaymondal1950]

very gooooooooooooood

[@kadirbekmezcioglu2647]

how can we change the naught resistance and naught inductor's side

[@Hafijurrahman-ut5dh]

thank you very much.

[@sohailjanjua123]

Hi Paradeep, I like your lecture

[@jazminromo1618]

Great video. I have a question though. Why wouldn't the copper losses be = (I2')^2 * (R1 +R2')?

[@koenabennedict6189]

Your formulas are incorrect. Therefore also the calculations are wrong.

[@aykutkaraman5127]

thanks but ı think somethings were wrong. explain : we have 0.5+i. I=56.25 ph-36.87 A. how is possible Voltage is 56.25? I found 62.88 ph 25.66 V.

[@sbk4723]

Sir do it for facts devices

[@markosmeskele2810]

thank u

[@matthewhauser9225]

cmon man

[@abdulrashidabubakar3673]

Thank you

[@abdulrashidabubakar3673]

K=E2/E1, not E1/E2

[@tejeshteja5699]

Very neglect

[@anirudhakulkarni945]

negative

[@assamesetrader9]

Worst