Sir your deduction was incorrect in 3rd question 9:53 timestamp in your video.. When you reached the state x((x^2) + 4) = 0, you should have gone for this "One of the solution of x is x=0 from the above statement" but we assumed that 'negation of q' is true i.e. x not equal 0 So we now have contradiction. Why your deduction was incorrect ==> X belongs to real number (R) and Real Number = rational number + irrational Numbers And our assumption was 'Negation q is true' i.e. x not equal 0. therefore X can have any real number value except 0 x=+2i OR x=-2i holds TRUE
@monalisakushwaha56735 жыл бұрын
Excellent 🐸
@karthiksukumaran854 жыл бұрын
But real numbers can not have imaginery numbers.
@theprincetilak2611 Жыл бұрын
GREAT EXPLANATION 🙌 I APPRECIATE YOUR HARDWORK
@story_time_bd25124 жыл бұрын
Sir, proof by case and proof by equivalance. Which one is direct amd which one is indirect?? Please reply sir.
@Mbediting799 ай бұрын
Great sir 👍
@AhamedKabeer-wn1jb5 жыл бұрын
Well explained Sir..
@farzanayeasminsumana60453 жыл бұрын
Very good explanation
@harshitpal8614 жыл бұрын
In last question, in last step We can also get x=0 and hence the contradiction is proved ..?🤔
@Shubham-hk6yf3 жыл бұрын
Ya bro both ways
@TamimXplore2 жыл бұрын
it's really helpful!!!
@SoumyaRanjan-w5jАй бұрын
But -4 is a real number
@rosewhiteboard73914 жыл бұрын
I am thankful for this it helps me
@Bikash01233 жыл бұрын
Thank you sir
@anandchauhan21795 жыл бұрын
Sir please contradiction pe ek aur video banao please help
@mariyamamreen4393 жыл бұрын
Auesome sir 🌺
@shshvb4 жыл бұрын
Sir what is the meaning of not of q........plzz elaborate
@GoogleRalCoderHUB9905 Жыл бұрын
Not q of contradiction meaning
@shshvb Жыл бұрын
@@GoogleRalCoderHUB9905 subscribe my channel
@alphagaming5432 Жыл бұрын
mamu @@GoogleRalCoderHUB9905
@kalashchourasiya37104 жыл бұрын
Nice writing sir
@baleshwarsah56912 жыл бұрын
Sir kis condition me contradiction method use karte hai
@sadakagaja3 жыл бұрын
Tq sir
@muhammadsaqlian39203 жыл бұрын
How true contradiction
@ihteshamshah4897 Жыл бұрын
First example k end py he said not of Q is false but it is true😑 If I'm not wrong
@fatimayaseen4057 Жыл бұрын
Yess.... another channel has also solved the same question with the same method . And they are totally confusing my mind!!
@ihteshamshah4897 Жыл бұрын
@@fatimayaseen4057 myn to ab paper dy ai pta nai kia tha kia nai🙂
@fatimayaseen4057 Жыл бұрын
😂 that's also good
@ihteshamshah4897 Жыл бұрын
@@fatimayaseen4057 dua kijiye ga Result acha ay
@badrinath21811 ай бұрын
In first qstn he took (not of q)= even which means by putting an even number in 3n+2 , it should result to an odd number.....but after solving it by placing even number(i.e 2k) in place of n in 3n+2 it came out to be even and hence this is a contradiction
@keerthiammu62932 жыл бұрын
Thank you sir ❤🌼
@meditationmanifestationmus61553 жыл бұрын
Sir isme q false h kuki n to even proof ho gya
@andistheinforitbutso75136 жыл бұрын
Hahaha head spinning contradiction
@andistheinforitbutso75136 жыл бұрын
U r human proof: Assume that u r not human. Since u r human, You cannot b not human, i.e., u r human.
@Durgaprasad_Nayak2 жыл бұрын
Hn 😅
@imtiyazbashir81453 жыл бұрын
-4 is real number ....real numbers encompasses all other numbers rational... irrational..integers and so on. Square of any real numbers CAN NEVER BE negative ..is the contradiction Plz do correct me if I am wrong