Lagrange Error Bound

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MeteaCalcTutorials

MeteaCalcTutorials

Күн бұрын

Learn how to use Lagrange Error Bound and to apply it so that you can get a 5 on the AP Calculus Exam.

Пікірлер: 67
@oscarortega4422
@oscarortega4422 8 жыл бұрын
the taylor series for sin(x) to the third degree is x - (x^3/3!) not just x- (x^3/3)
@simonstead93
@simonstead93 9 жыл бұрын
Your handwriting is absolutely fine, and you don't write anything down that you don't say out loud. Props!
@JaganDoodala
@JaganDoodala 10 жыл бұрын
This was excellently explained, and the video was incredibly precise! Thank you so much for your time!!!
@boystoys5000
@boystoys5000 9 жыл бұрын
Jagan Doodala That was the most constructive comment ive heard
@geografixxxx
@geografixxxx 6 ай бұрын
@@boystoys5000 It was an encouragin comment.
@MissBookGoddess
@MissBookGoddess 9 жыл бұрын
bless you and your firstborn child
@jaredrice354
@jaredrice354 7 жыл бұрын
Norbu Tsering he's on his own
@adityabhardwaj3495
@adityabhardwaj3495 3 жыл бұрын
@@jaredrice354 Sad
@geografixxxx
@geografixxxx 6 ай бұрын
@@adityabhardwaj3495 Happy
@jextejt
@jextejt 11 жыл бұрын
Just a quick note about the 3rd degree Taylor Polynomial for sin(x) should be x - (x^3/3!) or x - (x^3/6). A small error here, but it might be of concern to a student just starting out with these sorts of things.
@onice331
@onice331 11 жыл бұрын
the confusion that i have dealt with for the last week finally makes sense! thank you so much!
@stellaveazey8988
@stellaveazey8988 11 жыл бұрын
thank you so much! figuring this out has been very frustrating, but you explained it very well.
@only20frickinletters
@only20frickinletters 9 жыл бұрын
"Learn how to use Lagrange Error Bound and to apply it so that you can get a 5 on the AP Calculus Exam." Darn! I wanted to learn about Taylor polynomials because they will be useful in life! /sarcasm
@only20frickinletters
@only20frickinletters 9 жыл бұрын
gl on y'all's APs!
@mattg4531
@mattg4531 4 жыл бұрын
Norbu Tsering they were in the past. Nowadays we have calculators to evaluate elementary functions.
@DevinGagnon
@DevinGagnon Жыл бұрын
This is the best I have ever heard it explained, thanks so much.
@AlexSchendel
@AlexSchendel 9 жыл бұрын
Thanks! I finally understand how to use the formula I wrote down :)
@alexluwees3484
@alexluwees3484 3 жыл бұрын
How do you find the x that maximizes that function ? What if for example you had the 4th polyn of sinx , that means that 5th power of sinx would be cosx.. Then your max value would be 0 since (sin0 = 1). but "a" would be also zero, so now you have cos(0)/6! * (0-0) which is zero. What am I doing wrong ?
@b-e5619
@b-e5619 Жыл бұрын
The thing is that you don’t have 4th degree of sin(x). I think we just assume they will provide us odd numbers for sine and even for cosine. It also boggles my mind.
@pixelmine2
@pixelmine2 4 ай бұрын
Watching this day of the exam because i suck at this 👊❤ tysm
@ramka5861
@ramka5861 3 жыл бұрын
How to find out sin(0.1)? Is 0.1 in degrees or radians?? Please explain.
@DynamicRoulett
@DynamicRoulett 7 жыл бұрын
it may sound dumb but how come sin x is maximized when x is 0.1?
@leoz4651
@leoz4651 9 жыл бұрын
Good video, quick correction, the third degree for sin in taylor has a factorial in the denominator, no big deal, thank you again
@MakExITxHaPpEN15
@MakExITxHaPpEN15 10 жыл бұрын
Thanks this made everything clearer!!!
@arunvenkit5373
@arunvenkit5373 2 жыл бұрын
Thanks so much, this helped like crazy!!!
@trm3177
@trm3177 4 жыл бұрын
In books and other explanations I've seen they max sin t=1... not sin (0.1) ignoring the interval [0,0.1]. I think your explanation makes more sense but who is correct?
@poetic5604
@poetic5604 10 күн бұрын
Pretty sure it's gotta be sin(0.1), as we have to maximise sin(x) for interval x belonging to [0,0.1], and since sin(x) is an increasing function from [0,Pi/2], it is safe to say that in order to maximise sin(x), we have to input x=0.1
@pikachuincorporated8483
@pikachuincorporated8483 6 жыл бұрын
Excellent explanation.
@cowgoesmoo2
@cowgoesmoo2 9 жыл бұрын
Awesome video, nice and short.
@vinayA-h9k
@vinayA-h9k 8 күн бұрын
thanks a lot man
@beatleplayer1011
@beatleplayer1011 8 жыл бұрын
Thanks for clearing it up :)
@evanalmonte6162
@evanalmonte6162 10 жыл бұрын
My question is, Would the error be greatest at x=.1 since the Taylor polynomial is centered around 0?
@corks8807
@corks8807 9 жыл бұрын
Evan Almonte i think thats what he said.
@dominatemath
@dominatemath 11 жыл бұрын
Very helpful. Thanks.
@leowang2972
@leowang2972 11 жыл бұрын
The best way to cram before the exam
@XaviShaw
@XaviShaw 11 жыл бұрын
Very good!
@squidwardonachair6894
@squidwardonachair6894 6 жыл бұрын
thank you kind sir
@Kamadaytrades
@Kamadaytrades 11 жыл бұрын
Helped me out thanks
@leowang2972
@leowang2972 11 жыл бұрын
Thanks. I like it
@minlu8547
@minlu8547 7 жыл бұрын
Thank you!!!!:)
@MrRenanwill
@MrRenanwill 8 жыл бұрын
Lagrange Polynomial is not the Taylor Polynomial. Change the name of the title (and description) to "Taylor error bound" or something like this.
@BondedSeven
@BondedSeven 6 жыл бұрын
How did you know a = 0
@philn7457
@philn7457 5 жыл бұрын
He stated that the polynomial is centered at 0. "a" represents the value where the poly. is centered.
@kevinhu6961
@kevinhu6961 3 жыл бұрын
Where did he get (0.1) for the last step?
@aldenmoran9823
@aldenmoran9823 3 жыл бұрын
fr
@FireSymphoney
@FireSymphoney 7 жыл бұрын
blessedness in the air
@龙雨-i6o
@龙雨-i6o 5 жыл бұрын
thanks.
@johannsebastianbach3411
@johannsebastianbach3411 8 жыл бұрын
You da man!!
@Watermeba
@Watermeba 10 жыл бұрын
take my math test for me plz
@jisidro4
@jisidro4 8 жыл бұрын
He sounds like Michio Kaku!
@DennisBolanos
@DennisBolanos 2 жыл бұрын
You're funny.
@jacksontet
@jacksontet 6 ай бұрын
this is just wrong, it should be sin(c) not sin(x) making it all jsut 0
@turtleomnom2673
@turtleomnom2673 4 ай бұрын
bruh it was that easy
@jadenyuki7001
@jadenyuki7001 11 жыл бұрын
he probably meant 3!
@jiwonha2517
@jiwonha2517 7 жыл бұрын
? shouldn't it be -(x^3)/3!
@viruskiller18
@viruskiller18 10 жыл бұрын
cant hear a thing :O
@g00gleh00
@g00gleh00 11 жыл бұрын
Look at dat profile pic. Roonescape i see!
@BattleslashX
@BattleslashX 11 жыл бұрын
Look at that increase in view count.
@supagartx2
@supagartx2 9 жыл бұрын
i'm sure it was a great video, but i couldn't get past the first minute because i couldn't read your handwriting!
@aldenmoran9823
@aldenmoran9823 3 жыл бұрын
thats on u lmao. wait hold up u already graduated college thats wild. u probably wrote this while u were in highschool 2.
@azaz8398
@azaz8398 5 жыл бұрын
and i thought my writing is bad.... no offence
@pkrishnasuresh
@pkrishnasuresh 3 жыл бұрын
Great explanation
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