Laravel Advanced - Has Many Through Relationship

  Рет қаралды 7,152

Laratips

Laratips

Күн бұрын

Пікірлер: 27
@raya8540
@raya8540 2 жыл бұрын
Thank you very much! It is very helpful, hope you always have a great day! Thanks thanks thanks
@Laratips
@Laratips 2 жыл бұрын
Thank you 🙂
@bizhanhejazi8174
@bizhanhejazi8174 3 жыл бұрын
This video is the best I could ever imagined of.
@Laratips
@Laratips 3 жыл бұрын
Thank you 🙂
@davidsonzed
@davidsonzed 2 жыл бұрын
Thank you so much, this is extremely helpful and informative. I really really liked your videos and teaching techniques. This channel is one of the best on KZbin. 🙂
@Laratips
@Laratips 2 жыл бұрын
🙏🤘
@pyongits
@pyongits 4 жыл бұрын
Can you make videos about complex queries in Laravel, both eloquent and query builder a comparison of them? And using closures in queries like the use of anonymous functions.
@Laratips
@Laratips 4 жыл бұрын
Thank you for the idea. I will note this and make a video dedicated to it in the future.
@kvanca2330
@kvanca2330 3 жыл бұрын
Thank you for video. Can we use this more than 3 tables?
@mmsskk1413
@mmsskk1413 3 жыл бұрын
As always thank You.
@Laratips
@Laratips 3 жыл бұрын
No worries!
@leonvanrijswijk8409
@leonvanrijswijk8409 4 жыл бұрын
Thanks, I learned new things
@Laratips
@Laratips 4 жыл бұрын
Glad to hear that. Please share so that other would also know what you have learned and they could also learn some new things 🙂
@deepakagarwal663
@deepakagarwal663 2 жыл бұрын
I have three tables namely: category, subcategory, and services respectively. Now I want relationships between these tables as a category has many subcategories, then each subcategory has many services. so can you help me how to resolve such type of relations for this scenario
@Laratips
@Laratips 2 жыл бұрын
I guess that you are trying to directly get the services from the category. In that case you can do it like this. Make sure there is 'category_id' column in sub_categories table and 'sub_category_id' column in services table. class Category extends Model { /** * Get all of the deployments for the project. */ public function deployments() { return $this->hasManyThrough(Service::class, SubCategory::class); } }
@phenixbd
@phenixbd 2 жыл бұрын
Awesome !!!!!
@Laratips
@Laratips 2 жыл бұрын
Thank you! Cheers!
@ajaykj8925
@ajaykj8925 2 жыл бұрын
i need to fetch users with all posts and active posts in separate , so i have a post function in my user model. is that possible to call post inside with () in laravel ? like user ::with('posts')->with('posts'=>fun (qry){ qry-> where('isactive',1)}) ... It returns only one posts , so is there any other options ? Or do i need to create another function for active posts in my model ??
@Laratips
@Laratips 2 жыл бұрын
The syntax that you are using is not supported yet. For that you need to create another relationship method named "activePosts" and use it like this: In the User model, public function posts() { return $this->hasMany(Post::class); } public function activePosts() { return $this->posts()->where('isactive', 1); } Then you can access it like this: User::with(["posts", "activePosts"])->get(); If you do it like this, then it will be reusable.
@ajaykj8925
@ajaykj8925 2 жыл бұрын
@@Laratips ❤️✌️
@sportsandstudy6985
@sportsandstudy6985 2 жыл бұрын
How can i show users in blade please reply
@Laratips
@Laratips 2 жыл бұрын
You can make belongs to relationships in posts and get user from that
@sportsandstudy6985
@sportsandstudy6985 2 жыл бұрын
@@Laratips please explain i am new to relationship so if you can explain i will be thakfull
@Laratips
@Laratips 2 жыл бұрын
I already have video on all the relationship in laravel. You can check my channel
@sportsandstudy6985
@sportsandstudy6985 2 жыл бұрын
@@Laratips i am following your channel
@LaravelRo
@LaravelRo 3 жыл бұрын
Thank you for this amazing tutorials! I would like to ask you to make an advanced tutorial with grouping records with goupBy clause. Specificaly how to create a list with articles grouped by year, by month, by week - ierarchicaly. Best regards!
@Laratips
@Laratips 3 жыл бұрын
Thanks for the video idea. I will definitely make one
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