Thank you for review. I have to apologize for the code was not working, (migrations issue) and the readme files. I didn't mean any disrespect. I forgot on these important things. My fault.
@guilhermemoraes40553 жыл бұрын
Is your code anywhere in GitHub? I'd like to clone it
@guilhermemoraes40553 жыл бұрын
In my opinion, this kind of video are the best for junior level developers, like me, to learn from others mistakes. Thank you.
@abusayeedshakil97743 жыл бұрын
Please make more of these code reviews because it offers many things to learn at once especially how we should do things. Thank you.
@RasceGSalasG3 жыл бұрын
I love the code reviews , I always learn a lot , thank you
@brandon_ab1233 жыл бұрын
Please keep doing the junior code reviews. Helps a ton!
@MuhammadHaseeb43 жыл бұрын
After watching all the review code series I feel like i am a junior developer even with few years experience :D. Its more effective way to learn indeed. Thank you for making these efforts. appreciate that.
@merdmann2 жыл бұрын
These videos are great because it helps enforce standards in coding and shows new devs the standards that they themselves may not be aware of
@binodthakur6963 жыл бұрын
We learners are really feeling blessed to learn daily from you - god bless you.By your laravel tips,series and junior code review i have learned and still being exited watches your every video.
@joshuafomubod82163 жыл бұрын
This is great, I love this kind off video to see how others think or approach things help me see things from different angle
@armentorosyan82683 жыл бұрын
Thanks for the video! Feeling myself much more confident as a Laravel beginner!
@kareemlateefyomi86903 жыл бұрын
Please make more of this code reviews. Learnt a lot in just one video. Thank you
@fandinurrokhim2615 Жыл бұрын
thank you, as a junior developer this video really help me how to code better
@ayushmukherjee233 жыл бұрын
This looks more like a person who just started laravel vs even a junior. Good review!
@benouattara62493 жыл бұрын
what is you definition of junior ?
@adityakadam22563 жыл бұрын
Nice video. Just one suggestion. For the DRY Controller Code, though the code is becoming shorter it adds the double query to the database. May be it can be made efficient by using an array and then in the if condition adding the image key-value pair in the array and at the end create statement can come. Something like public function store(RecipeStoreRequest $request) { $recipeArray = [ 'title' => $request->title, 'category_id' => $request->category /* other key=>value pairs */ ]; if($request->hasFile('image')) { /*code for file upload*/ $recipeArray['image'] = $name; } $recipe = auth()->user()->recipes()->create($recipeArray); }
@LaravelDaily3 жыл бұрын
Yes, I agree, good catch.
@VitaliyHAN3 жыл бұрын
Thanks. Plz make more like this. Code review is good place to learn. BTW Im from Russia, I think you have the best laravel KZbin channel in the world!
@ljubicasamardzic78193 жыл бұрын
Thank you! These are extremely helpful. Looking forward to future code reviews.
@sirajul-anik3 жыл бұрын
For the recipes create/update operation I get his point for the duplication. He doesn't want to run queries twice. Your approach is okay. But I'd prefer to "make an array of common attributes, push conditional attributes to that array" and then create the row. With this approach, I'd need to run create the row only once and no duplication.
@ryanb5093 жыл бұрын
I was thinking the same thing but I can do one better. There's no need to merge arrays even. If you add the create after the if statement for dealing with the image. The code uses the variable $name (though I'd call it something clearer like $image_name) but you can just include that in the array, if there was no image uploaded that variable won't get set and it will just be null.
@sirajul-anik3 жыл бұрын
@@ryanb509 I am not sure if that's a good approach or not, because you're trying to access a variable that's not even initialized unless gets into the if block. and I don't think it actually differs from my approach. $attributes = ['a' => 'a', 'b' => 'b']; // add the common fields if (logic) { $attributes['images'] = 'value'; } Model::create($attributes); IMO, the above snippet looks what it means and I think your approach doesn't add any value. That's my opinion.
@LaravelDaily3 жыл бұрын
Yes, I agree, good catch.
@ryanb5093 жыл бұрын
@@sirajul-anik Both work. IMO I find the code for my method a little cleaner and more clear. For example if you are trying to quickly look into what is being passed into create, its right there. However with your method you have to go back in the code to where you are setting the variable then also look at where you are merging in the image to get the full logic. if ($logic) { $image_name = 'value'; } Model::create([ 'a' => 'a', 'b' => 'b', 'image' => $image_name ?? null ]);
@sirajul-anik3 жыл бұрын
@@ryanb509 it's more of the developers taste. both works fine.
@raulrojas65522 жыл бұрын
extremely useful for Laravel newbies
@larrylague13592 жыл бұрын
we learn a lot please continue making more video like this in the future
@geneartista97143 жыл бұрын
Truly helpful indeed, such lesson is what I need :) Thanks for your hard work.
@AbderrahmanFodili2 жыл бұрын
This really helped reduce my imposter syndrome. I can sleep peacefully tonight unless I read a freelancing project requirements
@exikoz3 жыл бұрын
Thank you for taking your time and teaching us this valuable information.
@gtsmeg34743 жыл бұрын
Nice video, I'm currently having multiple projects using Laravel, I currently use Laravel module package to modulate my application
@dhellly3 жыл бұрын
Thank you Povilas... Great Review!!!
@emmanuelsiziba51423 жыл бұрын
thank you from Zimbabwe
@targetx17333 жыл бұрын
You could atleast two reviews per week. It doesn't only helpful for junior developers,but it helps keeps more advanced devs in line and current
@LaravelDaily3 жыл бұрын
Well, send me the code to review :)
@darkmode4043 жыл бұрын
Not to disrespect but, I'm already appreciating that he uploads even one code review.
@joelmnisi46493 жыл бұрын
With admin prefix, he can also create a new admin.php file on routes folder and separate admin routes from other users.
@salmamourad44073 жыл бұрын
thanks for the review we need this type of video to learn how to code pleaase make more review videos on your channel
@p30mehrdad3 жыл бұрын
Yessss! Code review! thanks
@ayomikunsamuel77433 жыл бұрын
I think in following the single responsibility principle, the code block to upload an image should be abstracted and just called when needed.
@alexaverkiyev90993 жыл бұрын
Worked with Laravel Love - very powerful package.
@asadeisa55913 жыл бұрын
this kind of video is very very helpful
@GergelyCsermely3 жыл бұрын
Thank You, I like this videos, excellent help to learning
@mhmdomer3 жыл бұрын
Thanks for the review! The slug attribute must be unique for each recipe because it is used as a key to get the recipe in the route model binding. However, in this implementation, if two titles are the same then there will be conflicting slugs because the slug is not unique at the database level.
@LaravelDaily3 жыл бұрын
Good catch.
@marekjurica90983 жыл бұрын
I found this solution: protected static function boot() { parent::boot(); // registering a callback to be executed upon the creation of an recipe static::creating(function($recipe) { // produce a slug based on the recipe title $slug = Str::of($recipe->title)->slug('-'); // check to see if any other slugs exist that are the same & count them $count = static::whereRaw("slug RLIKE '^{$slug}(-[0-9]+)?$'")->count(); // if other slugs exist that are the same, append the count to the slug $recipe->slug = $count ? "{$slug}-{$count}" : $slug; }); }
@buddhasmoke30003 жыл бұрын
I would like to use spatie sluggable package to prevent such issues
@jsjunior3 жыл бұрын
How did you put sidebar as an icon in Phpstorm? @Laravel Daily
@ngocatnguyen57713 жыл бұрын
You can get the data out of request first then using it to check if the is image in the request or not, then after that insert into the database. This will using only 1 query instead of 2 in case there is image. I was taught that limiting the db transaction as much as possible.
@amarhidic25282 жыл бұрын
Image can be stored like this: 'image' => request()->hasFile('image') ? request('image')->store('images/recpies') : null So the final code can be even cleaner and we don't need to use if-else and update record after it has been stored. $recipe = auth()->user()->recipes()->create([ 'title' => request('title'), 'category_id' => request('category'), 'procedure' => request('procedure'), 'duration' => request('duration'), 'ingredients' => request('ingredients'), 'image' => request()->hasFile('image') ? request('image')->store('images/recpies') : null ])
@ejaadhulab89242 жыл бұрын
Thank you for sharing this code. I really needed this. I need some help in my code, can you pls help me out. I have Leaverequests table, $table->foreignId('leavetype_id')->references('id')->on('leavetypes')->constrained()->onDelete('cascade'); $table->foreignId('user_id')->references('id')->on('users')->constrained()->onDelete('cascade'); //User requesting leave $table->foreignId('handover_staff_id')->references('id')->on('users')->constrained()->onDelete('cascade'); $table->foreignId('approved_staff_id')->nullable()->references('id')->on('users')->constrained()->onDelete('cascade'); ListLeaves Controller, $leaverequests = Leaverequest::with('user')->latest()->paginate(5); I am unable to get the username for "handover_staff_id" and "approved_staff_id". I am already getting the "User requesting leave". I am unable to create the relationship between User modal and Leaverequests modal. Thank you in advance.
@genechristiansomoza49313 жыл бұрын
The "duplicate code" refactor calls the database twice. What I will do instead is to construct first the array of parameters. If there's image then I will add it to array of parameters. Lastly, I will call the create method passing the array of parameters.
@drushtant3 жыл бұрын
Thanks a lot. This is really very helpful. I just remembers I shared my codes with someone but forget to share the login details! and I know how irrirating it can be.
@Ehsankhan05773 жыл бұрын
thank you sir it's really helpful please keep it up
@muzika50012 жыл бұрын
Good explanation!
@LoganathanNatarajanlogudotcom8 ай бұрын
Love this video. thanks
@belce19823 жыл бұрын
Thanks as always!
@ryiad20103 ай бұрын
wonderful video
@mohamedkamal76063 жыл бұрын
Thank you, very helpful
@alifallahrn3 жыл бұрын
Thanks, the tips were great!
@PsyHooZ3 жыл бұрын
I think in last example better to do this: $recipe = [all data in example]; Then if (image) $recipe['image'] = value; And then user()->recipe()->create($recipe) This optimize query to db, I think 🤔 You don't need create, then update, if you can once create)
@lahcenfahmi53613 жыл бұрын
Thanks so much for the video
@profesone3 жыл бұрын
Helpful AF
@daniyarbaizhaksynov92303 жыл бұрын
Hi! Thanks for video! I think last case was wrong way of solve because in corrected version gets 2 request to database first for insert and second to update which is not cool! There have another ellegant way to solve it)
@WebJourneybd3 жыл бұрын
Thanks a lot. Will you make a video.... How to delete database notifications by row in laravel?
@gssj-o8p Жыл бұрын
Should I import the namespace of the class I use in route files?
@aribiali35743 жыл бұрын
Hi , please tell me how can i get ur level , I'm lost What should i do ?
@whoami-so2hy2 жыл бұрын
thanks for sharing
@randomguy59223 жыл бұрын
Thin Controllers Fat Models, do this principal applies for LARAVEL controllers also, because most of the time, I see thin Models and FAT controllers in laravel.
@mansoorkochy3 жыл бұрын
if you follow junior code review as a series It would be appreciated, as well please make records on php design patterns Best regards
@LaravelPackageTutorial3 жыл бұрын
Nice 👍
@brianotido40692 жыл бұрын
Thanks
@alexanderanastasiadis92843 жыл бұрын
It is necessary to declare the reference between fields in migration or we can put a simple integer and it can be done through a relation in the model. For example if i had relation between recipe and user from function that is a wrong practice?
@LaravelDaily3 жыл бұрын
Watch this video: kzbin.info/www/bejne/Y2iafaF4iLFlkM0
@buddhasmoke30003 жыл бұрын
For controller method ill prefer to make variable $data = $request->validated() in start of controller method. If(image) { logic $data['image'] = $name }
@luizmeier3 жыл бұрын
Exactly what happens when starting in a new company. Repositories without any instructions on how to install and configure things.
@kodaloid3 жыл бұрын
The change you made to deal with the duplication doesn't look right to me. The original condition checks only duplicates because the coder didn't realise they could append to the array that gets passed to create(). I get that you fixed it by adding an update if an image was specified, but you created a new problem by adding a sql command that doesn't need to exist. I'd instead encourage prepping the data properly before sending to the db to be more efficient.
@araromirichie4825 Жыл бұрын
I just wonder when will I be this good with Laravel 😢
@renwar3 жыл бұрын
Can the last tip be written in a better way by using save() method instead of create()? Smth like this below $recipe = auth()->user()->recipes(); $recipe->title = $request->title; ..... Other fields..... If ($request->hasFile('image')) { $recipe->image =..... } $recipe->save();
@LaravelDaily3 жыл бұрын
Probably, but not sure it would be worth this change, in fact it makes it less readable, in my opinion.
@sofyanmaulana82523 жыл бұрын
Yeah, I did the same too, because it only requires one connection to the database
@LaravelDaily3 жыл бұрын
Yes, I agree from DB query perspective, good catch.
@daleryanaldover65453 жыл бұрын
I remember my code looking exactly like that when I started using web frameworks, especially Rails and that habit of mistakes was brought in to my first Laravel project. lmao
@abderhmandaya16553 жыл бұрын
Sorry, but when I repeat the code I see that it is better than doing 2 sql
@rahman_abdu3 жыл бұрын
Things to do before laravel application deploy
@alexbaskov3 жыл бұрын
disagree with the "duplicated code thing". you're trading couple of lines of code into 2 separate db queries which may become quite costly in some huge distributed db servers and cause unneeded delays. could just create an array first, and then based on conditions add an 'image' key for that image and still do a single 'create' thing. i see those issues all the time when some trivial data is being injected based on couple of different relations, and it's one insert followed by 4 updates of newly created record. imagine you will need to add some versioning/revisioning or custom logging on top of that, when "date_updated" changes 5 times in 2 secs and 5 records in the "actions log" db. hope it helps some new coders - always think about scaling and optimization. not about 8 lines of code instead of 10.
@avvay03 жыл бұрын
"I got used", proceeds to make a mistake.
@eziosan7208Ай бұрын
Would you "Junior code review" my code, please.
@LaravelDailyАй бұрын
Maybe, if it's not a big piece of code. Send it to povilas@laraveldaily.com with information what exactly I should pay attention to.
@haroldchoung3858 Жыл бұрын
omg, how to get the password? guess?
@Mr_JuanCarlos3 жыл бұрын
Crack!
@peppis34082 ай бұрын
its not disrespect at all, its still a junior code so you expect these kind of errors lol
@ahmedhelal1743 жыл бұрын
kzbin.info/www/bejne/qqizfmBsjZWjg6s Thank you but I have one comment for that You saved the recipe with query then if it has image you did another query You hit database two times (2 queries) I think there is another good approach for that how about?
@LaravelDaily3 жыл бұрын
Yes, good catch,.other people also pointed it out in the comments, read other comments on this video.
@lassestube3 жыл бұрын
It feels sloppy to just send code that isn’t working, I agree a bit disrespectful if you will.
@andreich19802 жыл бұрын
In the RecipeController@index It's not great implementation for view_deleted... They don't eager load category and user for trashed recipes... It should be like this $recipesQuery = Recipe::with(...)->where(...)->anything(...) if (/* view deleted condition */) { $recipeQuery->withTrashed() } return $recipesQuery->get() Or something similar.
@andreich19802 жыл бұрын
RecipeController@store They could get current user form $request->user(), no need to use auth() helper Save an extra query $recipe = ...make() fill(['image' => ...]) $recipe->save(); It's a bad way to store images. They should have a recipe_id prefix or be stored in the recipe_id folder (123_name.jpg or 123/name.jpg) There's a tiny chance that 2 different users create a recipe at the same moment and there'll be a collision. Laravel has a default behavior - it generates a random file name - this is better.