Lec 9(a) Half Wave Uncontrolled Rectifier (R & L-Load)

[@GATEMATICEducation]

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[@sayandeeppoddar7324]

Sir where can we find the notes

[@shanuverma1233]

No Bloody resistor 😂😂 This much hate for poor resistance who by fault is our favourite load being so easy to plot 😂😂😂😂😂😂😂😂

[@ankitentertainment3933]

sir the way you speak its really amazing

[@ronnyalfons7096]

Thank u soo much sir, it took me about 2 years to understand what u just explained in a few minutes.🤙

[@paws_of_fury]

no bloody resistor 16:45 :D

[@GATEMATICEducation]

hehehe...

[@khushnumaperween1919]

Thanku so much sir, your content defeated the paid courses. Plz also make vdos on DC machine , synchronous and induction.

[@haroldhope9023]

Dear Sir , This is extremely well explained , however I0 sketch is not discontinuous as it touches the time axis,it is a shifted cosine

[@sireeshamattigunta6259]

You are doing great job...thank you sir.

[@GATEMATICEducation]

ur most welcome..just watch each and every lecture..u wont get prblm in real gate exam..all the best...

[@harshiniavadhanula5478]

Sir , i couldn't understand y the voltage across the diode is zero all the time. In reverse biased case I,e from pi to 2pi y will the diode be shorted.please reply me at the earliest.

[@fawadaslam851]

The Diode will remain shorted due to the back emf of the inductor. The inductor needs to release the energy inside it so it's voltage will become negative to make the diode continue to conduct current

[@JitendraKumar-kj1yw]

In RL load since maximum current occur between 0 to Π hence indictor will change its polarity between 0 to Π hence before Π for some time indictor and source both will supply power.

[@youcefaitamrane4074]

Many thanks for these valuable videos, Sir. One question if I may. Would the inductor circuit behave the same way if the diode were not present ? I worked that out and it turned out to be the same. Please confirm. Best regards, Youcef

[@pentainamerica]

I think it wouldn’t work that way... The current will have negative values as well in such case.

[@pentainamerica]

The current through inductor without the diode , will even have a negative value right....how did the current became completely positive by just a diode? I meant the current should just lag by 90 degrees and negative part must be cut....

[@konetiashok8198]

i could'nt understand how the extintion angle is 2pi-alpha in case of half controlled rectifier with inductive load.so,can u plse clarify my doubt sir?

[@Chiragverma947]

Thanku very much sir for providing free lectures 👍

[@saiharshanaidu1486]

During negative half cycle[Vk>VA]of first cycle diode gets opened then how can the negitive voltage can appear across Vo of inductor

[@kitfooverhoes6456]

inductor by its nature conserve voltage when the diode is conducting (on time) and discharge it's voltage when it is the negative cycle of the diode (off time) that is why you will find the voltage at the negative cycle, it's called BACK EMF

[@siddhantchiring7599]

@@kitfooverhoes6456 but in negative half cycle the diode should be revere bias , hence it should be an open circuit, so how can current flow

[@muhammadfahad2011]

@@siddhantchiring7599 as inductor stores energy during positive cycle , during negative cycle it draw backs that stored energy and since its direction is opposite so we get its wave on negative side

[@yashdave4752]

Thanks A Lot Sir For Your Precious Time!

[@VikrantKumarBrahman]

Dear Sir 1-ph, half wave rectifier with L-load gives 2 pulses in output voltage waveform. so would calling it a 2-pulse converter be erroneous?

[@GATEMATICEducation]

no its not giving two pulse..it is just following the Vs...means it is not coverting in to 2 pulse..thats y see the current waveform to know whether its one pulse or two pulse converter...we are getting Vo not by converting the waveform..Vo=Vs ...so it is not converting..it is following..got it..

[@pentainamerica]

The current through inductor without the diode , will even have a negative value right....how did the current became completely positive by just a diode? I meant the current should just lag by 90 degrees and negative part must be cut....

[@amansurya1483]

Sir the polarity across open circuited diode at 4:12 of this video will be opposite. So that the according to Vd = Vs. Am I right??

[@shivaprasadjuluri]

Thank you sir for posting these videos .It helped me a lot.

[@abhireddy6113]

Hello Sir, u showed us the trick for finding the RMS and Average value of the given function, why don't I get the correct avg voltage and RMS voltage formula when I am applying the same trick for half wave rectifier(R load), using the waveforms drawn.

[@VasanthBattula]

can you tell why R load is voltage stiff type of load and L is current stiff type of load. and while calculating the output power for R load we use Vrms and Irms, and for L load we use Vavg and Iavg

[@nocatnolife2946]

Please help me out of this. How output voltage is obtained for the negative half cycle

[@sandeeptiwari3655]

akbar aiyaz yes brother you are right..... It's wrong

[@mdparwezalam4644]

Because of L its in conduction mode ...so there output voltage of negative half cycle is similar to 1 st half cycle...it will follow the Vd=Vs....as you can see the graph .while the current after positive half cycle conduction remain conduct in negative half cycle which means vs=vd

[@kms7616]

@@mdparwezalam4644 ekdam correct✅☑✔✔ 👍👍

[@bondachiru3986]

thank very much sir,these lectures are very helpful

[@GATEMATICEducation]

ur most welcome..watch each and every lecture ..you will not get problem in power electronics..all the best..

[@kailash0181060]

can you tell me rms value of this wave(Vo )form by your trick which is in previous lecture.

[@dmrc7315]

I(t)=Vm/wL(1-cosw^2t) according to calculation it should be 1- cos w squire t

[@tahirhaniefmir3]

Sir how to download this video notes which you are providing ? Plz help

[@rohitlohchab3921]

Sir into half wave rectifier with r load ,while finding the power factor,why not vrms equals to vs like similar irms equal to Is

[@prabhatgautam3017]

Nice Explanation.....

[@pavanneelam4669]

sir why input current is equal to output current in finding power factor

[@ZILAL_ALHAKAYA]

sir , what is the name of the reference that you get this graphs from

[@anikjana100]

Sir for L load during pi to 2pi the diode is reversed biased but still there is a current flowing through the diode..... Is the diode conducting in the breakdown region?

[@GATEMATICEducation]

diode will be reverse biased only when the anode potential is less than cathode..but here this is not the case..it will remain in forward biased after pi also..

[@shivaballa6107]

GATEMATIC Education it means pie to 2pie anode potential is greater than cathode?? Is it correct??

[@badalpatnaik2249]

GATEMATIC Education sir how ??

[@amarjeetsingh5414]

great work sir thanks carry on

[@Arrogant176]

I0 rms = (root3)* Vm/ (root 2)*w*L correct? out put rms current?

[@reyazansari7175]

Sir how the inductor is connected during -ve half cycle when diode works as open circuit please help me sir

[@nocatnolife2946]

Same doubt bro

[@sachintiwari1959]

@@nocatnolife2946 actually from 0 to π inductor charges fully. And during negative half cycle inductor start behaving active source ( beause inductor does not allow sudden change in current) , thus the current remain in same direction from π to 2π

[@muhammadfahad2011]

as inductor stores energy during positive cycle , during negative cycle it draw backs that stored energy and since its direction is opposite so we get its wave on negative side

[@waqarmehdi4394]

During the positive cycle, the inductor stores energy in the form of magnetic field. But during the negative cycle, the stored energy is dissipated by the inductor. Since inductor opposes the change of current, therefore it tries to keep the current flowing in the same direction while dissipating the stored energy inside it. So during the negative cycle of voltage, the current still flows in the positive direction making the diode forward biased. This way the cycle repeats. Hope my answer helps !!

[@shanmukhteddu204]

sir what will be the PIV across the diode in case of L load

[@rajashekar2603]

Hello sir, From pie to 2pie inductor is behaving like current source b'coz it stored the energy in +ve cycle okay but the direction of current and supply voltage(-ve cycle) coming towards each other, then how the over voltage appears across diode in order to breakdown the depletion layer to become short circuit(in order to allow the current in the -ve cycle) kirchoff's law also not satifying here am confusing

[@GATEMATICEducation]

i cannot get you..plz post ur query in group by taking the screenshot of lecture..thankyou

[@VikrantKumarBrahman]

Dear Sir Cos (phi) = Vo(rms)/Vs(RMS), this implies cos (phi)= 1/sqrt(2) for 1-ph,0.5wave,rectifier with r-load. and 1 for 1-ph,0.5wave,rectifier with L-load. in L-load configuration waveform too justifies the fact but in case of R-load how to understand the justification from o/p waveforms?

[@VikrantKumarBrahman]

sorry for L-load COs(phi)= 0.

[@GATEMATICEducation]

see to find the input power factor first see whether the load is current stiff or voltage stiff..that i explained you in lec-07...here R load is voltage stiff type of load so you take output power=Vrms^2/R...but for current stiff you have to take output power= Voavg*Ioavg and for L load V0avg=0..so pout =0 and cosphi=0....got it..what do u mean by this..this means the active power dissipated across load is zero..measn whatever the power is transferred from source to load from 0 to pi is again transferred from load to surce from pi to 2pi...that's whay we are not getting output power...from waveform you can see that from0 to pi power is positive..and from pi to 2pi power is negative..got it..

[@naveedsofi7646]

Sir plz. and plz. explain this question if V is per phase voltage then average output voltage in per phase in 3 phase full wave rectifier(uncontroled type)

[@akiranandanellandula1003]

super sir

[@koustavpramanick8373]

Why there is voltage across L in reverse bias from pi to 2pi? In previous lec u told that in reverse bias there is no voltage build up in inductor and how its magnitude be -Vm?

[@GATEMATICEducation]

inductor has to discharge from any path..it has some energy stored..so to release that energy ..it will conduct after pi as well

[@koustavpramanick8373]

GATEMATIC Education but how the magnitude of Vo be -Vm sin wt at duscharge ?and how its determined ?

[@MasudRana-hk7pn]

16:44 No bloody resistance is present😂

[@firozali898]

Sir aap Mahan hai

[@PriyankaSingh-je6ro]

If diode anode is more negative then cathode.. Then it will conduct or not?

[@rishabh7621]

when anode is more negative than the cathode, then the diode is simply in reverse bias condition, thus it will not conduct.

[@faisalasri5035]

Is there any LE load? help me out

[@Harshavardhan-zr2ip]

Output is same as input (for L load) Then how it rectifier

[@belkacemguenidi4413]

very usefull thank you !!!

[@abdullahalmotipinto6754]

great!

[@HimanshuVerma-ej9gr]

From π to 2π how can you short circuit the diode???

[@PS-zh5xq]

Thank u sir

[@vikramram9581]

sir pls i want lecture on topic'' Bidirectional ac to dc voltage source converters'' becoz it is not there in any text book.

[@krishnachaithanyav6903]

sir during negative half cycle how can the diode conduct if it is reverse biased and one more while the Inductor is discharging , that voltage will appear across the diode so diode voltage will be -VM how can it be 0 during negative half cycle also.... am i right or wrong please explain sir thank u

[@GATEMATICEducation]

diode will go in to the reverse bias when the the current through the diode will be zero..here bcoz of inductor current is non zero after pi also...so it wont go in to the reverse bias..inductor is responsible for the conduction after pi...got it..

[@krishnachaithanyav6903]

LearnGATE Free sir but reverse bais in the sense anode to cathode voltage should be -ve na

[@GATEMATICEducation]

it will not go in to the reverse bias..as there is inductor present at the load side...if supply voltage is negative let us say -200v...then inductor voltage will be more negative..i.e. -300v..so overall diode will continue to conduct till inductor have energy...got it..

[@krishnachaithanyav6903]

LearnGATE Free thank you sir understood

[@shyammaurya1205]

sir please upload emt lecture for ISRO preparation....

[@sayandeeppoddar7324]

Sir where could we get the notes

[@PK-cy9nx]

Hello bro. Can I know , why do you neglect C and RC type of load.

[@anikjana100]

not important in gate

[@abhinaysingh5401]

sir why the diode is conducting for negative half cycle in pi to 2pi in case of l load???

[@abhinaysingh5401]

ok i got it

[@shivaballa6107]

Abhinay Singh how?? Explain please

[@samarsoni1]

from where can i get the pdf of the notes

[@umeshpunna5572]

Sir pls find fourier series of hwr??

[@lakshaykumar3230]

SUR gr8 lectur. luvvvv!

[@GATEMATICEducation]

thankyou

[@milankumarbhoi1033]

Sir i need Io(rms)value

[@ravendrayadav6540]

sir how to remember these many concepts.... its very complex when we combine all rectifier topic ... sir???

[@GATEMATICEducation]

divide the topic in to sub topic and write down each and every formula ...during revision also write the formula..repeat 5-6 times ..it will be easy for u to remember..ok

[@unconvetrade]

y r u not adding more videos on other subjects

[@gayatrisingh975]

In inductive circuit should not the output current lag output voltage?

[@rakeshmakwana923]

It is already shown here lagging.I0 attends its max value at wt=π while V0 attends its max value at wt=π/2.

[@pentainamerica]

The current through inductor without the diode , will even have a negative value right....how did the current became completely positive by just a diode? I meant the current should just lag by 90 degrees and negative part must be cut....

[@ananyaaparanta4571]

In L load,as it is current stiff and Vavg is 0,so output power is 0..is it?

[@ananyaaparanta4571]

Actually we generally say P=VI in DC and P=Vrms*Irms*pf in AC..But you said P=Vavg*Iavg in current stiff.

[@GATEMATICEducation]

yes u can say that..average output power dissipated across L load is zero..whatever the power it is taking from source is one cycle..that power is being transferred to source in next cycle..got it..

[@ananyaaparanta4571]

yes sir..I got it.thank you

[@bhaskardugana1623]

Sir inverter lecturs pls.

[@nandishmb7530]

In half wave uncontrolled rectifier, how diode get short circuited between the interval pi to 2pi.

[@nandishmb7530]

In l load

[@CryptoAnimated]

Isn't the integral at 13:53 1 - cos(wt^2) ?

[@CryptoAnimated]

I guess I see whats the problem, the integration should be dwt instead of dt

[@nashs.4206]

Yeah I was also confused with this integral. Like you said, the integral should be with respect to wt, and not just t. So, the full KVL equation would be: V_L = V_source L*[di(wt)/d(wt)] = Vp*sin(wt) => di(wt) = Vp/L * sin(wt) d(wt) => Integral (di(wt)) = Integral (Vp/L * sin(wt) d(wt))

[@pentainamerica]

The current through inductor without the diode , will even have a negative value right....how come all of a sudden current became positive by just a diode?

[@manojpydi8477]

sir lecture was awesome....but my faculty says inductor is charging and discharging is nonsense.....stores and releases energy is good....but in this video i hear u call inductor charges and dischargs....plz tell is it correct r not?

[@GATEMATICEducation]

both are having same meaning..charging means storing energy and discharging means releasing energy...one word is talking in terms of current and another one talking in terms of energy...so dont get confused..

[@manojpydi8477]

LearnGATE Free ....tq sir and u say 100% we technically called inductor charges and discharge....that's fine ....actually y I asking this is my sir arguing with this point once

[@firozali898]

Sir aap electrical ki sb subject padhae plz

[@tirthankardas9875]

please provaide synchronous motor theory part

[@krishnateja8707]

In L load we get output voltage same as input voltage but why don't we get in R load

[@gaganbagewadi1362]

Sir every time you integrated with respect to wt and now you integrated t @13.25

[@knuckle8582]

Why didn't he take reverse bias condition from pi to 2*pi

[@aviyaarchana5898]

Sir i couldn't help laughing at 16:43... :D

[@GATEMATICEducation]

u mean bloody resistor??

[@aviyaarchana5898]

LearnGATE Free ya haha

[@aviyaarchana5898]

i was like watching the video seriously n then u came up with bloddy resistor... haha

[@sunshine-by2kl]

Did I heard *bloody resistor*

[@naina2557]

Rms value must be VM/√2

[@atanudey6507]

sir where is concept of filter?

[@GATEMATICEducation]

this is power electronics subject...not analog electronics...so filter is not required for this..also not in gate syllabus..

[@atanudey6507]

LearnGATE Free ok thank you sir

[@GATEMATICEducation]

ur most welcome.

[@debasmitapatra9383]

Am I only one who heard "Bloody Resistor" 😂

[@jaydipprajapati9740]

Me too😂

[@koushikmondal5732]

@@jaydipprajapati9740 me too

[@jaydipprajapati9740]

@@koushikmondal5732 this is the bst series...ise follow karo

[@koushikmondal5732]

@@jaydipprajapati9740 okk thanks

[@haroldhope9023]

....In the case of pure L load

[@ranasarkar4825]

Sir beta ko Extinction angle kehte hei extension angle nhi !!, thoda acche se analysis karke aaiyega, warna baccho galat sikhenge

[@gokenriba08]

Y can't I understand anything 😭😭

[@Lost_Soul619]

I hope you are not in electronics related sectors 😪

[@ayushgupta22]

no bloody resistor 🗿🗿🗿🗿

[@jaydipprajapati9740]

Bloody resistor 🤣🤣🤣🤣🤣🤣🤣

[@naveedsofi7646]

Sir plz. and plz. explain this question if V is per phase voltage then average output voltage in per phase in 3 phase full wave rectifier(uncontroled type)

[@naina2557]

Rms value must be VM/√2

[@naveedsofi7646]

Sir plz. and plz. explain this question if V is per phase voltage then average output voltage in per phase in 3 phase full wave rectifier(uncontroled type)

[@GATEMATICEducation]

go to threee phase rectifier lecture..

[@naveedsofi7646]

Sir plz. and plz. explain this question if V is per phase voltage then average output voltage in per phase in 3 phase full wave rectifier(uncontroled type)

[@GATEMATICEducation]

i derived the relation between phase line and max line voltage..go through the three phase rectifier..