Lec07 | D-Operator Method in 1 Shot | 2nd Order Linear Differential Equation | Differential Calculus

[@gen._prime4168]

sir for the HW at 35:05 if we try to find the P.I using the way at 26:27 it is coming as -8/3e^x(1/3+x) but if we solve according to 33:15 then P.I is coming as -8/3xe^x. When which one should we consider and why?

[@TendingtoInfinity]

That is an excellent question. Let me explain to you, Both the answers are correct. If we take the part "-8/9e^x " out of "-8/3e^x(1/3 + x) " then "-8/9 e^x " can be adjusted with one of the term of C.F. as you should definitely get C1 e^x in the C.F.

[@gen._prime4168]

@@TendingtoInfinity ok, Thank you sir.

[@deepmondal8459]

We can also keep multiplying the numerator with x and differentiate the f(D) part w.r.t D until f(a) becomes not equal to zero.. With this approach -8xe^x/3 coming

[@bishaldutta1901]

sir please complex integration er video upload korban

[@debasritabose147]

35:05 P.I.=-8/3xe^x

[@TendingtoInfinity]

Yes. It is Correct.

[@souvikroy3584]

Q.17.hw ans The complete solution is y=(C1e^2x+C2e^3x) +e^x/10(Cosx-3Sinx) Where C1 and C2 are arbitrary constant

[@ashishjana4693]

35:05 Sir the complete solution is -> c1e^4x + c2e^x - (8xe^x/3)

[@vee.1425]

1:33:57 answer matched 😭🤌

[@TendingtoInfinity]

That's great. Keep practising.

[@ankitbhandary2005]

great job sir , no really I appreciate your effort to teach us these complex topics in this much easy way. Thanks for this

[@chanchalsarkar717]

Sir I am getting two answers for the question of 35:40, one PI is -8/3 xe^x and another PI is -8/3 (xe^x + e^x/3). After a bit of a manipulation, I was able to make both of the complete solutions same with a bit of change in the arbitrary constants. The answer came as Ae^4x + Be^x - 8/3 (xe^x)

[@TendingtoInfinity]

Your answer is absolutely correct. You can check the pinned comment to understand the solution more thoroughly.

[@ankanabiswas6548]

Sir ... Thank you soooo much.... This was very very helpful 🤩You are an amazing teacher. Khub e bhalo poran apni .

[@TendingtoInfinity]

Thank you so much 😊

[@chanchalsarkar717]

Sir at 1:33:57 I have got c1e^2x + c2e^3x + (e^x (cosx - 3sinx))/10 , which is basically the same answer that you have provided.

[@TendingtoInfinity]

Well done. That's absolutely correct!

[@6.anushmitadubey621]

how are you proceeding with the question?

[@amitraksharchakraborty8761]

Very helpful sir ❤

[@TendingtoInfinity]

Thank you for your support ☺️

[@sayakarar]

Sir aapnar support r guidance r jonno e 10 credits pelam exam e... 🙏🙏

[@TendingtoInfinity]

Arey that's great! Khub bhalo laglo sune.

[@ayushshaw1755]

1:13:13 checkpoint.

[@ashishjana4693]

36:20 (1/20)e^x -> perfect it

[@joyswarnakar]

How? Can you explain it shortly?

[@hqverse8352]

today is my exm and this playlist helped me alot..thank you so much sirr🙏🙏

[@TendingtoInfinity]

You're most welcome 🤗 and all the best .

[@ex-mf5ss]

sir in the 1:01:08 problem , if f(-a^2 ) = 0 then we can P.I = x*(1/f`(D)) sinax or cosax we do P.I = [x * (1/2D ) * sin2x ] = -(x/4)*cos2x thank you sir

[@TendingtoInfinity]

excellent. You arre most welcome!

[@priyanshikumari7567]

Sir but in 1:27:27 f(a) is not equal to 0 then why are we not using replace D by a instead of D+a

[@TendingtoInfinity]

I have said this reason in the video as well that whenever some other function is multiplied with an exponential function then we have to replace D by D+a whether f(a) is 0 or not.

[@pro_ticck]

sir 1:32:40 te 36(-1^2)-1 =35 hobe ig

[@SAKET_28]

Sir out of nowhere --- Combo ka example -- policewala gunda ...😂

[@kaushambiroy6951]

1:33:52 sir my answe is not matching just sign issues the particular integral coming is -e^x/10(3sinx + cosx)

[@TendingtoInfinity]

Check once again

[@animezenith2004]

at 1:07:56 how (D+2i)^2 can be D^2+4iD ? by applying (a+b)^2 it would be D^2+4iD+4i^2...

[@TendingtoInfinity]

Where is (D +2i) ^2 ??

[@12hoursgaming11]

@animez you are absolutely write but +4 cancel out( 2i)^2 ,i^2=-1 so,+4 and -4 are cancel out

[@Debojyoti_Saha]

sir when the denominator is zero may we use this method ----- derivate the denominator 1 time & multiply a 'x' in the nominator .. repeat the process untill the denominator is not equal to zero

[@thekalkatiandude]

36:00 aa gya bilkul shi answer

[@TendingtoInfinity]

Very good 😊💯

[@Sabuman1234]

Ae^4x + Be^x -8/3 (xe^x) that is questions answers , i am trying this in P.I METHOD ❤

[@TendingtoInfinity]

Answer is verified in the comment section.

[@joyswarnakar]

Sir, 36:15 answer is e^x /6 ! Cannot match my answer e^x/20 ! Please help.

[@arpanthakur5822]

Same brother

[@arpanthakur5822]

36:09 Can anyone explain please how did 1/20 is coming ?

[@arindamn4880]

(D+3) (D+4) THEN PUTTING THE VALUE 1+3 × 1+4 WHICH IS 20

[@hereseverything7737]

much needed video

[@TendingtoInfinity]

Thank you 😊

[@ayushkumarsingh1871]

in the last question if we replace 'd' by 'a' it is not coming zero then sir why have you replaced 'd' by 'd+a'

[@TendingtoInfinity]

Can you kindly mention the timestamp? As I think as per your query the answer is: If there is any other function multiplied with exp function then whether the denominator is 0 or not we have to replace D by D+a.

[@6.anushmitadubey621]

1:33:48 HOW TO SOLVE THAT QUESTION SIR?

[@TendingtoInfinity]

You can solve this just as the last question. The question that I've solved just before this. If there is still any problem to solve this I'll solve this in the practice session..

[@6.anushmitadubey621]

@@TendingtoInfinity Ok sir Thank you

[@TendingtoInfinity]

Let me know whether it is solved or not here only.

[@6.anushmitadubey621]

@@TendingtoInfinity yes sir I have solved the problem Thank you

[@TendingtoInfinity]

Great .

[@cRiatIvo_Gamer718]

aastik nastik 😲😲

[@TendingtoInfinity]

Sarcastic 🫢

[@ArjunDutta-dm3uy]

Sir hw ta ans asche c1e^3x+c2e^2x+e^x/10(-3sinx+cosx), ans ta milche na

[@AkhandBharat-t1o]

Vai amar o mil6e na ..sudhu ..3sinx ta mil6e na...r tomar ..?

[@ArjunDutta-dm3uy]

@@AkhandBharat-t1o bhai amar oi A and B term kono ase ni bki ta mileche

[@AkhandBharat-t1o]

Quick reply koro

[@TendingtoInfinity]

A and B ashbe CF theke , A and B er jaygay C1 and C2 likhleo eki bypar.

[@anaabatyasra1110]

Sir polynomial mai.pata kaise lagega ki yeeh polynomial hai??

[@TendingtoInfinity]

A polynomial function is a function that involves only non-negative integer powers or only positive integer exponents of a variable in an equation like the quadratic equation, cubic equation, etc. For example, 2x+5 is a polynomial that has an exponent equal to 1. Polynomial function, exponential function, Sin and cos these are everywhere continuous and differentiable function.

[@the_rajput_19]

PI=-8/3xe^x

[@TendingtoInfinity]

Can you please mention the timestamp.

[@soumyajitmondal3774]

Sir eta ki BSM 202 r syllabus er under e asche?

[@TendingtoInfinity]

Han ache.

[@ArjunDutta-dm3uy]

35.05 Pi=-8/3e^x.x ans asche sir

[@TendingtoInfinity]

Han otai ashbe.

[@ArjunDutta-dm3uy]

@@TendingtoInfinity ok sir