Lecture 04 I Problem solving on Fundamentals I Part 02 I GATE 2019 I Genique Education

[@GeniqueEducationTeam]

G saviour - To connect with pankaj sir join telegram - t.me/pankajshuklasir

[@sonuhalder9211]

1Q.ix=0,vx=0,2vx=0 hence it is also dead ckt as no independent source is here . 2Q.R=5ohm and I=0▪8amp Thanks sir for your lectures it will help us to build our concept and one thing polarity choose karne mai problem hota thaa but aab galti nahi hoga✌✌✌✌

[@rahulsinghthakur420]

ans 1--since there is no independent source so there is no power in circuit hence Vx=0 Ix=o ans 2-- r=5ohm

[@adyasapriyadarsiniacharya8196]

can u plz explain how u got 5ohm

[@rahulsinghthakur420]

@@adyasapriyadarsiniacharya8196 see 2A source is DELIVERING 12 wats so take signs according to that and voltage across 4 ohm resistor will be 6 volt and current through it will be 1.5 ampere but be careful about the signs of voltage and current then find currents in each branch ultimately u will get voltage across R = 4V and current through it 0.8 amperes.....finding current is very easy for these question if u find currents u need not to solve any questions....just do KCL in mind u will get ans...if not ask me again

[@vishwnathkumar9931]

Bhai Mera 3ohm aa raha hai..... Or second question Mai after solution ix vx Sab zero aaya

[@rahulsinghthakur420]

@@vishwnathkumar9931 bhai kuch silly mistake hora he ek baar dhire dhire solve karo aega ans...

[@NitinSharma-wf5eo]

RAHUL THAKUR bhai 20 ohm resister k accross current 3.5 hogi na to fir vahan par drop aaega 70V fir hum kvl lagaenge centre waale loop mein to voltage accross R aaega -76 ya +76 ka tera 4 ohm kaise aaya bhai ... Reply kar dena..

[@ashishraielectrical7437]

Sir i am diploma student and your video is very inspirational for me. Thanks sir.. 🙏🙏🙏

[@sonubishwas5300]

Sir first question is indeterminate. In question number2 R=5 ohm

[@santanu6763]

Question 2. Vr=4volt, Ir=0.8 amp, so R=5 ohm Thanks for your videos 👍 from core of heart ❤️

[@zeeshanali-qb1kw]

Kya aap bta skte ho ke ye ans kese aaya plz agr bta sko to

[@milankumarvid]

Q-1: I =0 , v= 0 and p= 0 Q-2: answer R=5 ohm Please correct me if my answer is wrong

[@subhasishnaik368]

Q no. 1 is an invalid ckt. Bcoz of absence of independent source. Q no.2. R=5 ohm. i(10)= 1.3 A, i(20)= 0.5 A, i(4)= 1.5 A(up), i(R)= 0.8 A..voltage across 2A source = 12/2= 6 V (current will out from +ve terminal).. absorbing power P(17V)+P(10)+P(R=5)+P(20)+P(4)+P(2A) =( -22.1) + 16.9 + 3.2 + 5 + 9 + (-12) = 0 Watt...Tq sir..

[@PrahladKumar-md9sh]

Thanks a lot sir you and all Genique team. Ans - 1. Everything is zero(0) 2. R = 5 ohms

[@mdwasim5444]

Bhai mujhe photage doge dono questions ka

[@kailaskrishna4385]

1- as per the condition to flow of current there must be a INDEPENDENT source which is not present here so Ix=0,Vx=0 and offcurse power is also =0w 2- 5ohm Superb sir .......👌👌👌 Bus ye sare network ke concept ko kaise machine,power system,PE me use krna hai ye sikha dijiye sir maza a jayega😊😊

[@kailaskrishna4385]

saapo 15 2amp ke across power diya hua hai usse 2amp ke across ka vtg nikal lo wahi vtg 4ohm ke across hoga and usee 4ohm k current mil jyega....

[@ashishranjan474]

Q2 r=5ohm (voltage across current source is -6v we can find in branch ...then by kvl get ans)

[@gladiator8827]

bhai kase nikala btado

[@terracegardeningwork]

ha nhi samja solution provide kro please

[@satyamgautam4694]

Q.1___ Ix ,Vx & P(dilevered) are 0.that's why KCL,KVL & conservation of power will not exist. Q2__R=5ohm.

[@amankumar7077]

where can i find the solution of the two questions?

[@kamleshsharma6226]

Q-1 ans= 0. Q-2 ans= 5ohm and power absorb by voltage source = -22. 1W and power absorb by current source = -12W and total dissipated power = 34.1W and total power of the ckt will be zero.

[@souravsarkar7941]

Q:-7 ,,Vx=11Volt i think cause current through this terminal will be 1A

[@jsgtech2705]

Q-7 in left side have independent voltage source of 10v and resistance 2ohm then we calculate current I=10/2=5Amp then it's how solve

[@mohdiqbalparry258]

In q1 there are all dependent sources therefore there will be 0 ans means 0volt 0amp 0power...

[@chetanh9628]

awesome lecture but in this video there is quality problem whiteboard writing is not visible clearly

[@nikunjrabadiya436]

1 ans Zero due to not a single dependent source present Am I right? Please anyone reply if you agree!

[@ommishra8853]

U are damn ri8 bro. Even if u calculate u will get 0

[@DanishAli-ql1es]

Can u pls elaborate this concept,i solved by doing calculation and i got zero but it u will explain me this one it will be very helpful

[@Learning342]

1st question ) all zero {ix,vx and power delivered} 2nd question ) R= 5 ohm

[@terracegardeningwork]

2nd que please provide a solution.

[@RahulKumar-mo6bf]

Q2 sol.plz

[@sreekanthdhandu4394]

Sir, in 8th question I calculated power absorb I'm not getting = 0.,P at 1A = 18W (D), P at Vs = -85W(A), P at 2A =18W(A),P at 3ohm =-12W(A),P at 4 ohm =36W (A) , P at 1ohm = 25W(A).. Ptotal absorb =-36w I'm getting sir

[@cholletivinay1148]

P at 1A = -6 w (A) , P 3 ohm = 12w (A), do correctly and convert all into either absorbing or delivering u will get as zero. Hope this will help u☺️

[@mrxd8972]

1st question Ix=Vx=0 and power del by 2Vx=0 since dead circuit... 2nd question R=5 ohm

[@redundant5837]

sir , Question no -8 me total power = 0 nhi aaya .....kya kre ?

[@heera_ai]

1. Ix=0amp. ,Vx=0 volt, P=0watt 2. R=5ohm

[@sanjaykumar-gz1zg]

First question has not independent current or voltage so all current will be zero so power will be zero 2nd question ans R=5 ohm

[@anilgurjar9813]

sir first of all thank you for this ans. in first one power deliver is zero and in the second one R=5ohm

[@mohitrajput1223]

Explain Q2 please

[@saikatpan3644]

Sir 2nd question ka answer R=5 ohm hoga...aur pura ckt me Energy conservation law v follow ho raha h🥰🥰🥰....Lekin 1st question me Depended source wala math apne to karwaya hi nhi🥺🥺🥺...kaise Kare😔😔😔

[@secretdevil459]

In first question Vx=-54Ix and Vx=-44ix so means Ix=0 or indeterminate. In 2nd question Vr=4V and Ir=0.8A so R=4/0.8=5 ohms

[@secretdevil459]

VX=ix=0 and so power delivered by the 2Vx source is 0

[@mechkumarpegu1138]

God of EE.. salute to you sir

[@MrKING-qr7om]

No is god of EE, just remember it!

[@yogeshjangid3698]

sir in question no 8------> {{{ 3Amp current shoud go from short ckt path and current through 1ohm resister should be 0 so voltage drop=0 }}} this was my concept please reply how it is wrong??? please sir

[@HiFiamitkumar3870]

Sir questions 5 me nodal laga ke abs de power Nikal sakte hai

[@rushabhshukla1900]

Q1:all ans are 0 Q2:R=5 ohms

[@ANKITSINGH-md9ou]

such circuit does not exist, practically it is a dead circuit

[@energyengineer4816]

In question 8 How we can apply kvl by skipping the mid elements? Is tarah tou ko hum kisi ko b skip kr k kvl lga sakty hain

[@AjayKumar-ps4ro]

sir if possible please explain the concept of 1st question

[@friday037]

Sir, in question 7(22:00) when u apply kvl in clockwise direction, polarity across 2ohm & 3 ohm need to be opposite right. If not please correct me

[@shubhamkumarprasad9463]

2nd answer is resistance value will be 8 ohm

[@sanketdkadam]

1Q) Dead ckt hence all parametera 0 2Q) R=13.68

[@pagadalasaipavankumar2929]

1)ans 0A,0V,0W 2)ans R=5ohms

[@jsgtech2705]

Sir aap independent source ka ek v question nhi karaye na bataye kese handle karte hai ek bar bata do

[@praveenchauhan6299]

ans of q1 is indeterminate.and q2 is r=10

[@nasar8480]

2) 5 ohm 1) I was not able to calculate it as I didn't notice that there is no independent source present in the circuit. I was just blindly manipulating the equations hoping to get the result.

[@kiranmedar3391]

Nasar Ahmad Zafar can you explain how to get 5 ohm?

[@nishkarshjain5684]

1) ans is Ix && Vx is 0 && P is also 0. 2) ans is 5 ohm.

[@jsgtech2705]

How 0 can u explain

[@chetanh9628]

sir i solved question no1 answers are Ix=10A, Vx= -540v , p= 129.6 kw

[@prembaboo4214]

Thank you Sir very much. You have explained very beautiful. My concepts have been cleared.

[@mangaldip7638]

1. There is no active element in the circuit 2.R = 7.8 ohm

[@pravakarmohapatra5735]

Sir 1st qn vx=ix=Pdeliver=0 &2nd r=-5ohm

[@appannaniceberg755]

1. dead circuit power delivered by 2Vx=0 2. R=5ohm

[@agaurav1]

Explain plz 2nd one

[@MohammadAsif-zp8px]

Since there is no independent source therefore Ix=0,Vx=0,and P2Vx=0 took.......ii)R=5 ohm..........kindly provide the answer for the same.

[@MohammadAsif-zp8px]

Also it's a dead ckt too .....

[@chinnichinnu2264]

first question: Ix=0, Second question: R= 5 ohm

[@zeeshanali-qb1kw]

Sir question no.7 mai total power kitni aayegi..usme zero nahi aarahi hai..or apne kaha tha kisi bhi ckt me total power zero aati hai

[@pratapchandra9304]

Q 1. Ix=0 A, Vx =0 V , P 2Vx=0 W Q2. R = 5ohm

[@supriyamaurya889]

1. Ix =0,Vx=0 power deliver to 2Vx =0 2. R=5 ohm

[@mankaransingh7226]

how 2 ans came share the ans

[@prabhakari6705]

Q1--• all terms = 0. Q2--• R = 5 ohm.

[@mohitrajput1223]

Explain Question 2 Please

[@pooranikannan7045]

Sir I have a doubt in the homework 1st question.... How to find the Ix value The voltage through 10 Ix is -30Ix By using kvl...... Current through 2ohm is 13Ix Current through 4ohm is 12 Ix

[@ankitrajhans488]

Ques 1- All ans equal to 0 Ques 2- 5 ohm

[@skill-mines]

1Q-All are dependent source so dead circuit P=0 And 2Q-5ohm

[@thesb2171]

5ohm how??

[@skill-mines]

@@thesb2171 I(4ohm)=1.5a I(20ohm)=0.5a Voltage across resistance=4v(using kvl) Again apply kvl in first loop and find I(10ohm)=1.3a So Ir=0.8 R=(4/0.8)=5 ohm

[@somlaeducations3308]

SUPER BRO @@skill-mines

[@simmikumari8216]

@@thesb2171 But why we are taking current in upward direction through 4 ohm resistance. Kindly explain

[@AnkitKumar-gf3sm]

Ans.1- 0 (dead curcuit) Ans.2 - 5 ohm

[@kumarg7365]

1.no independant source is there Vx and ix not determined not a valid circuit 2. R= 5 ohm

[@indureddy1040]

Its not a complete circuit its a portinn of ckt.so its absolutely valid ckt.because we can get voltage and current at very element of ckt

[@BeautyOfIndia007]

in qn no 8 a -2A current in branch you have taken sir, if we reverse the sign than it goes to stuck while getting answer. please explain this sir.

[@umesh_damar7135]

It is also my problem

[@ganudeep7871]

@genique education sir,Iam sorry to ask this doubt so late.in q.no 6 will the ohm's law be applicable in case of non-linear resistor sir or we can do approximation in case of network theory?bcoz directly aap ne power mein substitute Kiya v= ir

[@ishangujrati9712]

1) Ix=0, Vx=0, P2Vx=0 2) R = 5 ohms This is my ans. Sir plz post correct answer in the description.

[@GagandeepSingh-uy9cm]

Detail send karna

[@akriti7959]

Sr hm abhi second year ka student hu Sr hm gate 2022 ke liye prepared karata hu Sr hamako questions PDF kaise milega pleases give me answer Sr.

[@ShubhamSingh-xq7lg]

In first question ix and vx=0 ..in 2nd question R=5 ohm

[@shivanikoirala2251]

Question 1 since there isn't any active source ix=0,vx=0 Question 2 R= 5 ohm

[@mankaransingh7226]

how 2 ans came share the ans

[@HiFiamitkumar3870]

Sir abs de me. Sign kaise Nadal hate hau koi or method

[@khushboojain3883]

in 6th ques, u have written different formulae for power using ohm's law, but ohm's law is valid for only linear elements. So, i think it is not correct and moreover if it is correct according to u sir, then there is no need to give active and passive nature of the element as by equating different formulea of the power, we get R= 1/current , so current has to be positive as resistance cant be negative. So , just confirming that writing power formulae for non linear element using ohm's law is wrong. Thanks for ur work! Please do consider this comment. :)

[@pranavkumar1482]

Q1. Ix=0,Vx=0 & P2Vx=0(d) Q2. R=5 ohm

[@biswasurakhitbarik6343]

Can u explain q no 2..?

[@bhaskaralakshmiganisetti3779]

At 29 .20 how to take overall loop there is a branch resistance with source ...what the concept behind that plz clarify

[@vaishnavisrivastava8800]

1)Ix,Vx=0 2)R=5 ohm

[@pooranikannan7045]

Sir I have a little bit confusion in the 2nd question could u please clear it

[@ShivamSingh-lc1or]

Q1- Ix=0 Vx=0 P=0 Q2- r=5

[@SanjayChoudhary-ei5rl]

Q1. Vx=0;Ix=0 ; power delivered =0 watts Q2. R=5 ohms

[@mankaransingh7226]

plz share the solution of 2 ques how it come

[@MAJEDKHAN-channel]

Thanks u....for ur lectures....love u the way u teach

[@chetanh9628]

sir question no 9 me aapne last me jo current division rule use kiya usme how can you calculate total resistance is 7 ohm? they are in parallel so why not you take 10/7 ?

[@basudevsashtri1138]

No you can not do that because you are asked to find the value of I which is flowing through 5 ohms resistance. Thats why current divusion rule has been applied .

[@chetanh9628]

@@basudevsashtri1138 ya i know that but in current division rule total resistance sir take 7 ohm but why they not take 10/7 ohm (because 5 parallel with 2)? this is my question

[@nihardixit7094]

Ist ans -0 2nd - 1.538ohm

[@jyotirmayeepati4475]

1- all answers are 0 2- R=5ohm

[@sanapathivykuntarao9103]

Sir, explanation super. CIL 2020 ELECTRICAL classes please tell me sir

[@subhosen4933]

Ix=0,Vx=0,and therefore power delivered by 2vx source is also 0

[@sharvansinha4732]

Congratulations sir for 5k subscriber, I wish bahut 5k change into 50k

[@saikrishthangappan6140]

its 100k now.!!

[@rajasthanistatus4049]

Now 177k subs

[@athirapb7940]

Concept is very clear now! thnq sir😍

[@avanishyaduvansi]

Electrical Ac ka numerical ka videos hai kya

[@Bihar_Vibe]

Ix=0 ,Vx=0 & Pdeli.. by2Vx =0 R=5ohm

[@gajulagreeshma1085]

1st answer Vx=Ix=0 2nd answer R=13.6 ohm

[@GOODMORNINGELECTRICAL]

Sorry wrong Ans.

[@GOODMORNINGELECTRICAL]

R=5 Ohms and i= 1.3amp.

[@gajulagreeshma1085]

@@GOODMORNINGELECTRICAL ha again I texted r=5 ohms Once check down

[@nikhilnambiar4978]

First question - 0 Second Question - 5ohms

[@agaurav1]

Explain plz 2nd one

[@nikhilnambiar4978]

@@agaurav1 i (across 4ohm) = 6/4 =1.5A(upward direction). i (@20)= 2-1.5 =0.5A. V(@20) = 20*0.5= 10V. V(@R) = V(@20)- V(@4)= 10-4=6V. Apply KVL in leftmost loop. 17 - 10i-4=0. i= 1.3A. i(@R) = i - i(@ab)= 1.3-0.5 = 0.8A R= V(@R)/ i(@R)= 4V / 0.8 = 5 ohms.

[@kumarreddyyarram9574]

V @4ohm resistor is 6 volts right?

[@EEAnkitKumarPal]

@@nikhilnambiar4978 i@R is 1.8A

[@adityamandal2560]

sir if 2 nd problem if Rnl is given then by voltage division can we get Vnl ? then it become easy

[@PrinceKumar-bg5wc]

1) all zero 2)R=5ohm

[@tribhuwanpal9884]

Sir Ans of questions no 2nd is 5 ohm

[@geeta_ka_VANI]

what is the answer sir ..... as i am getting 7.80 ohm for 2nd question and all asked value is zero for 1st question please inform us

[@satishkumar-xw7fm]

First ckt are dade circuit and resistance of second ckt are 5 ohm

[@jsgtech2705]

How can u explain

[@Pariharnawab]

1) All are Zero 2) 5 ohm

[@gladiator8827]

sir 2nd ka answer kase niklega btado sir ho nhi rha h

[@soniayadav8849]

Sir , question no 6 me power deliver puch raha h ,toh us case me ans negative hona chaiye na

[@SanjayKumar-mq7zd]

First question all Ix, Vx, P all zero because there is no independent source 2nd question R=5ohm

[@souravmohapatra8139]

Can u plz explain how u got 5 ohm

[@saurabhpandey8683]

@@souravmohapatra8139 Voltage across 2amp is 6 volt . so Voltage across 4 ohm will be 6 too. Then use kcl at 4 ohm junction you get current in 20ohm as 0.5 .apply kvl in the middle loop you get potential at R is 4 v then in first calculate current from source which is (17-4 )/10 =1.3 amp .0.5 is across 20 ohm so remaining 0.8 is at R which produces 4 v =0.8*R

[@raziakhatoon9795]

@@saurabhpandey8683 thank u very much

[@electricalbyte8466]

Supab concept......

[@viaan9375]

Great sir

[@susmitakalidaha2958]

1st ckt is dead ckt so ix vx all 0 , second r has 5ohm

[@shubhamshukla5605]

First is dead circkt and second ans is 5 ohm

[@premkumar4786]

1 st ans all values 0 And 2nd answer is 5 ohm

[@SoulofHarmony]

explain please

[@mukeshkhinchi7366]

In first, is it ZERO or improper ckt.

[@aniketgarade1344]

Que 1) all are zero Que 2) 5 ohms

[@nikhilkumarch3258]

1st ans =all values are zeros 2nd ans=5ohm

[@mankaransingh7226]

plz share the solu of 2 ques how it come

[@miltonkumardas9972]

Question 2- R=5 ohm