Lecture - 17 Application of Stress / Strain

[@nityam1991]

ur 2 gud man... thnk a lot,, Ur lectures helped me a lot!!!!

[@pranav9339]

bruh u alive?!!!

[@imegatrone]

Your Video Is Very Useful Sharing Lecture Series on Strength of Materials

[@dipinjose9848]

how we obtained strain formula for hemispherical portion

[@adarshsachan7151]

Professor , in whole of this module why are u not taking the stresses in 3 dimensions to calculate strain .

[@preraksudan7322]

WHY longitudinal strain is considered as design criteria for safe operation, why not circumferential strain (Ref. Q2)?

[@onkarpatil6150]

Lower value must be considered for safe design.

[@pranav9339]

Refer to stress-strain curve. If longitudinal strain increases, at yield point, material starts yielding. Yielding sets plastic set into the material which can be extremely dangerous in engineering operations, because eventually reach fracture point. Hope I was clear.

[@rohitram533]

In ques 3, shouldnt it be gamma*g*h= P..... he has forgotten to mention g....

[@ketanpatel3710]

Rohit Ram ,he mentioned it and took it approximately equal to 10

[@Sheesh60]

Sir in q3 we can use concept of fluid which is given by p=h*Rhow*g is that simple guys 😊😊😊😊😊😊😊😊same ans will come thx to nptel which really increase our thinking power to like an perfect engineer 😘😘😘😘😘

[@tannuanthwal]

Brother i am seeing your comments throughout this whole series...nice work

[@Sheesh60]

@@tannuanthwal welcome 😊😊

[@suryavardhan4814]

can u elaborate some steps here