Lecture 19 I Question Discussion on Thevenin & Norton I Part 04 I Network Theory I GATE

[@GeniqueEducationTeam]

G saviour - To connect with pankaj sir join telegram - t.me/pankajshuklasir

[@azizahmad4013]

in question 3 .. independent voltage source must be short..then we can only apply analysis for getting rth

[@atulcreedsingh3257]

Thanks bro. By your help I got my answer👏. I was skipping this step while solving

[@aman12988]

But then also I am getting Rth value as 400 ohms and not 200 ohms bro..

[@umeshsingh-du3pk]

Of course we need to remove the independent voltage source.

[@kumarreddyyarram9574]

Pls somebody tell me why should we remove that

[@priya03_94]

Hello can you plz tell me why vth is coming 6V if we are considering 4V as main voltage ..like sir considered vth as main voltage.plz plz plz help me

[@priya03_94]

The best teacher for network😃

[@komalroy2831]

Are sirji you are genius 🙇🙏

[@SATENDRAPALPUNIYAN]

G-savior

[@mohdaqib784]

Sir mai aapse jaldi solve kar leta hoon wo bhi aap ke shikhae hue concept se thanks for basic sir

[@pankajshuklakakasir2969]

It's good dear

[@joyebkapadia2650]

Bhai sir samja rahe hai isliye nahi to unko aur kam time lagta

[@mohdaqib784]

@@joyebkapadia2650 haan bhai mai to bas itna kah rha tha I catch him very well in concept aur guru ji guru ho rahenge hum student hai aur sir se sekh kar hi aage badhenge sir ne bahut achche se concept aur basic me work kia bas wahi kah rha tha bhai

[@aman12988]

@@pankajshuklakakasir2969 Sir, in question 3, To find value of Rth using test voltage method I got Rth as 400 ohm and not 200 ohm.. Can u please provide solution for test voltage method of this question sir to get Rth.. please..!!

[@AMANSINGH-xj2vw]

What we will write on RHS (i.e on source side of eqtn) of nodal eqtn if that 1ohm resistance (in series to dependent source)would not have been there ...@time-9:29

[@manojmishra6202]

sir power system lecture bhi dijiye sir

[@asishdash5758]

yes sir i got the value by using test approach.

[@justanotheranonymousbeing]

How? I didn't get

[@sulthanaj7058]

How?

[@kashish8541]

@@sulthanaj7058 2 eq bnaegi: supernode concept sae v1+v2=it v1=4vt also v2=vt by solbing above you get vt/it=0.2 ohm

[@badarinathkodepalli462]

@@kashish8541 answer should be 0.2 kohm right

[@sajjadahmed5967]

U r gr8 teacher I salute u sir

[@shuvamdas3920]

Carry on

[@prashantsoni1956]

Awesome

[@neetuparihar7282]

shi bta

[@priya03_94]

Sir in question no. 1 ,when we are considering V1 AS THE MAIN VOLTAGE -WE ARE GETTING VTH AS 6V .WHY???

[@kushalroy2500]

sir in qus no.3 Vth will be 0.5mV. because Vth will be (1/2k). but you calculated as 1/2

[@GeniqueEducationTeam]

no dear its absolute correct. there will be no effect of kilo ohm as that will cancel out. watch the video carefully.

[@ashutoshkumarroy5726]

Ya it will be cancelled

[@RahulChauhan-ht8ol]

@@GeniqueEducationTeam sir please tell ques no 3.. To find Rth by test voltage ...i m getting 400 ohms

[@subratpal836]

@@GeniqueEducationTeam thank you sir!! ?Your lectures are great!!

[@umeshsingh-du3pk]

Most probably awesomeness is chasing you so that he could catch up with you. Fabulous

[@sachinwajewaje]

Thank you so much sir ❤

[@CHANDANKUMAR-bn1mi]

G- saviour

[@pravinsharma9634]

awesome sir

[@priya03_94]

Sir can you please take V2 first and then calculate the vth ???because when I am considering V2 ,m not getting the solution....sir please help me. I am doing like this V2(1/20+1/10) - V1(1/10) =0

[@adityaranjannayak6339]

Same problem I think sir missed that 20 resistor part which is connected to that node

[@soujanyamohanty9524]

Thank you so much sir

[@cop_vlog]

Sir same ans aa gya h by universal approach

[@animo5445]

How?

[@amrajamarnath7952]

Yes sir I got the answer through test voltage as 200ohms

[@RahulChauhan-ht8ol]

Please tell me ..i m getting 400 ohms by test voltage method

[@aman12988]

I am also getting 400 ohms.. How are u getting 200.?

[@umeshsingh-du3pk]

AMAN PATHAK V1=Vt V2-V1= 3Vt Write equation at node V1. You'll get

[@badarinathkodepalli462]

sir by test voltage method i got 0.2 ohm

[@forcompetitiveexam5041]

can you post a pic of geeting answer through test voltage

[@swapnilchandrakantbanduke9088]

its .2 kilo ohm not ohm

[@sonalsingh6046]

Luv u sir and I m big fan of urs

[@ankurverma4899]

05:45 To find Rth why 20 ohm rasistance removed what is the reason behind this??? Reply someone.....

[@umeshsingh-du3pk]

Ankur Verma there is a short path, so current will flow through short path, so we can remove the 20 ohm.

[@shivshankersinha969]

VT is 0.5v and Rth is .25kohm

[@santanu6763]

🙏🙏🙏

[@anjalibharti790]

Sir mera test voltage se answer nhi aa rha question 3 me ,eqn me 5/2 aa rha vt aur it ke relation me, kaise solve kru

[@abhilash29130]

In test voltage approach we have to short the independent voltage source..so there is no 5/2v will occur and u will get the answer of 0.2kohm.

[@satyasp751]

@@abhilash29130 you r right bro

[@beautyofindia9769]

By test voltage method I got same answer

[@deepanshuchoudhary689]

I also tried test voltage method and got vt= 0.5v but getting current value equal to zero. Will you give me solution ?

[@technicalconsultantpoint]

I m not getting the same soln by test voltage method in ques2

[@umeshsingh-du3pk]

Deepanshu Choudhary you don't need to calculate Vt, calculate the ratio between Vt and It.

[@sulthanaj7058]

I am also not got the same answer for question 2

[@shrinivasadn5187]

0.2k ohm answer is coming

[@sulthanaj7058]

Anyone getting question no3 test voltage source method? I am not getting answer pls any one slove

[@kashish8541]

help me as well

[@kashish8541]

i got the ans

[@arjunpanwar77]

Thank you so much sir..

[@SurendraKumar-ns9xt]

awesome