LECTURE 2: JEE SERIES FULL SYLABBUS | SYLLABUS INTRODUCTION AND EXPLANATION BY TUSHAR SIR

[@h4rry934]

29:34 Question Velocity(V)= u+at =0+3x4 (V=12m/s) Displacement(s)= ut+½at² =0x4+½3x(4)² =0+½48 =24m

[@munirajraut9901]

30:01 velocity=12m/s Displacement=24m

[@nilimakadbe4494]

30:17 final velocity = 12 m/s Displacement = 24m

[@nilimakadbe4494]

30:17 Explanation.. take initial velocity (U) =0 Put The values in eq V= U + at Then after getting V put the values in the second eq S=Ut +1/2 at²

[@RanjitGupta-o4y]

30:00 given:- acceleration = 3 m/ s^2 time = 4 second. Initial velocity= 0. Final velocity = ? Displacement = ? 1) V= u+ at ....formula v= 0+3m/s^2 × 4 s. V= 12 m/s. 2) s= ut + 1/2 at^2 ...formula. S= 0× 4 sec + 1/2 × 3 m/s^2 × (4s) ^2 =0+ 1/2 3 m/s^2 × 16s^2 = 0+1/2×48 =0+24 m S=24 m

[@munirajraut9901]

30:01 v= u+at S=ut+1/2at^2

[@rajukadbe5622]

Velocity by v=u+at, Displacement by s=ut+1/2 at^2

[@rajukadbe5622]

Final velocity=12 m/s Displacement=24m

[@rajukadbe5622]

In middle of hypotenuse line

[@NarendraNarnaware-91]

30:07 Final velocity = 12m/s Displacement = 24m