I am still confused about what happened in 28:40. Why can we just simply add something to the left and then change the inequality the other way around?
@thierryrioual7014 ай бұрын
Because that's the definition of the infimum: For all a in A, and for all epsilon > 0, a - epsilon < inf A =0, and epsilon >0, epsilon/2^k > 0. See "Infima and suprema of real numbers": en.wikipedia.org/wiki/Infimum_and_supremum Normally the inequality is strict but by taking epsilon arbitrarily close to zero the inequality becomes loose.
@asbjrnandersen47653 ай бұрын
lambda star is the infimum of the RHS. thats why adding a number greater than zero flips the inequality
@HuggableJohnАй бұрын
If you add a positive number to the greatest lower bound of a set, that number is no longer a lower bound of the set.
@TheMorhaGroup3 ай бұрын
"I hope you're as excited as I am😐😑😐"
@darrenpeck1562 жыл бұрын
Could this criteria lead from countable subadditivity to countable additivity?
@thomasjefferson622510 ай бұрын
disjoint unions for countable additivity
@nicholaskhawli43303 ай бұрын
Isnt finite union concluded from the 2 sets union proof ? I guess u could prove it but shouldnt it be trivial
@nicholaskhawli43303 ай бұрын
Why use inequality and add the epsilon if we will just equal it to zero . Then why not just use equality .