Topics covered: - Inner Product of < x | p > ~ e^{ipx}, - Position Wavefunction Momentum Wavefunction by Fourier Transform. - Generalizing the entire discussion to 3D (was upto 1D till now). - Schrodinger's Equation - separating the time variables out of it by writing down solutions for stationary states. - Time-Independent Schrodinger Equation as an eigensystem equation for the Hamiltonian operator. - Setting up the One-Dimensional Particle in a Box problem (continued in the next lecture).
@bookofspirit5 жыл бұрын
Thanks a ton!!
@saketpanigrahi5 жыл бұрын
Thanks
@Rohan_Choudhary54 жыл бұрын
Thanks brother
@bipinsonawane531210 жыл бұрын
Please share this series of lectures in all institutes where science is taken seriously.This is the real wealth . This is real need for a student who wish to do science at a deeper level.Thanks all for unexplainable hardword taken to do this work.Of course, Prof. thank you.
@gouranggehlot48964 жыл бұрын
Finally Balakrishnan sir made a mistake at 40:09(it's a relief, he is human too), it's overlap between state at t=0 and the energy eigen state not the position eigen state.
@sci-informatics35074 жыл бұрын
It overlaps with the stationary state. Prof. Balakrishnan describes at 32:00
@varunshrivastav88763 жыл бұрын
@@sci-informatics3507 so he's not human after all
@ayeshakawakil8452 жыл бұрын
@@varunshrivastav8876 this professor is blessed with Krishna himself...I am from Rural Bihar and professor literally has turned me to a scientist
@IamAdarsh14143 ай бұрын
😂
@UORA7514 жыл бұрын
The lecturer cleared out lot misunderstood priciples I had. Thank you for the video. I studied all those in Shankar's book but it wasn't so clrear and straight forward for solo-learning.
@qlw1513812 жыл бұрын
This is a Master Teacher at work! Great lecture!
@abhishekpatra38164 жыл бұрын
The way he predicted the energy eigenvalues at the end by using bohr's uantization and phase space is so awesome and awestrucking......i have never seen anything like that. Woww......😂😂😂
@metuphys56116 ай бұрын
that "what the hell" at 40:30 had me weak fr fr
@frankieli9811 жыл бұрын
he's so inspiring. I feel like I am in India right now.
@karthickraja685411 жыл бұрын
He is real teacher. That's Inspiring ...
@mahesh317927 күн бұрын
particle in box 🔥🔥🔥🔥🔥🔥🔥
@vivekpanchal33389 ай бұрын
Particle in a 1D box starts at 5 50:28
@sandeeppatidar1106 Жыл бұрын
Amazing lecture
@BHA76195 жыл бұрын
Thank you Sir, your work is priceless!!
@GhostFaceK1ll3r16 жыл бұрын
I love it. Keep it going brother!
@IamAdarsh14143 ай бұрын
🙏🙏🙏
@TheManglerPolishDeathMetal12 жыл бұрын
indeed it is
@pramod1208954 жыл бұрын
Can anyone explain coefficient part in 39:59
@mathieumaticien4 жыл бұрын
I don't get that either. Did you figure it out? Also how do we even know that we can write the general state Psi as a combination of the eigenstates of the Hamiltonian?
@pramod1208954 жыл бұрын
@@mathieumaticien Actually it's overlap between state psi and stationary state phi(n) @ time 0..not with position.. Since stationary states form complete set of eigenkets any vector in Hilbert space can be expanded as linear combination of these states with appropriate coefficients.. Since it is constant hamiltonian stationary state at time t is given by initial state psi n (r, 0) multipled by evolution operator given by exponential of eigen value..
@mathieumaticien4 жыл бұрын
@@pramod120895 oh i see that's very simple, you just take the inner product of Psi(t) with Phi_m(t) and use orthogonality of the eigenstates... How does one know Hamiltonians are Hermitian and the spectral theorem is valid?
@pramod1208954 жыл бұрын
@@mathieumaticien Hamiltonians are just function of position and momentum operators which are real (mathematically). thus complex conjugate transpose is also same as original operator and thus it is hermitian. (of course it has rigorous mathematical proof) Thus any hermitian operator have complete set of orthonormal eigen vectors with real eigen values and spectral theorem is valid ie sum of (ket(A)*bra(A)) =1 where A's are eigen vectors
@007acreed8 жыл бұрын
awesome....sir
@mikel52645 жыл бұрын
If the eigenvalue is the actual value of the physical observable, what is the physical meaning of the eigenstate? Is it a 'vector' of the state of the system with all possible values for that particular observable? Thanks
@MrNerdpwn5 жыл бұрын
An eigenstate has no physical meaning. It is an abstract mathematical concept. Only physically meaning things are the eigenvalues of observables and the inner products (probability amplitudes).
@fazleyahmad82397 жыл бұрын
very nice lecture sir
@20shourya14 жыл бұрын
@charbi88 r u sure man? not undergrad?
@tanmaysingal05 жыл бұрын
Correction: c_n = < \phi_n | \psi (0) >, not < r | \psi(0)>. (kzbin.info/www/bejne/jJC6f2eYiJ2Zars)
@navalrsabe70155 ай бұрын
completely, uncertain to me
@abdulwali23477 жыл бұрын
anyone tell me , which book sir follow ?
@stoksc7 жыл бұрын
i think it's sakurai from what he's teaching.
@ashishnayak20207 жыл бұрын
Quantum physics by hc verma also states in same manner