Lecture - 9 Quantum Physics

  Рет қаралды 67,653

nptelhrd

nptelhrd

Күн бұрын

Пікірлер: 35
@yamansanghavi
@yamansanghavi 7 жыл бұрын
I enjoy this more than a movie. Prof. Balakrishnan is GOD LEVEL.
@abdou290
@abdou290 13 жыл бұрын
excellent teacher. Better than MIT courseware. I wish I had teachers like him in my higher education. He is not using any paper or notes. Amazing!
@nonporous
@nonporous 14 жыл бұрын
Wow looking at the square well in the momentum basis was very enlightening! These lectures offer a lot more depth than any professor I know, it sure is better than reading Griffiths too.
@hahahamatsuyama9408
@hahahamatsuyama9408 9 жыл бұрын
He is definitely without ''uncertainty principle'' the best teacher I have ever encountered, he even notice the space topology itself, which is the underlining assumption we all take for granted, and ask the influence of the topology on the restrained condition!!!
@Shanu-v3e
@Shanu-v3e Ай бұрын
Prof v Balakrishnan ❤
@ManojTiwari-ky3fl
@ManojTiwari-ky3fl 8 жыл бұрын
Lecture 09: The particle in a Box ( 1D, 2D, finite well, delta potential)
@tanmaysingal0
@tanmaysingal0 5 жыл бұрын
There's no delta-potential in this one.
@nickpreetic4670
@nickpreetic4670 3 жыл бұрын
@@tanmaysingal0 yes there is, particle in a box is given by a delta potential at either end of the box to prevent its escape
@tanmaysingal0
@tanmaysingal0 3 жыл бұрын
@@nickpreetic4670 a delta-function still allows escape. What you mean is an infinite barrier to either side of positive potential energy. That isn't a delta function.
@tobiramasenju4549
@tobiramasenju4549 14 күн бұрын
​​Lol thats basically the delta potential. Stop yapping pa*j**t​@@tanmaysingal0
@sumanthdontharaju2073
@sumanthdontharaju2073 8 жыл бұрын
What a wonderful, wonderful lecture! Thank you Prof Balakrishnan, It was a delight watching your lectures in Quantum Mechanics
@collegev
@collegev 11 жыл бұрын
the insight of why all the eigenstates of the hamiltonian are not eigenstates of the momentum operator was shattering! and it was especially delightful because i guessed the answer as prof b was pushing hard to get the answer from the students in the class "somewhere in there i made a statement that is not correct. what is it?" this is what effective pedagogy is. prof b is what they call a rishi or a sage in india.
@sahil9547
@sahil9547 2 жыл бұрын
Last line 🙌🏻
@saikatsantra3770
@saikatsantra3770 3 жыл бұрын
There is no degeneracy in one dimensional problem provided the underlying space is simply connected, the circle is not simply connected. So particle in a one dimensional ring has degeneracy and it is actually doubly degenerated… very nice
@AlexandreHefren
@AlexandreHefren 12 жыл бұрын
1 hour of video = at least 2 hours to watch ant take notes. U.u
@ayeshakawakil845
@ayeshakawakil845 2 жыл бұрын
Professor Balakrishnan is 🔥, love you from Bihar
@chiragsharma5050
@chiragsharma5050 11 ай бұрын
Iam from electronics can I directly start qm from here?
@Raj-gc2rc
@Raj-gc2rc 13 күн бұрын
@@chiragsharma5050no I don’t think so unles you have all the prerequisite mastered
@pradhumndixit7353
@pradhumndixit7353 5 жыл бұрын
Wow ❤ Great sir ....enjoying quantum mechanics first time
@DaveJohnsonsuvam
@DaveJohnsonsuvam 11 жыл бұрын
i dont know if shankar is inspired from balakrishnan or its the other way round .. but both of them approach the subject efficiently and in a similar manner ..
@pranavgupta2138
@pranavgupta2138 4 жыл бұрын
Aag laga di sir ji ne🔥🔥🔥
@frisknikki
@frisknikki 4 жыл бұрын
fabulous lecture but fantastic in 16th minute....
@03Kabbotta11
@03Kabbotta11 12 жыл бұрын
So Balakrishnan's course is based off the Principal's of QM book by R. Shankur from Yale or are you referring to a different Shankur. I've always wondered this, and where did you hear this if you don't mind.
@gouranggehlot4896
@gouranggehlot4896 4 жыл бұрын
It looks like that but the treatment of shankar is not as abstract as Balakrishnan and there are certain things you get in his lectures which aren't in the book and vice versa.
@AmanGupta-fd6ig
@AmanGupta-fd6ig 6 жыл бұрын
@1:0:04 in the wave function part of the rectangular box shouldn't be 2over \sqrt(L_1*L_2) ?
@Hkj2000
@Hkj2000 3 жыл бұрын
Yes
@sahil9547
@sahil9547 2 жыл бұрын
Yes
@akshayeds2957
@akshayeds2957 6 жыл бұрын
at 32:00 it's negative not plus
@Vercongent
@Vercongent 11 жыл бұрын
Question: When defining the potential he said it is 0 for 0
@burhan8795
@burhan8795 10 жыл бұрын
all possible eigenvalues of the of the position operator
@maujo2009
@maujo2009 14 жыл бұрын
@nonporous Read also Sakurai.
@PetraKann
@PetraKann 2 жыл бұрын
A 1-D box?
@swasasheeru
@swasasheeru 15 жыл бұрын
great, thanks
@goutamrajkumar14
@goutamrajkumar14 11 жыл бұрын
good
@deepmondal323
@deepmondal323 6 жыл бұрын
God
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