Lesson 14: Algebraic Manipulation

In this lesson, we will look at some examples of how to manipulate boolean expressions and perform boolean proofs.

[@alextee2161]

Still helping others 7 years later. Lovely man, thank you.

[@puru3197]

This was very helpful, but I have a question, how was BC canceled out in AC+A'B+BC?

[@Massimus888]

He explained this in the first example. AC+A'B+BC=AC+A'B+BC(A+A')=AC+A'B+ABC+A'BC=AC+ACB+A'B+A'BC=AC(1+B)+A'B(1+C)=AC+A'B

[@robingadney4678]

sorry bad audio looks good its a pity

[@fabbymiles2906]

Thankyou so much pal, that was really helpful

[@samdorcely4996]

That was so helpful. Thank you so much!

[@safaaal-moqbali2434]

how you eliminate BC in the last Q??

[@haroonkhalidjanjua5427]

why didn't u consider AC a redundant? ac is also getting ored with the complement part.

[@lkw5050]

Hi! Loving your videos. Are you able to help explain to me how/why A+A'BC is able to be simplified as A+BC? Thanks!

[@digitalsystemsexamplesands9032]

+L&K W I'm glad you're finding the videos helpful. This is done with the distributive property with says that X +YZ = (X+Y)(X+Z) So for this example we have: A + A'BC = (A+A')(A+B)(A+C) = (1)(A+B)(A+C) = (A+B)(A+C) = A + BC Hope this helps!

[@kyomugasojovin8183]

Hw did u eliminate bc in the last example

[@upenyumudzingwa2551]

can you please help (ABC)' the compliment of that