I'm happy and grateful to find this gem 💕, thanks!
@sheilachandler19 жыл бұрын
You are AWESOME!! Thank you so very much. Your videos are very informative and very good quality!!
@AhmedMarzookisabeast6 жыл бұрын
Thx a million man really helpful and useful
@farooqshah4u12 жыл бұрын
Thanks alot ! it was a great help .
@master3395111 жыл бұрын
What video recording program are you using? to record your self and your desktop?
@alexssandrolima9 жыл бұрын
Muito bom e fácil de aprender.
@miftahbedru54311 жыл бұрын
Good Job ... But , in addition to denying the user from typing the wrong input ( number or text), it is good if we can also notify them by displaying message ... i said this because people my enter input in a user name text box for example , i may type myid56 , the system will read only letter and ignore the digits , if i did not notice this and move quickly .. i feel my user name is myid only and i may not log in, especially if i was doing signup ...
@akosiDAN12312 жыл бұрын
Glad to know it help :)
@wandseu8 жыл бұрын
salamat ng marami 😁😁😁
@mytedico4 жыл бұрын
Hi Mr AKOSI DAN are you not making any videos on VB.net programs
@AdnanVlogs847 жыл бұрын
please tell me how to prevent from duplicate character in a text field for example in a text field where we are writing string value and we want to enter "." (dot) key only once & repitation is not allowed
@jophelcyrusibasan39778 жыл бұрын
how about accepting special characters like dash and apostrophe ? for example "O'Hara-Hara" how to code it? please answer asap
@kwharton011611 жыл бұрын
very helpful
@carlofernandez36968 жыл бұрын
idol! thanks you!
@carmenlim561812 жыл бұрын
thanks! =) just had a nested IF for d BS and SP, wit e.handled set to false in VB.net.
@euphoric-617710 жыл бұрын
Thanks man! So easy once you know :) Btw change numer to number :D
@UCHS_CH8 жыл бұрын
helped a alot ,thnkx
@sunepjamir59389 жыл бұрын
i want to know how to use space after enter some letter....for example like "you are good"but in this it work only youaregood
@EnimaIffets9 жыл бұрын
Hi my friend more easier is: e.Handled = !( char.Isnumber(e.Keychar) || e.Keychar == 8 || e.Keychar ==32) ; You don t need short hand expression at all :-) Try it !