Limit of x*sin(1/x^2) as x approaches 0 (Squeeze Theorem) | Calculus 1 Exercises
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@WrathofMath 5 ай бұрын
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@punditgi Жыл бұрын
You always manage to squeeze the truth out of these limit problems! 😊
@WrathofMath Жыл бұрын
That's the goal! To let the mystery of these problems approach zero!
@punditgi Жыл бұрын
@@WrathofMath Nice! 😆
@user-wr4yl7tx3w Жыл бұрын
do you have a video explaining how the inequality flips depending on the negative sign and direction?
@WrathofMath Жыл бұрын
I do not, that could be a good shorts video. When we think about a number on the real line, multiplying it by -1 will reflect it to the opposite side of 0. So when we multiply a whole inequality by a negative, all numbers are reflected to opposite sides of 0, and so then their positions relative to each other are opposite.
@punditgi Жыл бұрын
@@WrathofMath Nice explanation. Thanks!
@Renata-sy3kg Жыл бұрын
why aren't you using the inequality 0
@KlerisHysenaj 21 күн бұрын
did you used chat gpt?
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