Thanks. This is way simpler than khan academy's video.
@Dirtfarm2310 жыл бұрын
I'm so glad that you exist
@Dnttashme9 жыл бұрын
omg better than damn khan academy
@AndrewMaksym9 жыл бұрын
+Little Bird yeah I wish they'd add more visuals to kahn academy instead of just writing on the chalk board ):
@madelinebade20866 жыл бұрын
Khan Academy doesnt help at all, this does
@cookiemoncook5 жыл бұрын
8 years ago this vid was made and I just learned how I am gonna pass my chem quiz, thank you sooo much 🙏
@iffatjahan53059 жыл бұрын
I usually watch Khan Academy videos, but the ones on limiting reagents are REALLY confusing. Thank you so much!!
@toadsagesev8 жыл бұрын
Thank you so much. This is definitely waaaay better than Khan Academy's confusing videos.
@nightfox3808 жыл бұрын
Your videos are sooo much better thank Khan Academy's. I can't thank you enough for all the videos you make.
@MultiBattleblader5 жыл бұрын
I was wondering where you got the actual yield from, but then I realized that it would be given in the question. Thanks for the help!
@liavbar92183 жыл бұрын
You helped me just as much as the video did, thank you!
@jessebeso81439 жыл бұрын
OK, I love you. I spent 3 hours on a limiting reactant problem. It happened to be the same one that I have come across on your video. Thank you! I now know how to work it out. Your the best.
@invnn12 жыл бұрын
I have been looking up a lot of these types of examples here on youtube. your example has the best presentation by FAR
@fallingwithoutfear113 жыл бұрын
THANK YOU! been struggling with this concept. and you always seem to know how to word it for me to understand, yet again, thank you so much Mr Anderson!!
@spav9513 жыл бұрын
You're really saving me the hassle of reading old notes. I attribute any sort of positive grade to you, sir.
@jsy78810 жыл бұрын
Priceless. Great. Concise. Excellent.
@parkjnine12 жыл бұрын
please make more videos on general chemistry! you explain it better than my college professor
@TheFatbaboon7 жыл бұрын
This guy explained finding the percent yield and limiting reagents better in a 9 minute video than they do in several hours of school.
@rebecarauda12010 жыл бұрын
Thanks so much! The explanation is very clear so this was very useful for a lab I had today.
@TheDeltaexpeiment9 жыл бұрын
I would just like to quickly thank you for this. I am so tired by the time chemistry comes around that I do not retain any thing my teacher says.
@JoeKavana8 жыл бұрын
Thank you Mr. Anderson.
@alliewade5098 жыл бұрын
Where did the 6.19 come from?
@jadenw47279 жыл бұрын
You are amazing, thanks for helping me pass chemistry
@guitarwizard200010 жыл бұрын
Thank you so much for making this. This clarified so many things!
@KabooM106711 жыл бұрын
Please someone answer this question, I got a problem where the actual yield isn't mentioned.. is there a way to calculate it or is it always given? Is it a mistake in the question?
@SplosionMovies9 жыл бұрын
shoutout to Mrs. A for reccomending this channel
@46562jlarson12 жыл бұрын
Yes, I understand now...my college prof. went way too fast, and I didn't understand...thank you. :)
@TheBuffalodiver11 жыл бұрын
Thank you for your insightful presentations
@akyaford13 жыл бұрын
Great video! Thank you for your help. Will definitely be watching again. You make it seem so easy:)
@aksmith20017 жыл бұрын
This was extremely helpful until the ending. So how exactly do I get the actual yield?
@MehDragon9910 жыл бұрын
This video is so helpful thank you so much! :)
@lalisaluhme10 жыл бұрын
where did 6.19 come from ? :(
@Whaheyyy10 жыл бұрын
He is just using 6.19 as a random number to create the example. Even though 6.88 grams is the actual yield, or rather the maximum yield achievable; in real life this perfect 100% yield will never occur and it is more common for something like 6.19 grams to actually yield. Thinking in another way, if a chemist was particularly bad...they might get something like 3.90 grams yield where the percentage yield would be 57%...as compared to the 90% from 6.19grams
@DogeFrom20149 жыл бұрын
Darwin Peczek Or maybe he actually did a real lab experiment involving the chemical reaction and got actual results. That's how we did it at school.
@gerbil7red3276 жыл бұрын
well how the fuck do you even find the actual yield, didnt really help
@claireboo57796 жыл бұрын
THANK YOU I looked up so many videos
@merrionrabbit352811 жыл бұрын
your amazing!!!!!!!! i understandthis now!!!!!!!!!! (after weeks of struggle)
@TTKarlheins12 жыл бұрын
Seriously! great work! the visuals help ALOT as well :) THANK YOU AGAIN. P.s. Are you serious about wanting someone to remix this video (as you 'remix this video' button suggests?) Cause i'll do it! I'm not even scared!!!!
@buildbearworks83964 жыл бұрын
I like the way he explained the limiting reactants but how you found the actual yeild was quite unclear.
@954bballer12 жыл бұрын
this was magical. thank you
@bluedevilsacc13 жыл бұрын
thanks Mr Andersen
@exzisd10 жыл бұрын
I'm guessing you rounded 3 significant figures at the end for percentage yield. My raw data was approximately 89.97% so rounding 3 SF would be 90%.
@RealChemistryVideos8 жыл бұрын
Great videos!
@gustafson20169 жыл бұрын
I wish you were my chemistry teacher!
@RosaLopez-cw8me9 жыл бұрын
Why do you multiply by moles and grams of CO2? Why not multiply by 2H2o? I don't understand that part.
@roykilof52048 жыл бұрын
This helped me a lot! Thank you
@bishnughorasaine55449 жыл бұрын
its reall helpful u know so helpful
@bethanywilms89133 жыл бұрын
super helpful!! Thank you!
@monaycoon66988 жыл бұрын
How do you find the actual yield of 6.19g of CO2?
@IcyXcandi41111 жыл бұрын
Extremely helpful!!!
@mamba2887410 жыл бұрын
How do you find the Excess Reactant? I have a question after finding the LR, it asks, How much excess reactant remains after the reaction has stopped?
@chriswhitmire416710 жыл бұрын
The excess reactant is the other reactant that is not the limiting reactant. In his example the limiting reactant was oxygen, so the excess reactant is methane. It is called the excess reactant because there is some of it left over after all of the limiting reactant has been used up
@2kAllDay14410 жыл бұрын
basically what hes saying is that you have to subtract the limiting reactant to the excess reactant.. which in this case would be 27.4g - 6.88g = 20.52g of excess left over.. hoped it helped.
@mamba2887410 жыл бұрын
Chris Whitmire Thank You! :)
@mamba2887410 жыл бұрын
The Beast14444 Thank You! I understand it now :)
@jessisingh8628 жыл бұрын
Cue the school bell woke me up real fast
@MrMexicanPunker11 жыл бұрын
where did you get the 6.19g of CO2 of the actual yield? Will you be given that in a question or do you have to solve that some other way?
@gotsomejams95403 жыл бұрын
Thank you, this helps.
@ericmaz786 жыл бұрын
thank you matt damon
@jackbennett22698 жыл бұрын
I'm here bcuz mr hale
@nxd114111 жыл бұрын
you are the man!
@katewhitacre26179 жыл бұрын
I'm confused because he said that methane was the limiting react ant but then he said that oxygen was?
@briantrek12 жыл бұрын
thumbs up if this is the best graphical representation of the concept
@KD-vu7om11 жыл бұрын
Wow. you are amazing.
@kamylleconsebido3767 жыл бұрын
How did you get the actual yield? Is it already given?
@amitgodara69859 жыл бұрын
limiting reagent was understood but i don't get the predicted yield and actual yield
@icemanzoom95410 жыл бұрын
Very Helpful.
@VSAngelForever9 жыл бұрын
Amazing!
@henrg5 жыл бұрын
The GOAT
@kerrywisher874511 жыл бұрын
Regarding your limiting reactants video. I followed the 4 blocks format you had shown. but it didn't work. My problem was-" P4 + 6 CL2 ----) 4 PCL3. How many grams of PCL3 could be obtained from 5.62g of P4 & 15.2g of CL2? I got 24.9g PCL3 for the P4 sample and 118g PCL3 for the CL2 sample. The correct answer was, there was not enough Cl...and it was 19.6g PCL3. I think I may have added a step...grams to moles step perhaps...im not sure. But it was certainly wrong. Any help? thanks.
@kathrynnolan19075 жыл бұрын
It was 19.5g PCL3, you rounded your significant figures wrong.
@adrianpham84299 жыл бұрын
say I have 2 Au and 2 is the coefficient, do i multiply Au twice by it's atomic mass?
@xy27413 жыл бұрын
i get it, and my chem class isn't even up to this yet.
@christineaustria77713 жыл бұрын
Thanks❤
@atreyuXx211 жыл бұрын
this increased my knowledge. and my hunger. *sighs*
@johnatkins14845 жыл бұрын
This guy looks like crash course guy
@gracelee356110 жыл бұрын
I LUV U UR THE BEST BOZEMAN
@johnkevin110410 жыл бұрын
his voice makes me sleepy...
@davidlxxiv4 жыл бұрын
Yessss dude
@unruly_kween36513 жыл бұрын
why can't you be my BIO and CHE professor
@RpkRunningfox11 жыл бұрын
and i am screwed
@iknowmewhoareyou26159 жыл бұрын
cue school bell?
@Izeezus9 жыл бұрын
Usually when Chemistry teachers are at that point during the LR lesson, the bell rings in the middle of the lesson, causing the students to leave class, and leaving the lesson while it's still being taught. It implies that Limiting Reactions take a while to calculate.
@DogeFrom20149 жыл бұрын
***** Lol doesn't really seem true, but still a nice analogy.
@MagentaFerret9 жыл бұрын
1:41 should be thrust, not lift.
@ronaqsahni53435 жыл бұрын
Irrevelevant to the topic in question. So who cares?
@fruittart37307 жыл бұрын
Oh god idk why but I'm so lost
@beanzaru11 жыл бұрын
this still was sort of confusing to me
@beanzaru11 жыл бұрын
but oh well that was in the past so i guess it doesnt really matter
@NLaw-uo5uk8 жыл бұрын
what is that "cue school bell?" it is horribly distracting and annoying. very nice video outside of that.thank you
@summergurlie9711 жыл бұрын
so I now understand this
@NewTub3r19 жыл бұрын
Always
@paulhoudeville42442 күн бұрын
Vive le tremplin !
@nightmindr13 жыл бұрын
great video, great help; get rid of the bell and the huge popup; it distracting and totaly anoying.
@augurelite13 жыл бұрын
Coolio
@fedyakot9 жыл бұрын
Haha- reagent
@paulmckenzie600812 жыл бұрын
I'm paying for a class that I have to go on the internet and find people that can teach it BETTER for free... college logic?