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@ujjawalbaranwal47255 жыл бұрын
Sir GL(2,R) me aapne + ke according identity hatai hai (for proving abelian wrto matrix multiplication )...magar isme to pahle se hi restrictions the ki ad-bc not equal to zero ,then isme 0 matrix hatane ki jaroorat nhi thi ....at 11:36 .please reply sir ....🙏🙏
@kunalthaker62364 жыл бұрын
Sir can u prefer the name of all book for jam in easy language
@kunalthaker62364 жыл бұрын
Sir plse reply
@prernatyagi49015 жыл бұрын
Sir 3rd distributive property thik nahin lg rahi. ( R+ , * , •) ko vs bhi disprove kar rahi hai
@rajanprajapati57445 жыл бұрын
Yeah
@pathakmanish98115 жыл бұрын
GL(2,R) WITH ADDITION, IDENTITY KHA EXIST KAREGA??
@arunpanwar26094 жыл бұрын
Sir, Muje pura course nahi chahiye ,, muje keval "Linear Algebra" ke video hi chahiye ,, I mean ki me keval Linear Algebra ke video ke liye pay kar sakata hu kya ... 😊
@mathematicalPathshala4 жыл бұрын
Yes you can take, it is available on our application play.google.com/store/apps/details?id=co.lynde.unflv
@AnjuAnju-tx9qz6 жыл бұрын
Sir field ka aapne jo 2nd example diya h usme 2nd operation ke w.r.t. commutative toh nhi ho rha(a^logb#b^loba).thank you
@mathematicalPathshala6 жыл бұрын
Dono same h verify
@AnjuAnju-tx9qz6 жыл бұрын
@@mathematicalPathshala thanku sir
@soumitreemishra80605 жыл бұрын
General linear group to nonzero det he , app jo uska subset bol rahe ho wo zero det he, toh wo subset kese hoga
@rajanprajapati57445 жыл бұрын
Bhai sir sahi hai, apko abhi iska concept pata nahi hai modern algebra ke lecture me defined hai
@vasundharakulkarni80185 жыл бұрын
In property (alpha + beta) # u = ( alpha # u ) + ( beta # u ) it should be like this.. Right? Instead of ( * ) there will be ( + ) If it's not, then please explain...
@gourishankarsahoo5185 жыл бұрын
In external binary operation Why field element take scalar
@mathematicalPathshala5 жыл бұрын
We just call them scalars only not they are scalar always,,
@vidhimittal46975 жыл бұрын
Sir, do you provide complete video lectures for CSIR NET? If yes, what is the procedure to buy them?
@mathematicalPathshala5 жыл бұрын
No
@harishkhrethalia18745 жыл бұрын
Whats application its we can see in daily life
@trishanksaharia5 жыл бұрын
Sir (G,+) ki identity element zero matrix Hain. Toh how can that identity matrix belong to G since G has a special condition for non zero determinant and if zero matrix belongs to G then that condition fails. Thus (G,+) is not a Monoid. Can u please clarify?
@vidhimittal46975 жыл бұрын
Yes you are absolutely right. General linear group forms a group under "ordinary matrix multiplication"and not ordinary matrix addition. Hence, (G,+) will not form a group and thus (G, +, .) will not form a field. There is no need to check whether (G*, .) forms an abelian group.
@shiwamsingh88935 жыл бұрын
Exactly I have same question
@ujjawalbaranwal47255 жыл бұрын
@@shiwamsingh8893 ya
@ARUNYADAV-nz1dl6 жыл бұрын
Sir aap linear algebra pura pda dijiyega n sir ??
@mathematicalPathshala6 жыл бұрын
Will try my best
@shubhamsinghyadav53106 жыл бұрын
Thku sr g apka bhut bhut sukriya ..
@vishakham62065 жыл бұрын
Sir m.sc Kae liyae bhi hae ye
@mathematicalPathshala5 жыл бұрын
For Msc and phd entrances only
@harishkhrethalia18745 жыл бұрын
Sir daily life example of vector space and where this uses
@sikandarburnwal18345 жыл бұрын
Aap ek mic ka use karo sound vibrate ho raha h😓😓😓😓😓
@adityaraj10935 жыл бұрын
sir mai av 12th pass out huaa huu or mujhe is topic ka kuchh term and theory samajh me nhii aarha haii sir mai kis topic se apna jam ka preparations start kree sir... plzz plzzz jaroor recomend kre sir...
@nikhilsrivastava64285 жыл бұрын
sir private video ki fee kitni h?
@mathematicalPathshala5 жыл бұрын
Visit at mathatical-pathshala.com
@rajakishormohapatra68455 жыл бұрын
Plz sir can you check the property 3 under external composition. Thank u sir nice video i enjoyed.
@ARUNYADAV-nz1dl6 жыл бұрын
Sir (Q*,+,•) ; (R*,+,•) ; (C*,+•) n field hoga ??
@mathematicalPathshala6 жыл бұрын
Addion k respect me identity ni h so not even group under addition so not a field
@soumyadas96755 жыл бұрын
Thanks sir
@pirehdoll15495 жыл бұрын
Plz clearly define all properties with solution because it is difficult for me to understand identity and inverse property😔
@VikashKumar-bb5fi6 жыл бұрын
Thanku sir
@gourishankarsahoo5185 жыл бұрын
Why a vector space defined on a field not an integral domain
@mathematicalPathshala5 жыл бұрын
That is totally different concept such as we difine such structure over ring that is called modules
@gourishankarsahoo5185 жыл бұрын
@@mathematicalPathshala plz describe
@mathematicalPathshala5 жыл бұрын
Read the definition of module,, then u will understand we can make different different structures