Lithium Aluminum Hydride LiAlH4 Reduction Reaction + Mechanism

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Excellent explanation.kindly upload more lecture.

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[@svnspell6709]

Hey i have a question! Hiw does Alh2 combined with O makes it a good leaving group rather then simple O?

[@Leah4sci]

If you're referring to the negatively charged oxygen leaving the structure at 7:40 in the video, having that oxygen leave would make the central carbon unstable as it would become a carbocation with less than an octet of electrons. The AlH2-O is a good leaving group because the oxygen is highly electronegative and is capable of holding that negative charge when apart in solution. Aluminum alone would not be happy leaving as a hydride either, as I explained in the video around this time. For further questions, make sure to reach out to me through my website at Leah4sci.com/contact

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Amazing video mam ..... thanks

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[@krishnaswamy.v.k.d.6404]

Hii..im basically a biochemist..your video looks interesting but my concern is once the reaction is over how to remove those reducing agents from the reaction mixture

[@RajeshChauhan-vg8nm]

krishnaswamy. V.K.D. Well we use anhydrous diethyl ether to remove lialh4 because it is very reactive in water

[@Leah4sci]

I'm sorry, but I don't offer tutoring through KZbin comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join

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very good !

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Thank you 😇

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Perfect explanation . Can help me to make videos on Coordination Compound. And. Salt analysis. I fill difficulty in this chapters .Please help me . You are my path to achieve my goal.

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[@putulbehala4892]

4:32 Can we say that the mechanism is SNA/E?

[@Leah4sci]

It doesn't follow the traditional steps of an SNE mechanism. However, it is primarily considered a substitution reaction as the leaving group is ultimately replaced with a hydrogen atom.

[@nathanghazi7235]

what if at the end we washup using a Base instead of an acid. My textbook uses a base but doesn't show the actual mechanism. just the final product which is the same as a washup with an acid.

[@Leah4sci]

I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

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Good method

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Glad you like it!

[@sherazkhan2802]

A video from Khan academy says that the reduction of carboxylic acids and esters follow the same mechanism unlike what you said ...Also the balanced equation in our textbook has no mention of hydrogen as a by product . There is only a water molecule. Can anyone help with it ?

[@Leah4sci]

The goal of this video is to teach you the concept. If your resources don't match up focus on understanding why each step is as it is. This way you'll know which is correct regardless of what the resources tell you. Especially with biproducts not mentioned

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[@ArjunKumar-xv5vl]

At 7:06 why there is no positive charge on Alh3

[@Leah4sci]

The formal charge on aluminum in AlH3 is zero. Notice that AlH4 carried a negative charge. When its hydride left and attacked the acidic hydrogen, it then lost that negative charge and became neutral.

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@@Leah4sci thanks....

[@ArjunKumar-xv5vl]

@@Leah4sci is it true that you can't predict what will be the product of chemical reaction in chemistry....is it that you do experiment with the reactants , then comes data ..and then based on that data we write a story that satisfy that resultant...

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[@Leah4sci]

I'm sorry, but I don't offer tutoring through KZbin comments. For help with questions like this and more, I recommend you join the organic chemistry study hall. Details: leah4sci.com/join

[@sccm100]

My professor showed us this rxn but didn't explain the mechanism which is kind of dumb

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I hope the videos helped fill in the gaps

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[@wildmechtargus2679]

@7:30 what's the fate of O-AlH2

[@lanelasarsky981]

Agreed

[@Leah4sci]

Once kicked off it's left to wander in solution as a spectator ion

[@MrGangadharakv545]

what is the fate of AlH2O

[@Leah4sci]

At which point in the video?

[@MrGangadharakv545]

Leah4sci in mechanism of reduction of carboxylic acids to esters, OAlH2 is kicked out as a good leaving group in the second step. then what about the fate of OAlH2

[@jatingirdhar1277]

Nabh4 is not used for reduction of carboxylic acid

[@Leah4sci]

I agree. NaBH4 is a weak reducing agent and will only reduce ketones and aldehydes. Is there a point in the video where I say otherwise?

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