Logic Gates : XOR and XNOR gates Explained | XOR and XNOR gate as Inverter

[@ALLABOUTELECTRONICS]

Timestamps: 0:00 Introduction 0:35 XOR gate 6:26 XNOR gate 16:00 XOR and XNOR gate as Inverter

[@cyrusswen782]

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Since yesterday was waiting for next video and u came 🎉🎉

[@blacks_choice]

Yesterday is now 10 months ago

[@dkdhavk614]

The output of XNOR gate is always the complement of XOR gate. It's just that when the number of inputs are even then we can also express the output of XNOR gate in terms of that circle dot symbol using successive XNOR gates. When the number of inputs are odd then the output is either the complement of 3 input XOR gate or complement of A circle dot B circle dot C. When the number of inputs are odd then A circle plus B...C= A circle dot B...C When the number of inputs are even then A circle plus B...C= (A circle dot B...C)'

[@otaku4life549]

Your videos has helped me tremedeously in preparing for my final exams. Thank you so much for your efforts. It just saved my ass from failing this subject 😺

[@shankarmwaskle2622]

10:50 for n input xnor gate when even number of inputs are high then output is also high. But it is not following according to this generalized way. As if we consider 3 input XNOR GATE as follows: A(XNOR)B(XNOR)C = 0(XNOR)0(XNOR)1= 1 (i.e. odd number of one's) Similarly 0(XNOR)1(XNOR)0= 1(i.e. odd number of one's) And for even number of 1s it is giving me 0 as output . Considering above XNOR expression 0(XNOR)1(XNOR)1=0 ( i.e. even number of 1s) 1(XNOR)0(XNOR)1=0 ( i.e. even number of 1s) I have two conclusions for n input xnor gate: 1. For even inputs, output is logic high if number of logic high inputs are even. 2. For odd inputs, output is logic high if number of logic high inputs are odd.

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Eagerly waiting for more videos on logic gates ☺️☺️

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I love it thank you so much 😊

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You have old videos of more complicated topics in detail . I couldn't join college after 12 . If you can make a playlist of videos from start to end in a sequence or like a course it will be much more helpful . Currently I'm unable to follow . Please do this . I don't follow any curriculum but I want to be a good engineer one day.

[@ALLABOUTELECTRONICS]

There are various playlist for the different subjects ( basic electronics, digital electronics, analog electronics, network analysis etc ). Please check the playlist page of the channel. You will find it.

[@mpkdon]

Hope u doing well?

[@abhisiktaghosh6607]

Nicely explained ❤

[@nidhimavijyanti5537]

Thankyou sir I have understood this concept only cause of you 💫

[@user-nx9ec1sb9h]

If there are two 1’s and you add them, it’s gonna be 0? And not 1?

[@IrfanaShaik-bf7ff]

@@user-nx9ec1sb9h it's 1

[@mayurshah9131]

Excellent lesson 👍👍

[@pinkcrab]

Thank you so much for this lesson.

[@richaashtekar7381]

Plz do Boolean laws too 🙏🙏and demorgan laws

[@ALLABOUTELECTRONICS]

Yes, that will also be covered.

[@MannyaAtwal]

8:23 in XNOR 0 + 0 is 0 the only y =1 is of1+1 =1

[@lovely_ji]

Why are resistors in ohms and megaohms difficult to fabricate, why we use it in kiloohms generally?

[@ALLABOUTELECTRONICS]

They are also used. It depends on the application. In digital electronics, typically the external resistors used with the digital circuits are in kilo ohm. But sometimes the other resistors are also used. And apart from digital electronics, in many other applications the resistors in ohms and mega ohms are used quite often.

[@siddhaarths6713]

Sir what software are you using

[@OKBRO_kannda100]

Who are studying in 2024

[@krishk4870]

What you are trying to say by 3:24 "we can say that it's output is equal to ONE when odd number of inputs are high" ????? It's confusing because the way you identifying odds and evens. which one are odds and which one are even????

[@ALLABOUTELECTRONICS]

In the input, if there is odd numbers of 1s (1,3,5 etc) then output of the XOR gate will be 1. I hope, it will clear your doubt.

[@krishk4870]

@@ALLABOUTELECTRONICS TQ let see, by the way good work.

[@anupghimire4627]

@@ALLABOUTELECTRONICS But in X-NOR gate you say the function is high(1) when Even number of input is high(1) but why 0 0 0 =1 (high) , Although there is no any even high(1) output. How it becomes 1?

[@ALLABOUTELECTRONICS]

You also need to include the case when all the inputs are 0. That means when no inputs are high or when even numbers or inputs are high.

[@busisiweprincess631]

In simple terms, with regards to 3 inputs: if you have only one high(logic 1) as any input (obviously the other two inputs being low or logic 0s), You will have your output as 1. So for XOR, anywhere where there's one logic1 and two logic 0s the output will be 1.

[@sutopasarkar497]

Sir,when we take 2 inputs for X-OR gate, in the truth table why for A=1,B=1 we get Y=1? Isn't it Y=0? Sir, please answer me. My Digital Electronics 1 exam is knocking at the door😭

[@ALLABOUTELECTRONICS]

For two input XOR gate, when both inputs are 1, then output is 0. You can check the truth table at 1:19

[@sutopasarkar497]

​@@ALLABOUTELECTRONICS Thank you sir. Best of luck. Keep up the hardwork❤

[@poojashah6183]

Best🌈🦄👌🏻👍🏻

[@yasinhamad5982]

(A xor B)' = A' xnor B' ?? or it is A xnor B ? why didn't you put A' xnor B' xnor C' xnor D' here 14:58

[@ALLABOUTELECTRONICS]

(A( xor) B)’ = A ( xnor) B. You can also verify that.

[@yasinhamad5982]

@ALLABOUTELECTRONICS Thanks a lot.

[@iramkhan4798]

I couldn't understand gate structure

[@Ashish-ip7kx]

Thanks 👍🙏

[@madhumohan5605]

Super sir

[@Mohamed-xz1fq]

12:31 I think the line 1 z must be 0

[@ALLABOUTELECTRONICS]

Output will be 1 when odd number of inputs are 1. When all three inputs are 0, then output will be 0. Hence, z is 0 in the first case.

[@skwayes8629]

Sir how to simplify XOR Gate to XNOR? How to show A'B'(+) AB.

[@ALLABOUTELECTRONICS]

You mean, you want to covert the XOR gate to XNOR right !! If so, then you just need to add the NOT gate after the XOR gate.

[@AshwinR-w1z]

10:54 how 000 is even

[@ALLABOUTELECTRONICS]

The number of 1s are 0 (even) in 000. In short, when number of 1s are ( 0,2,4 etc) then output is 1.

[@manomana18]

Jab inputs 4 hoti tou inki simplification ni hori a xor b xor c xor d ans ana hai ni ara

[@ALLABOUTELECTRONICS]

In case of 4 variables, once you get A( xor) B, or xor of any two inputs then, consider them as one variable and try to simplify that.

[@TheresaVincent-l1j]

Shyanne Cliffs

[@Anbuninja840]

XNOR si bascially the same as AND

[@physics2773]

You are even number of inputs it is 0 or 1

[@PampostReturning]

Thank you.

[@MannyaAtwal]

888