Linearizing Graphs in Physics

This lesson describes the process of linearizing graphs. Linearizing is a method of recognizing one of three shapes of non-linear graphs, and creating new calculated data that will allow you to create a linear graph of the data. The slope and intercept, and therefore the equation, of this new linear graph is relatively easy to find, and it turns out that the equation of the linearized graph is also the equation of the original, non-linear graph.
You will need to learn the shapes, names, and proportional relationships of "side opening parabolas", "top opening parabolas", and "inverse" graphs.

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[@abbey9981]

This is exactly what I needed for my physics exam, I didn't understand anything my teacher said, but you were so helpful!!! THANK YOU

[@erikatejada4847]

I'm only watching this because of online classes

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[@heatherstein9576]

Thanks so much. I'm three years out of math and My professors question was like "is _ and _ porportional when checking clearance" but they are a mix of logarithmic, linear, and quadratic equations all similarly derived. This helped

[@ahmedaj2000]

THANK YOU SO MUCH!! This helped for tomorrow's quiz :)

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did ya pass?

[@delirious-gn7sm]

@@qabaselfurjani3973 i guess well never know

[@artsmith1347]

11:42 "that is the equation" ... of the curve fit. It might be interesting to note that it is close to T^2 = ((2*pI)^2) / g * L, which comes from the small-angle approximation in high school physics classes: T = 2 * pi * sqrt(L/g)

[@averyzeiler9686]

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[@selulekonkosi4419]

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[@user-xj4nq8wb3b]

Regarding the first example no change, the relation ship is that as x changes y stays the same. This would be true in the case of an object moving at constant velocity v vs t is a flat line.

[@anxiousmonk7]

Nice! You really cleared up my confusion. Thanks, man.

[@armleg]

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[@hazemammar6022]

you are the king of physics

[@hannaebrahim4145]

this was a really helpful video! really well explained.Thank you so much

[@sruthimajhi5610]

Thanks sir ...this helped me a lot🙏❣️

[@physicsanthem1108]

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[@lmaolpha_male]

what about a graph which looks like a sector, with the origin as centre

[@tarragonpowder8724]

My teacher did this for a single class (and his equations turn out to be wrong) and just the very next class he is taking a quiz for it, and has asked us to “figure it out online”. I’m a sophomore high schooler, things like this don’t happen in other classes.

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[@danielmichael4884]

Found this really helpful, thanks.

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Wow this was so helpful & easy to understand. Like no words. Tysm! Keep em coming pls!

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wow!!! i thought its not that easy ... but now got it clear... thankyou so much :)

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saranya M same man physics looks tough but nah

[@butterflytobe1013]

You don't know what you did for me I was not able t understand graphs ik it is silly but I was literally crying that. I can't understand this lil thing thankyou a billion tims

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THANK YOU I FINALLY UNDERSTAND

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Graphical Analysis. Very COOL!

[@Tman_M4]

How do you find slope if you can’t really see the rise over run

[@iamtufa]

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[@yoverale]

I think you are missing one case (y^2 α 1/x) isn’t that usual on physics results?

[@tomerekson_lphs7045]

I think you meant y α 1/x², which is an "inverse square" relationship, such as gravitational force vs distance, which obeys an inverse square law (F α 1/d²). There is a reason that is not listed--the "inverse square" graph shape looks like and inverse at first glance. So what you should do is to linearize it by graphing y vs 1/x, and the new graph becomes a top opening parabola. So now you see that y α 1/x². It's just following the linearization process twice. Otherwise, you would not know if an inverse shaped graph is 1/x or 1/x².

[@yoverale]

@@tomerekson_lphs7045 i see, thanks!

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[@user-fs3rm1yi7s]

It really helps me a lot. Thanks for your sharing. Have a good luck!

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Thank you so much !!! You saved me man☺️

[@noid919]

What about exponential decay? Is there a rule for this that fits?

[@Wells1680]

Thanks a lot

[@kanniram]

Very well explained. Thank you MrEScienceTheater.

[@neilcovington5679]

What does the slope represent? s^2 / meter?

[@crypticnomad]

what if we have a curve that only becomes linear with x*y?

[@LonePeakPhysics]

If I understand you correctly, on a y vs. x graph, you are asking about an equation such as 5=x*y? This would be an inverse relationship. Rearrange it to be y=5/x. To linearize this, you would graph y vs. 1/x. If this is not what you meant, please clarify and I'll try to answer.

[@Josh-bf9xq]

thank you so much :)

[@subhajit201]

what about the graph of voltage during charging of a capacitor. saturating exponential growth.

[@oliverkerr5620]

thank you!

[@vishavdeeprajput6678]

How will you graph y propotional to 1/x²

[@MegaPhysicsdude]

If you first try to linearize for y proportional to 1/x, you would then get a parabola, and you would recognize the need to linearize again to y vs. 1/x². Two steps.

[@nomekop777]

@@MegaPhysicsdude so graph 1/y vs x, and that gives you a parabola?

[@MegaPhysicsdude]

That is correct. For an inverse square relationship, if you graph for 1/x, you would then see a parabola.

[@thabisomasisi6426]

Thank you, that was very informative 😃😃

[@Andalfulfulde]

Cool, ❤❤❤ Please I have never heard of 5% rule 😢😢

[@aryang1232]

THANKS SO MUCH, iwas gonna die in atar physics

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Sup bro.

[@aryang1232]

Holy crap, 1 year ago, I passed hooray

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Your next buddy

[@dariuscsiky5505]

Thanks for the informative video!

[@pickleporkdork7358]

What if you did length squared instead?.. Would you still get a linear graph?

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Thank god I found this it was so helpful

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thank you so much!

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You are genius sir👍👍👍👍

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You solved all my problem !!! Thanks

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This is brilliant!, thank you so much!

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legend

[@natepelo]

How did you find the slope and y intercept?

[@davidquesadilla4041]

Great video!

[@alminananong4221]

Where did you get your y intercept?

[@iglo1209]

this is soooooo goooood thank you sooo much

[@sandra.j_bs_3292]

Nice class Tnq 😊😊

[@alminananong4221]

I don't understand isn't that time must be independent and length is the dependent?

[@bradfordtalbert4658]

No. You adjust the length of the pendulum and then time the period corresponding to that length.

[@Exposer2695]

thanks Man

[@sarangjams9721]

Not sure if you'll reply but my textbook says to square root my x values to form a linear graph whereas yours says to square it. Which one is correct or do you know why mine is different?

[@iamtufa]

I suppose you find the answer by now, mind sharing it because I have the same question

[@kurrimboccusruwaydah1036]

i am trying to do this for sme calculation i need for work.... the graph is not linear though I used this method... what could be wrong?

[@shiashia8463]

Are you sure you named the graph correctly? Is it already linearized?

[@nosratulkarimafifa6583]

Aww Thanks a bunch for your help 💞💞

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oml bless. u saved me

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Thank youuu so much.. ❤🇧🇩

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just subscribed :)

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Thanx sir

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thx m8

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ty

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This is the video I was finding .........

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dosent work 2022

[@leetabear]

How did you find the slope and the y-intercept?

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that high pitch screeching AHH

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I find it comfortable lmao

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periodt.

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Thank you for this helping video

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Bernard star calculate

[@emmarolon1778]

when you thought he was making position vs time graphs the entire time and now on top of having wasted your time, you are more confused than ever ( _:

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Nice but abit lost

[@lexihedstrom]

I have a quiz in an hour

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Expain it clerly with more briefly i thought many of viewers not got this

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[@blazingfest5885]

Man I hate physics

[@aryang1232]

THANKS SO MUCH, iwas gonna die in atar physics