LORENTZ TRANSFORMATION EQUATIONS & IT'S DERIVATION || LORENTZ TRANSFORMATION || WITH EXAM NOTES ||

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Very brilliant sir Sir derivation is long But consept clear Thankyou so much sir 👌👌👌

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Please 1 vedio for Michelson Morley experiments and physical significance of result today

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[@seetharamasvara7254]

Mu-meson paradox A case of length contraction is discussed in respect of mu-meson surging towards Earth after its origin in upper atmosphere. It is argued that the space between Meson & Earth appears shrunken from the perspective of meson. This is perplexing. Is it the (hypothetical) measuring system in mu-meson is elongated ? This argument is some what like Geocentric Model of Universe where whole of the universe was considered revolving around Earth( It appears so to us on earth ). I have developed a model based on a ‘Hypothetical Experiment’ conducted in a lab on mu-Meson generated in the upper atmosphere & moving towards earth. The Meson is moving towards Earth at .998c OR (299.4 mtrs/ micro-second w.r. to earth) Consider an Electro-Magnetic Pulse Genrator & Receiver (G-R) inside a lab on Meson sending pulse in the direction of motion. Let there be a Reflector ( R ) at 300 mtrs in Meson Scale ( 18.9642 mtrs on Absolute Scale or Earth’s Scale for all practical purposes) e = v/c = 299.4/300 = 0.998 γ = √ (1-v2/c2) = √ ( 1- 0.9982 ) = 0.06321 Shrinkage Factor, S = 1 / γ = 15.8193. i.e., 1 E-mtr = 15.8193 M-mtr, 1 E- mi-sec = 1/ 15.8193 M-mi-sec ( where E stands for measurement on Earths scale & M stands for measurements on Meson scale.) Dist GR to R = 300 M-mtr = 18.9642 E-mtr. Speed of E-M pulse w.r.t G-R is 0.6 mtrs on earth’s scale. Therefore to traverse 18.964 E-mtr time reqd = 18.9642 / 0.6 = 31.607 E. mi-sec = 1.998 M. mi-sec Reverse journey time for Photon = 18.9642 / (300+299.4) = 0.03164 E. mi-sec = 0.002 M. mi-sec. Total Journey time = 31.607+ 0.03164 = 31.63864 E. mi-sec = 1.998 + .002 = 2 M.mi-sec. Bidirectional Speed of Light w.r.t Meson = 600 / 2 = 300 mtr / mi-sec. Forward Speed of Light w.r.t Meson = 300 / 1.998 = 150.15 M-mtr / M. mi-sec. Return Speed of Light w.r.t Meson = 300 / .002 = 150000 M-mtr / M. mi-sec. Speed of Meson as measured on Earth with earth’s scale & clock ( which is at negligible speed ) = 299.4 mtrs / mi-sec Speed of Light w.r.t Meson’s scale & clock = 299.4 * 15.8193 * 15.8193 = 74924.9256 mtrs/ mi-sec ---- (1) Distance to Earth in Meson’s measuring scale = 9500 * 15.8193 = 150283 mtrs ---- (2) Dividing (2) by (1) we get about 2.0058 mi-sec Therefore from the above result it is evident that the Meson generated at upper atmosphere finds earth at about 150000 mtrs in its scale & it surges towards Earth at about 75000 mtrs/mi-sec in its measuring scale & clock to reach earth in 2 mi-sec on its clock. From above approach it is clear that Light propogates with a CONSTANT RATE OF DISPLACEMENT form its origin unaffected by the motion of the source just like a wave in a Pond generated by a man sitting in a moving boat. Its bidirectional speed is 300 mtrs/sec to any observer in his scale & time but unidirectional speed is variable. The speed of Light is < 300 mtrs/mi-sec to an observer moving in the direction of light with minimum of 150 mtrs/mi-sec. to observers with speed greater than mu-meson. Speed of Light approaches infinity to an observer approaching the light with speeds comparable to mu-meson speed. I welcome opinion of viewers about correctness or otherwise of my analysis. [e-mail]

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Can anyone explain why we quate the coefficient to zero in the equation

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