Magnetic Force on Semicircular Current Carrying Wire

[@dalerichmondnaviza9449]

Small addition to this: dL could also be evaluated by using the arc length of a circle which is equal to (theta*radius) so dL = d(theta)*R

[@monikakalecinska742]

You've helped me understand so much about electromagnetics! Thank you so much, I'm not as scared for my exam I have in two days in the subject :)

[@minevural6029]

Great ! This topic cannot be explained better. It helped me very much. Thanks.

[@nontuthuko.lutseke.1113]

Thnk you soooo much, my lecturer really confused me when we were doing this in class, this is really helpful ❤🙏

[@yerthor]

by far the best explanation i've seen on this topic

[@JoseYtlello840]

thnks a lot you are a good teacher

[@englishwithravi4590]

Thank you so much sir.im from sri lanka❤️

[@OfficialVasuRastogi]

Explained well thanks 😊

[@thabosithole6211]

You’re amazing

[@eriedului]

Amazing Video

[@Karim-ud9kl]

Perfect explanation, Thanks!!

[@AKLECTURES]

Leyenda Geek you're welcome! :)

[@wit8438]

what's the force if arc subtends angle theta

[@vadila123]

great video, great explanation!

[@mariajonsun3280]

Thanks. Helped me a lot.

[@animationphysics8770]

Sir if we rotate this diagram then what angle we can take like 0 pi/2 is it possible

[@drujjawalrathore]

Superb , Thanks !!!!:)

[@zessifcb]

great explanation , thank you .

[@wit8438]

should we integrate 0 to theta or there is another method for it

[@adonis1168]

You. Are. Amazing bud

[@akilanilmalgoda5453]

Why is it integral of dFsin(θ) but not dF cos( θ)??

[@akilanilmalgoda5453]

Still, the answer is the same :|

[@joshua7015]

Because you want the component of Current (I) that is perpendicular to the Magnetic Field (B) in order to determine the Force. For that component we must use sin theta. Using cos theta will give us the parallel component See the right hand rule. Current, Magnetic Field and Force are all at right angles to each other

[@manoneetsikhwal7424]

Just call me Tsuyu it won't give us parallel component

[@joshua7015]

@@manoneetsikhwal7424 How does it not? Cos is for parallel component whereas sin is for perpendicular component.

[@MrRitik-qj8tr]

@@@joshua7015" angle between dF and vertical is theta" so doing dF cos theta gives us component of Force in vertical direction while doing dF cos theta will give us horizontal component. "What you are saying would have been correct if theta was the angle between dF and horizontal."🤗

[@fatmanur5409]

What if it is full circle? Net force gonna be 0, right?

[@refkaalkhasawneh7644]

Ur a genius thank u

[@farahrefaie6993]

my man

[@banajadandasena4142]

Torque calculation?

[@MagicByEli]

I don't get why the x components cancel out

[@suryanshshishodia682]

Perfect.

[@zivojinpecin1372]

Fucken killed it, keep it up man

[@AKLECTURES]

Zivojin Pecin thanks! :-) will do.

[@roshanmujeeb]

thanks man

[@ashwinnair2325]

Thanx sir

[@israeljo3616]

Why dFy = dF sin theta...and not dF cos theta..

[@joshua7015]

Because you want the component of Current (I) that is perpendicular to the Magnetic Field (B) in order to determine the Force. For that component we must use sin theta. Using cos theta will give us the parallel component See the right hand rule. Current, Magnetic Field and Force are all at right angles to each other

[@allisonscanlan4144]

What if it's a quarter circle

[@NiggaSlayer666]

change the boundaries to 0 >> Pi/2

[@gravityplayer5237]

While it did help me understand, you teach it so aggresively... 🤨

[@adode97]

I Really want to understand but you keep on yelling, and that really annoys me. Can you please next time try to be calmer as the mic quality isnt the best.

[@adiscapestherune2657]

I think he tries to make it intense.