Make my trip Frontend interview experience | React and Javascript

Hey everyone, In this video I have shared my frontend interview experience with Mmt.
This video covers the following topics -
1. How I got the call
2. How many rounds were there ?
3. Tips on how to answer questions.
4. All the Questions along with answers covered in detail.
5. Must watch React coding question.
If this video was helpful, give it a thumbs up and subscribe to my channel for more such videos. 🔔
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Cheers,
Akash Ingole
Would love to Stay Connected with you ❤️
Instagram - / akashingoleofficial
#frontendinterview #reactjsinterview #reactjs #javascript

[@akashingole]

Don't forget to subscribe 🙌 Thank you for watching... Have a great day 😇 -AI

[@phaddu7737]

How many years of experience was this interview for, as I'm preparing for one it would be helpful to know.

[@tanyagupta264]

In the react timer question, you should not be removing dependency array. That means with every second, you are creating new interval and clearing the old one. Which actually loses the purpose of having an interval in first place (it is behaving more like a setTimeout). Instead try setCount((count) => count + 1) inside your interval method and add back empty dependency array so that your set method picks up the latest count value while incrementing

[@manishkumarprasad1911]

You are right

[@ankitmehrotra8519]

This will work - setCount(c => c+1), with previous value implement you can keep empty dependency array.

[@MrK-nb7xr]

Really .. your video greatly helps man, hats off ... Can you make video about yourself , your current company , Past experience and how much data structures needed to crack the frontend interview .... Keep on attending the interview and share your experiences ..

[@imac_]

Extremely easy solution for moving 0's at last ---> let arr = [8, 10, 5, 0, 9, 4, 0, 6, 3]; let last_index = arr.length; for (let i of arr) { if (i == 0) { arr.splice(last_index, 0, i); arr.splice(arr.indexOf(i), 1); } } console.log(arr);

[@VipulDessaiBadGAMERbaD]

This is good but needs extra memory

[@imac_]

@@VipulDessaiBadGAMERbaD Hi Brother, I've updated my answer, I have corrected the mistake and now its an Efficient in terms of both Time and Space Complexity. Thanks for pointing the mistake.

[@VipulDessaiBadGAMERbaD]

splice has its own time complexity of O(n) and on top of that if you use again arr.indexOf that also has O(n), so this might end up consuming more time, the solution is pretty simple using two pointers

[@thebattinson1278]

More egelant and simpler : function moveZero(arr) { return [...arr.filter(e => e>0) , ...arr.filter(e => e===0) ] }

[@thebattinson1278]

Another solution for the first one : function moveZero1(arr) { return [...arr.filter(e => e>0) , ...arr.filter(e => e===0) ] }

[@abhishekbanda97]

function addEle(arr,num){ let a = [] arr.reduce((prev,curr) => { a.push(prev+curr) return curr; }) if(a.includes(num)){ return true }else{ return false } } console.log(addEle([2,1,3,6],4)) this one also working

[@rounak308]

need more video like these in js.interview question analysis etc

[@sankatsiddhartha2649]

Answer to the question move zeros at end question No Need for dual foreach loop: const arr = [1, 2, 3, 0, 5, 6, 0, 10, 12]; function moveZerosAtLastPos(arr) { const nonZeroItems = []; const zeroItems = []; [].forEach.call(arr, (item) => { item !== 0 ? nonZeroItems.push(item) : zeroItems.push(item); }); return nonZeroItems.concat(zeroItems); } const result = moveZerosAtLastPos(arr); console.log(result); 😆😆

[@soumyaranjanpanda7532]

This was really helpful buddy !! Thank you 🙂

[@ankushladani496]

Thank you sir Continue this series...

[@devashishpujari]

Your video content is really helpful ❤️. Can't we use JS functions? like.. filter() method to get an array of non zero elements and then append 0s till the arr.length 🤔

[@digvijaysingh9028]

No Because using inbuilt functions are not allowed mostly Secondly Filter method behind the scene runs loop and it will be O(n)

[@rahulkashyap-jp1vt]

very helpful video, thanks again

[@yoguy515]

all the zeros to the end console.log( array.sort().reverse())

[@VipulDessaiBadGAMERbaD]

Any sorting algorithm is O(n Log n), his solution in O(n)

[@amansaxena4446]

Thanks akash for sharing your experience.

[@akashingole]

Glad to hear that 🙌🏻

[@akj3344]

What were the experience requirements for this job? And how much experience do you have? Would help us to know

[@abhijeetkaushal1343]

Bhai were you selected? CTC they were offering? I have different approaches but yours also works so good

[@rahulkrishnanr758]

bro is this sde1 or sde2 what was the experience ?

[@aniketsriwastva6345]

Great explanation

[@saitejagatadi9711]

Thank you so much 😊

[@karann3335]

bro you are genius

[@sohailbasha7781]

U have attest mention the years of experience so tahg we get an idea

[@akashingole]

3+

[@Ravi_Goyal]

Can we use python to solve coding questions in frontend interview?

[@sahukarisantosh4655]

the 2nd question asked for me also

[@nishantsharma7267]

Nice 👍

[@bhagya12335]

Can I know how many years of experience you have in front end

[@juhibhardwaj6275]

Hii Akash Ingole, Could you please. Tell me how many rounds were there...?? Can you tell me how many rounds on DS or coding and how many rounds on React Js

[@akashingole]

Total 3 rounds including DS and React

[@HighEntertainer]

3+ year for people wondering

[@SCRIPTSAG]

What package you got it

[@shubhammehra8300]

experience requirements??

[@sahukarisantosh4655]

where i get that dsa questions

[@VipulDessaiBadGAMERbaD]

Leet code

[@coading1216]

Bhai how do you apply for this companys?

[@akashingole]

Got the call from HR

[@virajlohate]

@@akashingole how to get call from HR?

[@RohitSinghofficial]

Bhai kitne interviews dega :D :p

[@RohitSinghofficial]

just kidding.. keep doing it..

[@Viral_Shorts_v]

here to shortes way to shift zeros- const funShifZero =(arr)=>{ const tempArr1=[] const tempArr0=[] for(let i = 0; i

[@aigaming019]

Very useful 😊